def test_newsletter_languages(self):
# newsletter_languages() returns the set of languages
# of the newsletters
# (Note that newsletter_languages() is not part of the external
# API, but is used internally)
models.Newsletter.objects.create(
slug='slug',
title='title',
active=False,
languages='en-US',
vendor_id='VENDOR1',
)
models.Newsletter.objects.create(
slug='slug2',
title='title',
active=False,
languages='fr, de ',
vendor_id='VENDOR2',
)
models.Newsletter.objects.create(
slug='slug3',
title='title',
active=False,
languages='en-US, fr',
vendor_id='VENDOR3',
)
expect = set(['en-US', 'fr', 'de'])
self.assertEqual(expect, newsletter_languages())
def test_newsletter_languages(self):
# newsletter_languages() returns the set of languages
# of the newsletters
# (Note that newsletter_languages() is not part of the external
# API, but is used internally)
models.Newsletter.objects.create(
slug='slug',
title='title',
active=False,
languages='en-US',
vendor_id='VENDOR1',
)
models.Newsletter.objects.create(
slug='slug2',
title='title',
active=False,
languages='fr, de ',
vendor_id='VENDOR2',
)
models.Newsletter.objects.create(
slug='slug3',
title='title',
active=False,
languages='en-US, fr',
vendor_id='VENDOR3',
)
expect = set(['en-US', 'fr', 'de'])
self.assertEqual(expect, newsletter_languages())
def get_accept_languages(header_value):
"""
Parse the user's Accept-Language HTTP header and return a list of languages
"""
# adapted from bedrock: http://j.mp/1o3pWo5
languages = []
pattern = re.compile(r'^([A-Za-z]{2,3})(?:-([A-Za-z]{2})(?:-[A-Za-z0-9]+)?)?$')
# bug 1102652
header_value = header_value.replace('_', '-')
try:
parsed = parse_accept_lang_header(header_value)
except ValueError: # see https://code.djangoproject.com/ticket/21078
return languages
for lang, priority in parsed:
m = pattern.match(lang)
if not m:
continue
lang = m.group(1).lower()
# Check if the shorter code is supported. This covers obsolete long
# codes like fr-FR (should match fr) or ja-JP (should match ja)
if m.group(2) and lang not in newsletter_languages():
lang += '-' + m.group(2).upper()
if lang not in languages:
languages.append(lang)
return languages
def get_accept_languages(header_value):
"""
Parse the user's Accept-Language HTTP header and return a list of languages
"""
# adapted from bedrock: http://j.mp/1o3pWo5
languages = []
pattern = re.compile(
r'^([A-Za-z]{2,3})(?:-([A-Za-z]{2})(?:-[A-Za-z0-9]+)?)?$')
# bug 1102652
header_value = header_value.replace('_', '-')
try:
parsed = parse_accept_lang_header(header_value)
except ValueError: # see https://code.djangoproject.com/ticket/21078
return languages
for lang, priority in parsed:
m = pattern.match(lang)
if not m:
continue
lang = m.group(1).lower()
# Check if the shorter code is supported. This covers obsolete long
# codes like fr-FR (should match fr) or ja-JP (should match ja)
if m.group(2) and lang not in newsletter_languages():
lang += '-' + m.group(2).upper()
if lang not in languages:
languages.append(lang)
return languages
def test_newsletter_languages(self):
# newsletter_languages() returns the set of languages
# of the newsletters
# (Note that newsletter_languages() is not part of the external
# API, but is used internally)
models.Newsletter.objects.create(
slug="slug", title="title", active=False, languages="en-US", vendor_id="VENDOR1"
)
models.Newsletter.objects.create(
slug="slug2", title="title", active=False, languages="fr, de ", vendor_id="VENDOR2"
)
models.Newsletter.objects.create(
slug="slug3", title="title", active=False, languages="en-US, fr", vendor_id="VENDOR3"
)
expect = set(["en-US", "fr", "de"])
self.assertEqual(expect, newsletter_languages())
def get_best_language(languages):
"""
Return the best language for use with our newsletters. If none match, return first in list.
@param languages: list of language codes.
@return: a single language code
"""
if not languages:
return None
# try again with 2 letter languages
languages_2l = [lang[:2] for lang in languages]
supported_langs = newsletter_languages()
for lang in chain(languages, languages_2l):
if lang in supported_langs:
return lang
return languages[0]
def get_best_language(languages):
"""
Return the best language for use with our newsletters. If none match, return first in list.
@param languages: list of language codes.
@return: a single language code
"""
if not languages:
return None
# try again with 2 letter languages
languages_2l = [lang[:2] for lang in languages]
supported_langs = newsletter_languages()
for lang in chain(languages, languages_2l):
if lang in supported_langs:
return lang
return languages[0]
