예제 #1
0
def checkRings(cycles):
    """This fixes a bug in figuras algorithm.  Sometimes when
    traversing through fused rings embedded in a larger ring
    two paths are returned when only one should have been
    This removes (most) of these cases"""
    # XXX I've encountered this bug before in figueras algorithm
    #     I really need to investigate if further and see
    #     if CDK has the same issues.
    res = []

    set = kjSet()
    sameSizes = {}
    i = 0
    for atoms, bonds in cycles:
        size = len(bonds)
        sameSizes[size] = sameSizes.get(size, []) + [(atoms, bonds)]

    keys = sameSizes.keys()
    keys.sort()
    last = kjSet()
    for size in keys:
        cycles = sameSizes[size]
        nextCycles = kjSet()

        i = 0
        if len(cycles) == 1:
            res.append(cycles[0])
            print "adding ring of size", cycles[0][1]
            continue

        dontAdd = {}
        for atoms1, bonds1 in cycles:
            s1 = kjSet(bonds1)
            j = i + 1
            for atom2, bonds2 in cycles[j:]:
                s2 = kjSet(bonds2)
                check = (s1-s2) + (s2-s1)
                l = len(check)

                if not (l and len(last & check) == l):
                    print "adding ring of size", len(bonds1)
                    res.append((atoms1, bonds1))
                else:
                    if i not in dontAdd:
                        dontAdd[j] = 1
                        res.append((atoms1, bonds1))
                        print "adding ring of size", len(bonds1)
                        print "dropping ring of size", len(bonds2)
        
            i += 1
        
                    
            nextCycles += s1
        last += nextCycles
    return res
예제 #2
0
def checkRings(cycles):
    """This fixes a bug in figuras algorithm.  Sometimes when
    traversing through fused rings embedded in a larger ring
    two paths are returned when only one should have been
    This removes (most) of these cases"""
    # XXX I've encountered this bug before in figueras algorithm
    #     I really need to investigate if further and see
    #     if CDK has the same issues.
    res = []

    set = kjSet()
    sameSizes = {}
    i = 0
    for atoms, bonds in cycles:
        size = len(bonds)
        sameSizes[size] = sameSizes.get(size, []) + [(atoms, bonds)]

    keys = sameSizes.keys()
    keys.sort()
    last = kjSet()
    for size in keys:
        cycles = sameSizes[size]
        nextCycles = kjSet()

        i = 0
        if len(cycles) == 1:
            res.append(cycles[0])
            print "adding ring of size", cycles[0][1]
            continue

        dontAdd = {}
        for atoms1, bonds1 in cycles:
            s1 = kjSet(bonds1)
            j = i + 1
            for atom2, bonds2 in cycles[j:]:
                s2 = kjSet(bonds2)
                check = (s1 - s2) + (s2 - s1)
                l = len(check)

                if not (l and len(last & check) == l):
                    print "adding ring of size", len(bonds1)
                    res.append((atoms1, bonds1))
                else:
                    if i not in dontAdd:
                        dontAdd[j] = 1
                        res.append((atoms1, bonds1))
                        print "adding ring of size", len(bonds1)
                        print "dropping ring of size", len(bonds2)

            i += 1

            nextCycles += s1
        last += nextCycles
    return res
예제 #3
0
파일: kjfactor.py 프로젝트: jpatsenker/cra
def factor(G):
    from kjbuckets import kjSet, kjGraph
    allnodes = kjSet(G.keys()) + kjSet(G.values())
    allnodelist = allnodes.items()
    allnodemap = map(None, allnodelist, range(len(allnodelist)))
    nodetoindex = kjGraph(allnodemap)
    pairs = G.items()
    left = pairs[:]
    right = left[:]
    for i in xrange(len(left)):
        (l, r) = pairs[i]
        left[i], right[i] = nodetoindex[l], nodetoindex[r]
    return (left, right), allnodelist
예제 #4
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def factor(G):
    from kjbuckets import kjSet, kjGraph
    allnodes = kjSet(G.keys()) + kjSet(G.values())
    allnodelist = allnodes.items()
    allnodemap = map(None, allnodelist, range(len(allnodelist)))
    nodetoindex = kjGraph(allnodemap)
    pairs = G.items()
    left = pairs[:]
    right = left[:]
    for i in xrange(len(left)):
        (l, r) = pairs[i]
        left[i], right[i] = nodetoindex[l], nodetoindex[r]
    return (left, right), allnodelist
예제 #5
0
파일: tsort.py 프로젝트: jpatsenker/cra
def tsort(list_of_pairs):
    result = []
    Graph = kjGraph(list_of_pairs)
    notsource = (kjSet(Graph.values()) - kjSet(Graph.keys())).items()
    while Graph:
       sources = kjSet(Graph.keys())
       dests = kjSet(Graph.values())
       startingpoints = sources - dests
       if not startingpoints:
          raise LOOPERROR, "loop detected in Graph"
       for node in startingpoints.items():
           result.append(node)
           del Graph[node]
    return result + notsource
예제 #6
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def tsort(list_of_pairs):
    result = []
    Graph = kjGraph(list_of_pairs)
    notsource = (kjSet(Graph.values()) - kjSet(Graph.keys())).items()
    while Graph:
        sources = kjSet(Graph.keys())
        dests = kjSet(Graph.values())
        startingpoints = sources - dests
        if not startingpoints:
            raise LOOPERROR, "loop detected in Graph"
        for node in startingpoints.items():
            result.append(node)
            del Graph[node]
    return result + notsource
예제 #7
0
파일: tsort2.py 프로젝트: dmf24/cra
def tsort(pairs):
    from kjbuckets import kjGraph, kjSet
    G = kjGraph(pairs)
    Gt = ~G  # transpose
    sources = kjSet(G.keys())
    dests = kjSet(G.values())
    all = (sources + dests).items()
    total = len(all)
    endpoints = dests - sources
    for i in xrange(total - 1, -1, -1):
        #print i, endpoints
        if not endpoints:
            raise LOOPERROR, "loop detected"
        choice = endpoints.choose_key()
        for n in Gt.neighbors(choice):
            G.delete_arc(n, choice)
            if not G.has_key(n):
                endpoints[n] = n
        del endpoints[choice]
        all[i] = choice
    return all
예제 #8
0
파일: kjmincut.py 프로젝트: hstanev/dbcook
    def calc_mincut( me, g, uncutables =(), exclude_selfrefs =True, count_multiples =True):
        edge_cost = me.edge_cost = {}
        for edge in g:
            if edge in uncutables: cost = len(g)
            else:
                cost = count_multiples and g.count(edge) or 1
            edge_cost[ edge] = cost

        g = kj.kjGraph( g)

        #prngraph( g & ~g.tclosure() ) #- core-cycle

        if exclude_selfrefs:
    #        self_refs = kj.kjSet(g).ident() & g
    #        g = g - self_refs
             g = g - kj.kjSet(g).ident()

        me._find( g)
예제 #9
0
파일: kjmincut.py 프로젝트: hstanev/dbcook
    def calc_mincut(me,
                    g,
                    uncutables=(),
                    exclude_selfrefs=True,
                    count_multiples=True):
        edge_cost = me.edge_cost = {}
        for edge in g:
            if edge in uncutables: cost = len(g)
            else:
                cost = count_multiples and g.count(edge) or 1
            edge_cost[edge] = cost

        g = kj.kjGraph(g)

        #prngraph( g & ~g.tclosure() ) #- core-cycle

        if exclude_selfrefs:
            #        self_refs = kj.kjSet(g).ident() & g
            #        g = g - self_refs
            g = g - kj.kjSet(g).ident()

        me._find(g)