def test_inversion(self):
x = ImmutableListMultiDict.of({1: [2, 2, 3, 6], 4: [5, 6]})
reference_set_based = ImmutableSetMultiDict.of(
{2: [1], 3: [1], 5: [4], 6: [1, 4]}
)
# 2->1 appears twice because 1->2 appears twice in the source
reference_list_based = ImmutableListMultiDict.of(
{2: [1, 1], 3: [1], 5: [4], 6: [1, 4]}
)
self.assertEqual(reference_set_based, x.invert_to_set_multidict())
self.assertEqual(reference_list_based, x.invert_to_list_multidict())
def test_immutable_keys(self):
x = ImmutableListMultiDict.of({1: [2, 2, 3], 4: [5, 6]})
# TypeError: '_ImmutableDictBackedImmutableListMultiDict' object does not support item
# assignment
with self.assertRaises(TypeError):
# noinspection PyUnresolvedReferences
x[20] = [1, 2]
def test_immutable_values(self):
x = ImmutableListMultiDict.of({1: [2, 2, 3], 4: [5, 6]})
# AttributeError: '_TupleBackedImmutableList' object has no attribute 'append'
with self.assertRaises(AttributeError):
# noinspection PyUnresolvedReferences
x[1].append(7)
# TypeError: '_TupleBackedImmutableList' object does not support item assignment
with self.assertRaises(TypeError):
# noinspection PyUnresolvedReferences
x[1][0] = 7
def test_inversion(self):
x = ImmutableSetMultiDict.of({1: [2, 2, 3, 6], 4: [5, 6]})
# when you start from a set multidict, your inverses as a list
# and set multidict both contain the same items, since there
# are no duplicate mappings in the source
reference_set_based = ImmutableSetMultiDict.of(
{2: [1], 3: [1], 5: [4], 6: [1, 4]}
)
reference_list_based = ImmutableListMultiDict.of(
{2: [1], 3: [1], 5: [4], 6: [1, 4]}
)
self.assertEqual(reference_set_based, x.invert_to_set_multidict())
self.assertEqual(reference_list_based, x.invert_to_list_multidict())
def test_len(self):
x = ImmutableListMultiDict.of({1: [2, 2, 3], 4: [5, 6]})
# note 5, not 4, because the list version maintains distinctness
self.assertEqual(5, len(x))
# len's implementation often does caching, so test it works twice
self.assertEqual(5, len(x))
def test_filter_keys(self):
orig = ImmutableListMultiDict.of({1: [1], 2: [2], 3: [3], 4: [4]})
evens = orig.filter_keys(lambda x: x % 2 == 0)
self.assertEqual(ImmutableListMultiDict.of({2: [2], 4: [4]}), evens)
all_keys = orig.filter_keys(lambda x: x)
self.assertEqual(orig, all_keys)
def test_modified_copy_builder(self):
orig = ImmutableListMultiDict.of({1: [2, 2, 3], 4: [5, 6]})
updated = orig.modified_copy_builder().put(4, 5).build()
expected = ImmutableListMultiDict.of({1: [2, 2, 3], 4: [5, 6, 5]})
self.assertEqual(expected, updated)
def test_unmodified_copy_builder(self):
orig = ImmutableListMultiDict.of({1: [2, 2, 3], 4: [5, 6]})
self.assertIs(orig, orig.modified_copy_builder().build())
def test_slots(self):
x = ImmutableListMultiDict.of({1: [2, 2, 3], 4: [5, 6]})
self.assertFalse(hasattr(x, "__dict__"))
def test_isinstance(self):
x = ImmutableListMultiDict.of({1: [2, 2, 3], 4: [5, 6]})
self.assertFalse(isinstance(x, Mapping))
self.assertTrue(isinstance(x.as_dict(), Mapping))
def test_str(self):
self.assertEqual("{1: (2, 2, 3)}", str(ImmutableListMultiDict.of({1: [2, 2, 3]})))
def test_of(self):
x = ImmutableListMultiDict.of({1: [2, 2, 3], 4: [5, 6]})
self.assertEqual([2, 2, 3], list(x[1]))
y = immutablelistmultidict([(1, 2), (1, 2), (1, 3), (4, 5), (4, 6)])
self.assertEqual([2, 2, 3], list(y[1]))
def test_empty_singleton(self):
empty1 = immutablelistmultidict()
empty2 = immutablelistmultidict()
self.assertIs(empty1, empty2)
empty4 = ImmutableListMultiDict.of(dict())
self.assertIs(empty1, empty4)
def test_empty(self):
empty = immutablelistmultidict()
self.assertEqual(0, len(empty))
empty2 = ImmutableListMultiDict.of(dict())
self.assertEqual(0, len(empty2))
self.assertEqual(empty, empty2)