Python dict_add_by_distance 예제들

예제 #1

def fourSum(num, target):
    d = {}
    num1 = list(enumerate_t(num))
    num2 = comb2(num1)
    dict_add_by_distance(d, num2, target)
    return list(
        map(list, frozenset(indices_to_num(get_all_pairs(d, target, 4), num))))

예제 #2

def threeSum(num):
    target = 0
    d = {}
    num1 = list(enumerate_t(num))
    num2 = comb2(num1)
    dict_add_by_distance(d, num1, target)
    dict_add_by_distance(d, num2, target)
    return map(list, frozenset(indices_to_num(get_all_pairs(d,target,3),num)))

예제 #3

파일: 18-4sum.py 프로젝트: bhuztez/leetcode-solution

def fourSum(num, target):
    d = {}
    num1 = list(enumerate_t(num))
    num2 = comb2(num1)
    dict_add_by_distance(d, num2, target)
    return list(map(list, frozenset(indices_to_num(get_all_pairs(d,target,4),num))))

예제 #4

파일: 1-two-sum.py 프로젝트: xiaoyanyuha/leetcode-solution

def twoSum(num, target):
    d = {}
    dict_add_by_distance(d, enumerate_t(num), target)
    return list(frozenset(get_all_pairs(d, target, 2)))[0]

예제 #5

파일: 1-two-sum.py 프로젝트: IkutoJyu/leetcode-solution

def twoSum(num, target):
    d = {}
    dict_add_by_distance(d, enumerate_t(num), target)
    return list(frozenset(get_all_pairs(d, target, 2)))[0]