예제 #1
0
def test_trailing_bitcount():
    assert trailing(0) == 0
    assert trailing(1) == 0
    assert trailing(-1) == 0
    assert trailing(2) == 1
    assert trailing(7) == 0
    assert trailing(-7) == 0
    for i in range(100):
        assert trailing(1 << i) == i
        assert trailing((1 << i) * 31337) == i
    assert trailing(1 << 1000001) == 1000001
    assert trailing((1 << 273956)*7**37) == 273956
    # issue 12709
    big = small_trailing[-1]*2
    assert trailing(-big) == trailing(big)
    assert bitcount(-big) == bitcount(big)
예제 #2
0
def trailing(n):
    """Count the number of trailing zero digits in the binary
    representation of n, i.e. determine the largest power of 2
    that divides n."""
    n = int(n)
    if not n:
        return 0
    low_byte = n & 0xff
    if low_byte:
        return small_trailing[low_byte]

    # 2**m is quick for z up through 2**30
    z = bitcount(n) - 1
    if type(z) is int:
        if n == 1 << z:
            return z

    t = 0
    p = 8
    while not n & 1:
        while not n & ((1<<p)-1):
            n >>= p
            t += p
            p *= 2
        p //= 2
    return t
예제 #3
0
def test_trailing_bitcount():
    assert trailing(0) == 0
    assert trailing(1) == 0
    assert trailing(-1) == 0
    assert trailing(2) == 1
    assert trailing(7) == 0
    assert trailing(-7) == 0
    for i in range(100):
        assert trailing((1 << i)) == i
        assert trailing((1 << i) * 31337) == i
    assert trailing((1 << 1000001)) == 1000001
    assert trailing((1 << 273956)*7**37) == 273956
    # issue 12709
    big = small_trailing[-1]*2
    assert trailing(-big) == trailing(big)
    assert bitcount(-big) == bitcount(big)
예제 #4
0
파일: factor_.py 프로젝트: tomtwohats/sympy
def trailing(n):
    """Count the number of trailing zero digits in the binary
    representation of n, i.e. determine the largest power of 2
    that divides n.

    Examples
    ========
    >>> from sympy import trailing
    >>> trailing(128)
    7
    >>> trailing(63)
    0
    """
    n = int(n)
    if not n:
        return 0
    low_byte = n & 0xff
    if low_byte:
        return small_trailing[low_byte]

    # 2**m is quick for z up through 2**30
    z = bitcount(n) - 1
    if type(z) is int:
        if n == 1 << z:
            return z

    t = 0
    p = 8
    while not n & 1:
        while not n & ((1<<p)-1):
            n >>= p
            t += p
            p *= 2
        p //= 2
    return t
예제 #5
0
파일: factor_.py 프로젝트: mattpap/sympy
def trailing(n):
    """Count the number of trailing zero digits in the binary
    representation of n, i.e. determine the largest power of 2
    that divides n.

    Examples
    ========

    >>> from sympy import trailing
    >>> trailing(128)
    7
    >>> trailing(63)
    0
    """
    n = int(n)
    if not n:
        return 0
    low_byte = n & 0xff
    if low_byte:
        return small_trailing[low_byte]

    # 2**m is quick for z up through 2**30
    z = bitcount(n) - 1
    if isinstance(z, SYMPY_INTS):
        if n == 1 << z:
            return z

    t = 0
    p = 8
    while not n & 1:
        while not n & ((1 << p) - 1):
            n >>= p
            t += p
            p *= 2
        p //= 2
    return t