예제 #1
0
 def __mul__(s, t):
     cls, new, (prec, rounding) = s._ctxdata
     if not hasattr(t, '_mpc_'):
         if isinstance(t, int_types):
             v = new(cls)
             v._mpc_ = mpc_mul_int(s._mpc_, t, prec, rounding)
             return v
         t = s.mpc_convert_lhs(t)
         if t is NotImplemented:
             return t
         if hasattr(t, '_mpf_'):
             v = new(cls)
             v._mpc_ = mpc_mul_mpf(s._mpc_, t._mpf_, prec, rounding)
             return v
         t = s.mpc_convert_lhs(t)
     v = new(cls)
     v._mpc_ = mpc_mul(s._mpc_, t._mpc_, prec, rounding)
     return v
예제 #2
0
 def __mul__(s, t):
     cls, new, (prec, rounding) = s._ctxdata
     if not hasattr(t, '_mpc_'):
         if isinstance(t, int_types):
             v = new(cls)
             v._mpc_ = mpc_mul_int(s._mpc_, t, prec, rounding)
             return v
         t = s.mpc_convert_lhs(t)
         if t is NotImplemented:
             return t
         if hasattr(t, '_mpf_'):
             v = new(cls)
             v._mpc_ = mpc_mul_mpf(s._mpc_, t._mpf_, prec, rounding)
             return v
         t = s.mpc_convert_lhs(t)
     v = new(cls)
     v._mpc_ = mpc_mul(s._mpc_, t._mpc_, prec, rounding)
     return v
예제 #3
0
    def fmul(ctx, x, y, **kwargs):
        """
        Multiplies the numbers *x* and *y*, giving a floating-point result,
        optionally using a custom precision and rounding mode.

        See the documentation of :func:`fadd` for a detailed description
        of how to specify precision and rounding.

        **Examples**

        The result is an mpmath number::

            >>> from mpmath import *
            >>> mp.dps = 15; mp.pretty = False
            >>> fmul(2, 5.0)
            mpf('10.0')
            >>> fmul(0.5j, 0.5)
            mpc(real='0.0', imag='0.25')

        Avoiding roundoff::

            >>> x, y = 10**10+1, 10**15+1
            >>> print x*y
            10000000001000010000000001
            >>> print mpf(x) * mpf(y)
            1.0000000001e+25
            >>> print int(mpf(x) * mpf(y))
            10000000001000011026399232
            >>> print int(fmul(x, y))
            10000000001000011026399232
            >>> print int(fmul(x, y, dps=25))
            10000000001000010000000001
            >>> print int(fmul(x, y, exact=True))
            10000000001000010000000001

        Exact multiplication with complex numbers can be inefficient and may
        be impossible to perform with large magnitude differences between
        real and imaginary parts::

            >>> x = 1+2j
            >>> y = mpc(2, '1e-100000000000000000000')
            >>> fmul(x, y)
            mpc(real='2.0', imag='4.0')
            >>> fmul(x, y, rounding='u')
            mpc(real='2.0', imag='4.0000000000000009')
            >>> fmul(x, y, exact=True)
            Traceback (most recent call last):
              ...
            OverflowError: the exact result does not fit in memory

        """
        prec, rounding = ctx._parse_prec(kwargs)
        x = ctx.convert(x)
        y = ctx.convert(y)
        try:
            if hasattr(x, '_mpf_'):
                if hasattr(y, '_mpf_'):
                    return ctx.make_mpf(mpf_mul(x._mpf_, y._mpf_, prec, rounding))
                if hasattr(y, '_mpc_'):
                    return ctx.make_mpc(mpc_mul_mpf(y._mpc_, x._mpf_, prec, rounding))
            if hasattr(x, '_mpc_'):
                if hasattr(y, '_mpf_'):
                    return ctx.make_mpc(mpc_mul_mpf(x._mpc_, y._mpf_, prec, rounding))
                if hasattr(y, '_mpc_'):
                    return ctx.make_mpc(mpc_mul(x._mpc_, y._mpc_, prec, rounding))
        except (ValueError, OverflowError):
            raise OverflowError(ctx._exact_overflow_msg)
        raise ValueError("Arguments need to be mpf or mpc compatible numbers")
예제 #4
0
    def fmul(ctx, x, y, **kwargs):
        """
        Multiplies the numbers *x* and *y*, giving a floating-point result,
        optionally using a custom precision and rounding mode.

        See the documentation of :func:`~mpmath.fadd` for a detailed description
        of how to specify precision and rounding.

        **Examples**

        The result is an mpmath number::

            >>> from mpmath import *
            >>> mp.dps = 15; mp.pretty = False
            >>> fmul(2, 5.0)
            mpf('10.0')
            >>> fmul(0.5j, 0.5)
            mpc(real='0.0', imag='0.25')

        Avoiding roundoff::

            >>> x, y = 10**10+1, 10**15+1
            >>> print x*y
            10000000001000010000000001
            >>> print mpf(x) * mpf(y)
            1.0000000001e+25
            >>> print int(mpf(x) * mpf(y))
            10000000001000011026399232
            >>> print int(fmul(x, y))
            10000000001000011026399232
            >>> print int(fmul(x, y, dps=25))
            10000000001000010000000001
            >>> print int(fmul(x, y, exact=True))
            10000000001000010000000001

        Exact multiplication with complex numbers can be inefficient and may
        be impossible to perform with large magnitude differences between
        real and imaginary parts::

            >>> x = 1+2j
            >>> y = mpc(2, '1e-100000000000000000000')
            >>> fmul(x, y)
            mpc(real='2.0', imag='4.0')
            >>> fmul(x, y, rounding='u')
            mpc(real='2.0', imag='4.0000000000000009')
            >>> fmul(x, y, exact=True)
            Traceback (most recent call last):
              ...
            OverflowError: the exact result does not fit in memory

        """
        prec, rounding = ctx._parse_prec(kwargs)
        x = ctx.convert(x)
        y = ctx.convert(y)
        try:
            if hasattr(x, '_mpf_'):
                if hasattr(y, '_mpf_'):
                    return ctx.make_mpf(mpf_mul(x._mpf_, y._mpf_, prec, rounding))
                if hasattr(y, '_mpc_'):
                    return ctx.make_mpc(mpc_mul_mpf(y._mpc_, x._mpf_, prec, rounding))
            if hasattr(x, '_mpc_'):
                if hasattr(y, '_mpf_'):
                    return ctx.make_mpc(mpc_mul_mpf(x._mpc_, y._mpf_, prec, rounding))
                if hasattr(y, '_mpc_'):
                    return ctx.make_mpc(mpc_mul(x._mpc_, y._mpc_, prec, rounding))
        except (ValueError, OverflowError):
            raise OverflowError(ctx._exact_overflow_msg)
        raise ValueError("Arguments need to be mpf or mpc compatible numbers")