예제 #1
0
파일: pb12.py 프로젝트: mihandrei/prototype
def triangular_divisors(n):
    if n%2==0:
        af = factor(n/2)
        bf = factor(n+1)
    else:
        af = factor((n+1)/2)
        bf = factor(n)

    triangular_factors = af + bf
    
    ndivizors = 1
    for p, e in triangular_factors:
        ndivizors *= (e+1)
    return ndivizors
예제 #2
0
파일: p21.py 프로젝트: mihandrei/prototype
def divisor_iter(n):    
    factorization = factor(n)

    # factorization of the current divisor
    divisor_fact = [(p, 0) for p, e in factorization]

    def _next_divisor_fact():
        """ count up from 2**0 * 3*0 * ... to the factorization"""
        for i in xrange(len(factorization)):
            dp, de = divisor_fact[i]
            if de < factorization[i][1]:                
                divisor_fact[i] = (dp, de + 1)
                return divisor_fact
            else: #overflow
                divisor_fact[i] = (dp, 0)
                if i == len(factorization) - 1:
                    return None

    def _compute_divisor():
        mul = 1
        for p, e in divisor_fact:
            mul *= p**e
        return mul


    while True:
        yield _compute_divisor()
        if not _next_divisor_fact():
            return
예제 #3
0
파일: pb12.py 프로젝트: mihandrei/prototype
def pb12():
    """
    What is the value of the first triangle number to have over five hundred divisors?
    """
    for i in xrange(2, 10**9):
        td =  triangular_divisors(i)
        if (td >= 500):
            print i, td, i*(i+1)/2, factor(i*(i+1)/2)
            break
예제 #4
0
def totient(n, cached_primes=None):
    t = 1
    for p, e in factor(n, cached_primes):
        t *= p**(e - 1) * (p - 1)
    return t