def delone(self, uri):
""" delete a single resource
You have to return a result dict of the form
uri:error_code
or None if everything's ok
"""
return delone(self, uri)
def delone(self, uri):
""" delete a single resource
You have to return a result dict of the form
uri:error_code
or None if everything's ok
"""
if uri[-1] == '/': uri = uri[:-1]
res = delone(self, uri)
# parent='/'.join(uri.split('/')[:-1])
return res
def delone(self, uri):
return delone(self, uri)
