Python to_previous_menu 예제들

예제 #1

파일: interface_maint.py 프로젝트: chaps/time-management

def map_choice_to_function(choice, facade):
    if choice == "0":
        to_previous_menu(facade)
    elif choice == "1":
        delete_history(facade)
    elif choice == "2":
        quit_program(facade)
    else:
        print("Choice not recognized.")

예제 #2

파일: interface_maintenance.py 프로젝트: vinosamari/time-management

 def map_choice_to_function(self, choice):
     if choice == "0":
         interface_common.to_previous_menu()
     elif choice == "1":
         self.delete_history()
     elif choice == "2":
         interface_common.quit_program(self.notes_facade)
     else:
         print("Choice not recognized.")

예제 #3

파일: interface_lytics.py 프로젝트: chaps/time-management

def map_choice_to_function(choice, facade):
    if choice == "0":
        to_previous_menu(facade)
    elif choice == "1":
        clear_screen()
        pass
    elif choice == "2":
        quit_program(facade)
    else:
        print("Choice not recognized.")

예제 #4

파일: interface_analytics.py 프로젝트: vinosamari/time-management

 def map_choice_to_function(self, choice):
     if choice == "0":
         interface_common.to_previous_menu()
     elif choice == "1":
         interface_common.clear_screen()
         pass
     elif choice == "2":
         interface_common.quit_program(self.notes_facade)
     else:
         print("Choice not recognized.")

예제 #5

파일: interface_tm.py 프로젝트: chaps/time-management

def map_choice_to_function(choice, facade):
    if choice == "0":
        to_previous_menu(facade)
    elif choice == "1":
        make_a_note(facade)
    elif choice == "2":
        set_a_task(facade)
    elif choice == "3":
        print_contents(facade)
    elif choice == "4":
        complete_task(facade)
    elif choice == "5":
        print_overdue_tasks(facade)
    elif choice == "6":
        print_scrum_notes(facade)
    elif choice == "7":
        quit_program(facade)
    else:
        print("Choice not recognized.")