d = np.concatenate(d)
else:
d = d[0]
if latetime:
print("cutting out times greater than {}".format(latetime))
d = d[d["t"] <= latetime]
# calculating quantities
if num_of_coords == 2:
# notice this only does x-y, y-z, and inverts the first.
x = "x" if opts["--X"] else "y"
y = "y" if opts["--Y"] else "z"
coords = [x, y]
if opts["--reverse"]:
coords.reverse()
elif num_of_coords == 3:
if opts["--reverse"]:
coords = ["x", "z", "y"]
else:
coords = ["x", "y", "z"]
massE = float(opts["--massE"]) if opts["--massE"] else None
d = add_quantities(d, coords, massE=massE)
if opts["--dict"]:
d = {k: d[k] for k in d.dtype.names}
from pys import dump_pickle
dump_pickle(outname, d)
else:
np.save(outname, d)
for name in pext ];
d[:] = [
rfn.rec_append_fields(
id, 'species',
np.ones(len(id)).astype(int)*pexts[i]['species'])
for id,i in zip(d,key) ];
vprint('length of d={}'.format(len(d)));
d = [ i for i in d if i['t'].shape[0] > 0];
vprint('length of d={} after remove empties'.format(len(d)));
vprint('cutting out duplicate times');
if len(d) > 1:
d = np.concatenate(d);
elif d == []:
print("empty pext");
quit();
else:
d = d[0];
vprint('sorting by times')
d.sort(order='t');
if latetime:
print('cutting out times greater than {}'.format(latetime));
d = d[ d['t'] <= latetime ];
#calculating quantities
if opts['--reverse']:
dim = dim[:-2] + list(reversed(dim[-2:]))
massE = float(opts['--massE']) if opts['--massE'] else None;
d = add_quantities(d, dim, massE=massE);
np.save(outname, d);
