def solve(self, lists, previous_selection=set()):
"""
>>> x = {Context(value=1.0, cohorts={1,2,3}), Context(value=2.0, cohorts={2,3,4})}
>>> m = GreedyMaxCover()
>>> r = m.run(x) # Silent the result
>>> r = m.results_in_list
>>> r == [[1,2,3]] or r == [[2,3,4]]
True
"""
result1 = []
GreedyMaxCover._solve(lists, result1)
size1 = MaxCover.length_of_total_elements(result1)
size2 = -1
result2 = []
if previous_selection:
result2 = GreedyMaxCover.get_selection_from_previous_results(lists, previous_selection)
size2 = MaxCover.length_of_total_elements(result2)
result3 = []
GreedyMaxCover._solve_from_size(lists, result3)
size3 = MaxCover.length_of_total_elements(result3)
# Find the distinct set of possible selections
if size1 > size2:
if size1 > size3:
return [result1]
else:
return [result3]
else:
if size2 > size3:
return [result2]
else:
return [result3]
def get_list_with_maximum_friends(lists):
"""
>>> x = [[1,2,3],[3,4],[4,5,6],[6,7,8,9]]
>>> GreedyMaxCover.get_list_with_maximum_friends(x) == [1,2,3]
True
"""
result = {}
for i, l in enumerate(lists):
friend, enemy = MaxCover.find_friend_enemy(lists, l)
f = MaxCover.length_of_total_elements(friend)
e = MaxCover.length_of_total_elements(enemy)
result[i] = f - e
# print result
r = sorted(result.iteritems(), key=operator.itemgetter(1), reverse=True)
# print r
return lists[r[0][0]]