예제 #1
0
파일: beam.py 프로젝트: carstimon/sympy
    def slope(self):
        """
        Returns a Singularity Function expression which represents
        the slope the elastic curve of the Beam object.

        Examples
        ========
        There is a beam of length 30 meters. A moment of magnitude 120 Nm is
        applied in the clockwise direction at the end of the beam. A pointload
        of magnitude 8 N is applied from the top of the beam at the starting
        point. There are two simple supports below the beam. One at the end
        and another one at a distance of 10 meters from the start. The
        deflection is restricted at both the supports.

        Using the sign convention of upward forces and clockwise moment
        being positive.

        >>> from sympy.physics.continuum_mechanics.beam import Beam
        >>> from sympy import symbols
        >>> E, I = symbols('E, I')
        >>> R1, R2 = symbols('R1, R2')
        >>> b = Beam(30, E, I)
        >>> b.apply_load(-8, 0, -1)
        >>> b.apply_load(R1, 10, -1)
        >>> b.apply_load(R2, 30, -1)
        >>> b.apply_load(120, 30, -2)
        >>> b.bc_deflection = [(10, 0), (30, 0)]
        >>> b.solve_for_reaction_loads(R1, R2)
        >>> b.slope()
        (-4*SingularityFunction(x, 0, 2) + 3*SingularityFunction(x, 10, 2)
            + 120*SingularityFunction(x, 30, 1) + SingularityFunction(x, 30, 2) + 4000/3)/(E*I)
        """
        x = self.variable
        E = self.elastic_modulus
        I = self.second_moment
        if not self._boundary_conditions['slope']:
            return diff(self.deflection(), x)

        C3 = Symbol('C3')
        slope_curve = integrate(self.bending_moment(), x) + C3

        bc_eqs = []
        for position, value in self._boundary_conditions['slope']:
            eqs = slope_curve.subs(x, position) - value
            bc_eqs.append(eqs)

        constants = list(linsolve(bc_eqs, C3))
        slope_curve = slope_curve.subs({C3: constants[0][0]})
        return S(1)/(E*I)*slope_curve
예제 #2
0
    def slope(self):
        """
        Returns a Singularity Function expression which represents
        the slope the elastic curve of the Beam object.

        Examples
        ========
        There is a beam of length 30 meters. A moment of magnitude 120 Nm is
        applied in the clockwise direction at the end of the beam. A pointload
        of magnitude 8 N is applied from the top of the beam at the starting
        point. There are two simple supports below the beam. One at the end
        and another one at a distance of 10 meters from the start. The
        deflection is restricted at both the supports.

        Using the sign convention of upward forces and clockwise moment
        being positive.

        >>> from sympy.physics.continuum_mechanics.beam import Beam
        >>> from sympy import symbols
        >>> E, I = symbols('E, I')
        >>> R1, R2 = symbols('R1, R2')
        >>> b = Beam(30, E, I)
        >>> b.apply_load(-8, 0, -1)
        >>> b.apply_load(R1, 10, -1)
        >>> b.apply_load(R2, 30, -1)
        >>> b.apply_load(120, 30, -2)
        >>> b.bc_deflection = [(10, 0), (30, 0)]
        >>> b.solve_for_reaction_loads(R1, R2)
        >>> b.slope()
        (-4*SingularityFunction(x, 0, 2) + 3*SingularityFunction(x, 10, 2)
            + 120*SingularityFunction(x, 30, 1) + SingularityFunction(x, 30, 2) + 4000/3)/(E*I)
        """
        x = self.variable
        E = self.elastic_modulus
        I = self.second_moment
        if not self._boundary_conditions['slope']:
            return diff(self.deflection(), x)

        C3 = Symbol('C3')
        slope_curve = integrate(self.bending_moment(), x) + C3

        bc_eqs = []
        for position, value in self._boundary_conditions['slope']:
            eqs = slope_curve.subs(x, position) - value
            bc_eqs.append(eqs)

        constants = list(linsolve(bc_eqs, C3))
        slope_curve = slope_curve.subs({C3: constants[0][0]})
        return S(1) / (E * I) * slope_curve
예제 #3
0
    def solve_for_reaction_loads(self, *reactions):
        """
        Solves for the reaction forces.

        Examples
        ========
        There is a beam of length 30 meters. A moment of magnitude 120 Nm is
        applied in the clockwise direction at the end of the beam. A pointload
        of magnitude 8 N is applied from the top of the beam at the starting
        point. There are two simple supports below the beam. One at the end
        and another one at a distance of 10 meters from the start. The
        deflection is restricted at both the supports.

        Using the sign convention of upward forces and clockwise moment
        being positive.

        >>> from sympy.physics.continuum_mechanics.beam import Beam
        >>> from sympy import symbols, linsolve, limit
        >>> E, I = symbols('E, I')
        >>> R1, R2 = symbols('R1, R2')
        >>> b = Beam(30, E, I)
        >>> b.apply_load(-8, 0, -1)
        >>> b.apply_load(R1, 10, -1)  # Reaction force at x = 10
        >>> b.apply_load(R2, 30, -1)  # Reaction force at x = 30
        >>> b.apply_load(120, 30, -2)
        >>> b.bc_deflection = [(10, 0), (30, 0)]
        >>> b.load
        R1*SingularityFunction(x, 10, -1) + R2*SingularityFunction(x, 30, -1)
            - 8*SingularityFunction(x, 0, -1) + 120*SingularityFunction(x, 30, -2)
        >>> b.solve_for_reaction_loads(R1, R2)
        >>> b.reaction_loads
        {R1: 6, R2: 2}
        >>> b.load
        -8*SingularityFunction(x, 0, -1) + 6*SingularityFunction(x, 10, -1)
            + 120*SingularityFunction(x, 30, -2) + 2*SingularityFunction(x, 30, -1)
        """
        if self._composite_type == "hinge":
            return self._solve_hinge_beams(*reactions)

        x = self.variable
        l = self.length
        shear_curve = limit(self.shear_force(), x, l)
        moment_curve = limit(self.bending_moment(), x, l)
        reaction_values = linsolve([shear_curve, moment_curve], reactions).args
        self._reaction_loads = dict(zip(reactions, reaction_values[0]))
        self._load = self._load.subs(self._reaction_loads)
예제 #4
0
    def solve_for_reaction_loads(self, *reactions):
        """
        Solves for the reaction forces.

        Examples
        ========
        There is a beam of length 30 meters. A moment of magnitude 120 Nm is
        applied in the clockwise direction at the end of the beam. A pointload
        of magnitude 8 N is applied from the top of the beam at the starting
        point. There are two simple supports below the beam. One at the end
        and another one at a distance of 10 meters from the start. The
        deflection is restricted at both the supports.

        Using the sign convention of upward forces and clockwise moment
        being positive.

        >>> from sympy.physics.continuum_mechanics.beam import Beam
        >>> from sympy import symbols, linsolve, limit
        >>> E, I = symbols('E, I')
        >>> R1, R2 = symbols('R1, R2')
        >>> b = Beam(30, E, I)
        >>> b.apply_load(-8, 0, -1)
        >>> b.apply_load(R1, 10, -1)  # Reaction force at x = 10
        >>> b.apply_load(R2, 30, -1)  # Reaction force at x = 30
        >>> b.apply_load(120, 30, -2)
        >>> b.bc_deflection = [(10, 0), (30, 0)]
        >>> b.load
        R1*SingularityFunction(x, 10, -1) + R2*SingularityFunction(x, 30, -1)
            - 8*SingularityFunction(x, 0, -1) + 120*SingularityFunction(x, 30, -2)
        >>> b.solve_for_reaction_loads(R1, R2)
        >>> b.reaction_loads
        {R1: 6, R2: 2}
        >>> b.load
        -8*SingularityFunction(x, 0, -1) + 6*SingularityFunction(x, 10, -1)
            + 120*SingularityFunction(x, 30, -2) + 2*SingularityFunction(x, 30, -1)
        """
        if self._composite_type == "hinge":
            return self._solve_hinge_beams(*reactions)

        x = self.variable
        l = self.length
        shear_curve = limit(self.shear_force(), x, l)
        moment_curve = limit(self.bending_moment(), x, l)
        reaction_values = linsolve([shear_curve, moment_curve], reactions).args
        self._reaction_loads = dict(zip(reactions, reaction_values[0]))
        self._load = self._load.subs(self._reaction_loads)
예제 #5
0
파일: beam.py 프로젝트: wxgeo/geophar
    def deflection(self):
        """
        Returns a Singularity Function expression which represents
        the elastic curve or deflection of the Beam object.

        Examples
        ========
        There is a beam of length 30 meters. A moment of magnitude 120 Nm is
        applied in the clockwise direction at the end of the beam. A pointload
        of magnitude 8 N is applied from the top of the beam at the starting
        point. There are two simple supports below the beam. One at the end
        and another one at a distance of 10 meters from the start. The
        deflection is restricted at both the supports.

        Using the sign convention of upward forces and clockwise moment
        being positive.

        >>> from sympy.physics.continuum_mechanics.beam import Beam
        >>> from sympy import symbols
        >>> E, I = symbols('E, I')
        >>> R1, R2 = symbols('R1, R2')
        >>> b = Beam(30, E, I)
        >>> b.apply_load(-8, 0, -1)
        >>> b.apply_load(R1, 10, -1)
        >>> b.apply_load(R2, 30, -1)
        >>> b.apply_load(120, 30, -2)
        >>> b.bc_deflection = [(10, 0), (30, 0)]
        >>> b.solve_for_reaction_loads(R1, R2)
        >>> b.deflection()
        (4000*x/3 - 4*SingularityFunction(x, 0, 3)/3 + SingularityFunction(x, 10, 3)
            + 60*SingularityFunction(x, 30, 2) + SingularityFunction(x, 30, 3)/3 - 12000)/(E*I)
        """
        x = self.variable
        E = self.elastic_modulus
        I = self.second_moment
        if self._composite_type == "hinge":
            return self._hinge_beam_deflection
        if not self._boundary_conditions['deflection'] and not self._boundary_conditions['slope']:
            if self._composite_type == "fixed":
                args = I.args
                conditions = []
                prev_def = 0
                prev_end = 0
                for i in range(len(args)):
                    if i != 0:
                        prev_end = args[i-1][1].args[1]
                    deflection_value = integrate(self.slope().args[i][0], (x, prev_end, x))
                    conditions.append(((prev_def + deflection_value), args[i][1]))
                    prev_def = deflection_value.subs(x, args[i][1].args[1])
                return Piecewise(*conditions)
            return S(1)/(E*I)*integrate(integrate(self.bending_moment(), x), x)
        elif not self._boundary_conditions['deflection']:
            return integrate(self.slope(), x)
        elif not self._boundary_conditions['slope'] and self._boundary_conditions['deflection']:
            if self._composite_type == "fixed":
                args = I.args
                conditions = []
                prev_def = 0
                prev_end = 0
                for i in range(len(args)):
                    if i != 0:
                        prev_end = args[i-1][1].args[1]
                    deflection_value = integrate(self.slope().args[i][0], (x, prev_end, x))
                    conditions.append(((prev_def + deflection_value), args[i][1]))
                    prev_def = deflection_value.subs(x, args[i][1].args[1])
                return Piecewise(*conditions)
            C3 = Symbol('C3')
            C4 = Symbol('C4')
            slope_curve = integrate(self.bending_moment(), x) + C3
            deflection_curve = integrate(slope_curve, x) + C4
            bc_eqs = []
            for position, value in self._boundary_conditions['deflection']:
                eqs = deflection_curve.subs(x, position) - value
                bc_eqs.append(eqs)
            constants = list(linsolve(bc_eqs, (C3, C4)))
            deflection_curve = deflection_curve.subs({C3: constants[0][0], C4: constants[0][1]})
            return S(1)/(E*I)*deflection_curve

        if self._composite_type == "fixed":
            args = I.args
            conditions = []
            prev_def = 0
            prev_end = 0
            for i in range(len(args)):
                if i != 0:
                    prev_end = args[i-1][1].args[1]
                deflection_value = integrate(self.slope().args[i][0], (x, prev_end, x))
                conditions.append(((prev_def + deflection_value), args[i][1]))
                prev_def = deflection_value.subs(x, args[i][1].args[1])
            return Piecewise(*conditions)

        C4 = Symbol('C4')
        deflection_curve = integrate((E*I)*self.slope(), x) + C4

        bc_eqs = []
        for position, value in self._boundary_conditions['deflection']:
            eqs = deflection_curve.subs(x, position) - value
            bc_eqs.append(eqs)

        constants = list(linsolve(bc_eqs, C4))
        deflection_curve = deflection_curve.subs({C4: constants[0][0]})
        return S(1)/(E*I)*deflection_curve
예제 #6
0
파일: beam.py 프로젝트: wxgeo/geophar
    def solve_for_reaction_loads(self, *reactions):
        """
        Solves for the reaction forces.

        Examples
        ========
        There is a beam of length 30 meters. A moment of magnitude 120 Nm is
        applied in the clockwise direction at the end of the beam. A pointload
        of magnitude 8 N is applied from the top of the beam at the starting
        point. There are two simple supports below the beam. One at the end
        and another one at a distance of 10 meters from the start. The
        deflection is restricted at both the supports.

        Using the sign convention of upward forces and clockwise moment
        being positive.

        >>> from sympy.physics.continuum_mechanics.beam import Beam
        >>> from sympy import symbols, linsolve, limit
        >>> E, I = symbols('E, I')
        >>> R1, R2 = symbols('R1, R2')
        >>> b = Beam(30, E, I)
        >>> b.apply_load(-8, 0, -1)
        >>> b.apply_load(R1, 10, -1)  # Reaction force at x = 10
        >>> b.apply_load(R2, 30, -1)  # Reaction force at x = 30
        >>> b.apply_load(120, 30, -2)
        >>> b.bc_deflection = [(10, 0), (30, 0)]
        >>> b.load
        R1*SingularityFunction(x, 10, -1) + R2*SingularityFunction(x, 30, -1)
            - 8*SingularityFunction(x, 0, -1) + 120*SingularityFunction(x, 30, -2)
        >>> b.solve_for_reaction_loads(R1, R2)
        >>> b.reaction_loads
        {R1: 6, R2: 2}
        >>> b.load
        -8*SingularityFunction(x, 0, -1) + 6*SingularityFunction(x, 10, -1)
            + 120*SingularityFunction(x, 30, -2) + 2*SingularityFunction(x, 30, -1)
        """
        if self._composite_type == "hinge":
            return self._solve_hinge_beams(*reactions)

        x = self.variable
        l = self.length
        C3 = Symbol('C3')
        C4 = Symbol('C4')

        shear_curve = limit(self.shear_force(), x, l)
        moment_curve = limit(self.bending_moment(), x, l)

        slope_eqs = []
        deflection_eqs = []

        slope_curve = integrate(self.bending_moment(), x) + C3
        for position, value in self._boundary_conditions['slope']:
            eqs = slope_curve.subs(x, position) - value
            slope_eqs.append(eqs)

        deflection_curve = integrate(slope_curve, x) + C4
        for position, value in self._boundary_conditions['deflection']:
            eqs = deflection_curve.subs(x, position) - value
            deflection_eqs.append(eqs)

        solution = list((linsolve([shear_curve, moment_curve] + slope_eqs
                            + deflection_eqs, (C3, C4) + reactions).args)[0])
        solution = solution[2:]

        self._reaction_loads = dict(zip(reactions, solution))
        self._load = self._load.subs(self._reaction_loads)
예제 #7
0
파일: beam.py 프로젝트: wxgeo/geophar
    def _solve_hinge_beams(self, *reactions):
        """Method to find integration constants and reactional variables in a
        composite beam connected via hinge.
        This method resolves the composite Beam into its sub-beams and then
        equations of shear force, bending moment, slope and deflection are
        evaluated for both of them separately. These equations are then solved
        for unknown reactions and integration constants using the boundary
        conditions applied on the Beam. Equal deflection of both sub-beams
        at the hinge joint gives us another equation to solve the system.

        Examples
        ========
        A combined beam, with constant fkexural rigidity E*I, is formed by joining
        a Beam of length 2*l to the right of another Beam of length l. The whole beam
        is fixed at both of its both end. A point load of magnitude P is also applied
        from the top at a distance of 2*l from starting point.

        >>> from sympy.physics.continuum_mechanics.beam import Beam
        >>> from sympy import symbols
        >>> E, I = symbols('E, I')
        >>> l=symbols('l', positive=True)
        >>> b1=Beam(l ,E,I)
        >>> b2=Beam(2*l ,E,I)
        >>> b=b1.join(b2,"hinge")
        >>> M1, A1, M2, A2, P = symbols('M1 A1 M2 A2 P')
        >>> b.apply_load(A1,0,-1)
        >>> b.apply_load(M1,0,-2)
        >>> b.apply_load(P,2*l,-1)
        >>> b.apply_load(A2,3*l,-1)
        >>> b.apply_load(M2,3*l,-2)
        >>> b.bc_slope=[(0,0), (3*l, 0)]
        >>> b.bc_deflection=[(0,0), (3*l, 0)]
        >>> b.solve_for_reaction_loads(M1, A1, M2, A2)
        >>> b.reaction_loads
        {A1: -5*P/18, A2: -13*P/18, M1: 5*P*l/18, M2: -4*P*l/9}
        >>> b.slope()
        Piecewise(((5*P*l*SingularityFunction(x, 0, 1)/18 - 5*P*SingularityFunction(x, 0, 2)/36
        + 5*P*SingularityFunction(x, l, 2)/36)/(E*I), l >= x), ((P*l**2/18 - 4*P*l*SingularityFunction(-l +
        x, 2*l, 1)/9 - 5*P*SingularityFunction(-l + x, 0, 2)/36 + P*SingularityFunction(-l + x, l, 2)/2
        - 13*P*SingularityFunction(-l + x, 2*l, 2)/36)/(E*I), x < 3*l))
        >>> b.deflection()
        Piecewise(((5*P*l*SingularityFunction(x, 0, 2)/36 - 5*P*SingularityFunction(x, 0, 3)/108
        + 5*P*SingularityFunction(x, l, 3)/108)/(E*I), l >= x), ((5*P*l**3/54 + P*l**2*(-l + x)/18
        - 2*P*l*SingularityFunction(-l + x, 2*l, 2)/9 - 5*P*SingularityFunction(-l + x, 0, 3)/108
        + P*SingularityFunction(-l + x, l, 3)/6 - 13*P*SingularityFunction(-l + x, 2*l, 3)/108)/(E*I), x < 3*l))
        """
        x = self.variable
        l = self._hinge_position
        E = self._elastic_modulus
        I = self._second_moment

        if isinstance(I, Piecewise):
            I1 = I.args[0][0]
            I2 = I.args[1][0]
        else:
            I1 = I2 = I

        load_1 = 0       # Load equation on first segment of composite beam
        load_2 = 0       # Load equation on second segment of composite beam

        # Distributing load on both segments
        for load in self.applied_loads:
            if load[1] < l:
                load_1 += load[0]*SingularityFunction(x, load[1], load[2])
                if load[2] == 0:
                    load_1 -= load[0]*SingularityFunction(x, load[3], load[2])
                elif load[2] > 0:
                    load_1 -= load[0]*SingularityFunction(x, load[3], load[2]) + load[0]*SingularityFunction(x, load[3], 0)
            elif load[1] == l:
                load_1 += load[0]*SingularityFunction(x, load[1], load[2])
                load_2 += load[0]*SingularityFunction(x, load[1] - l, load[2])
            elif load[1] > l:
                load_2 += load[0]*SingularityFunction(x, load[1] - l, load[2])
                if load[2] == 0:
                    load_2 -= load[0]*SingularityFunction(x, load[3] - l, load[2])
                elif load[2] > 0:
                    load_2 -= load[0]*SingularityFunction(x, load[3] - l, load[2]) + load[0]*SingularityFunction(x, load[3] - l, 0)

        h = Symbol('h')     # Force due to hinge
        load_1 += h*SingularityFunction(x, l, -1)
        load_2 -= h*SingularityFunction(x, 0, -1)

        eq = []
        shear_1 = integrate(load_1, x)
        shear_curve_1 = limit(shear_1, x, l)
        eq.append(shear_curve_1)
        bending_1 = integrate(shear_1, x)
        moment_curve_1 = limit(bending_1, x, l)
        eq.append(moment_curve_1)

        shear_2 = integrate(load_2, x)
        shear_curve_2 = limit(shear_2, x, self.length - l)
        eq.append(shear_curve_2)
        bending_2 = integrate(shear_2, x)
        moment_curve_2 = limit(bending_2, x, self.length - l)
        eq.append(moment_curve_2)

        C1 = Symbol('C1')
        C2 = Symbol('C2')
        C3 = Symbol('C3')
        C4 = Symbol('C4')
        slope_1 = S(1)/(E*I1)*(integrate(bending_1, x) + C1)
        def_1 = S(1)/(E*I1)*(integrate((E*I)*slope_1, x) + C1*x + C2)
        slope_2 = S(1)/(E*I2)*(integrate(integrate(integrate(load_2, x), x), x) + C3)
        def_2 = S(1)/(E*I2)*(integrate((E*I)*slope_2, x) + C4)

        for position, value in self.bc_slope:
            if position<l:
                eq.append(slope_1.subs(x, position) - value)
            else:
                eq.append(slope_2.subs(x, position - l) - value)

        for position, value in self.bc_deflection:
            if position<l:
                eq.append(def_1.subs(x, position) - value)
            else:
                eq.append(def_2.subs(x, position - l) - value)

        eq.append(def_1.subs(x, l) - def_2.subs(x, 0)) # Deflection of both the segments at hinge would be equal

        constants = list(linsolve(eq, C1, C2, C3, C4, h, *reactions))
        reaction_values = list(constants[0])[5:]

        self._reaction_loads = dict(zip(reactions, reaction_values))
        self._load = self._load.subs(self._reaction_loads)

        # Substituting constants and reactional load and moments with their corresponding values
        slope_1 = slope_1.subs({C1: constants[0][0], h:constants[0][4]}).subs(self._reaction_loads)
        def_1 = def_1.subs({C1: constants[0][0], C2: constants[0][1], h:constants[0][4]}).subs(self._reaction_loads)
        slope_2 = slope_2.subs({x: x-l, C3: constants[0][2], h:constants[0][4]}).subs(self._reaction_loads)
        def_2 = def_2.subs({x: x-l,C3: constants[0][2], C4: constants[0][3], h:constants[0][4]}).subs(self._reaction_loads)

        self._hinge_beam_slope = Piecewise((slope_1, x<=l), (slope_2, x<self.length))
        self._hinge_beam_deflection = Piecewise((def_1, x<=l), (def_2, x<self.length))
예제 #8
0
    def deflection(self):
        """
        Returns a Singularity Function expression which represents
        the elastic curve or deflection of the Beam object.

        Examples
        ========
        There is a beam of length 30 meters. A moment of magnitude 120 Nm is
        applied in the clockwise direction at the end of the beam. A pointload
        of magnitude 8 N is applied from the top of the beam at the starting
        point. There are two simple supports below the beam. One at the end
        and another one at a distance of 10 meters from the start. The
        deflection is restricted at both the supports.

        Using the sign convention of upward forces and clockwise moment
        being positive.

        >>> from sympy.physics.continuum_mechanics.beam import Beam
        >>> from sympy import symbols
        >>> E, I = symbols('E, I')
        >>> R1, R2 = symbols('R1, R2')
        >>> b = Beam(30, E, I)
        >>> b.apply_load(-8, 0, -1)
        >>> b.apply_load(R1, 10, -1)
        >>> b.apply_load(R2, 30, -1)
        >>> b.apply_load(120, 30, -2)
        >>> b.bc_deflection = [(10, 0), (30, 0)]
        >>> b.solve_for_reaction_loads(R1, R2)
        >>> b.deflection()
        (4000*x/3 - 4*SingularityFunction(x, 0, 3)/3 + SingularityFunction(x, 10, 3)
            + 60*SingularityFunction(x, 30, 2) + SingularityFunction(x, 30, 3)/3 - 12000)/(E*I)
        """
        x = self.variable
        E = self.elastic_modulus
        I = self.second_moment
        if self._composite_type == "hinge":
            return self._hinge_beam_deflection
        if not self._boundary_conditions['deflection'] and not self._boundary_conditions['slope']:
            if self._composite_type == "fixed":
                args = I.args
                conditions = []
                prev_def = 0
                prev_end = 0
                for i in range(len(args)):
                    if i != 0:
                        prev_end = args[i-1][1].args[1]
                    deflection_value = integrate(self.slope().args[i][0], (x, prev_end, x))
                    conditions.append(((prev_def + deflection_value), args[i][1]))
                    prev_def = deflection_value.subs(x, args[i][1].args[1])
                return Piecewise(*conditions)
            return S(1)/(E*I)*integrate(integrate(self.bending_moment(), x), x)
        elif not self._boundary_conditions['deflection']:
            return integrate(self.slope(), x)
        elif not self._boundary_conditions['slope'] and self._boundary_conditions['deflection']:
            if self._composite_type == "fixed":
                args = I.args
                conditions = []
                prev_def = 0
                prev_end = 0
                for i in range(len(args)):
                    if i != 0:
                        prev_end = args[i-1][1].args[1]
                    deflection_value = integrate(self.slope().args[i][0], (x, prev_end, x))
                    conditions.append(((prev_def + deflection_value), args[i][1]))
                    prev_def = deflection_value.subs(x, args[i][1].args[1])
                return Piecewise(*conditions)
            C3 = Symbol('C3')
            C4 = Symbol('C4')
            slope_curve = integrate(self.bending_moment(), x) + C3
            deflection_curve = integrate(slope_curve, x) + C4
            bc_eqs = []
            for position, value in self._boundary_conditions['deflection']:
                eqs = deflection_curve.subs(x, position) - value
                bc_eqs.append(eqs)
            constants = list(linsolve(bc_eqs, (C3, C4)))
            deflection_curve = deflection_curve.subs({C3: constants[0][0], C4: constants[0][1]})
            return S(1)/(E*I)*deflection_curve

        if self._composite_type == "fixed":
            args = I.args
            conditions = []
            prev_def = 0
            prev_end = 0
            for i in range(len(args)):
                if i != 0:
                    prev_end = args[i-1][1].args[1]
                deflection_value = integrate(self.slope().args[i][0], (x, prev_end, x))
                conditions.append(((prev_def + deflection_value), args[i][1]))
                prev_def = deflection_value.subs(x, args[i][1].args[1])
            return Piecewise(*conditions)

        C4 = Symbol('C4')
        deflection_curve = integrate((E*I)*self.slope(), x) + C4

        bc_eqs = []
        for position, value in self._boundary_conditions['deflection']:
            eqs = deflection_curve.subs(x, position) - value
            bc_eqs.append(eqs)

        constants = list(linsolve(bc_eqs, C4))
        deflection_curve = deflection_curve.subs({C4: constants[0][0]})
        return S(1)/(E*I)*deflection_curve
예제 #9
0
    def solve_for_reaction_loads(self, *reactions):
        """
        Solves for the reaction forces.

        Examples
        ========
        There is a beam of length 30 meters. A moment of magnitude 120 Nm is
        applied in the clockwise direction at the end of the beam. A pointload
        of magnitude 8 N is applied from the top of the beam at the starting
        point. There are two simple supports below the beam. One at the end
        and another one at a distance of 10 meters from the start. The
        deflection is restricted at both the supports.

        Using the sign convention of upward forces and clockwise moment
        being positive.

        >>> from sympy.physics.continuum_mechanics.beam import Beam
        >>> from sympy import symbols, linsolve, limit
        >>> E, I = symbols('E, I')
        >>> R1, R2 = symbols('R1, R2')
        >>> b = Beam(30, E, I)
        >>> b.apply_load(-8, 0, -1)
        >>> b.apply_load(R1, 10, -1)  # Reaction force at x = 10
        >>> b.apply_load(R2, 30, -1)  # Reaction force at x = 30
        >>> b.apply_load(120, 30, -2)
        >>> b.bc_deflection = [(10, 0), (30, 0)]
        >>> b.load
        R1*SingularityFunction(x, 10, -1) + R2*SingularityFunction(x, 30, -1)
            - 8*SingularityFunction(x, 0, -1) + 120*SingularityFunction(x, 30, -2)
        >>> b.solve_for_reaction_loads(R1, R2)
        >>> b.reaction_loads
        {R1: 6, R2: 2}
        >>> b.load
        -8*SingularityFunction(x, 0, -1) + 6*SingularityFunction(x, 10, -1)
            + 120*SingularityFunction(x, 30, -2) + 2*SingularityFunction(x, 30, -1)
        """
        if self._composite_type == "hinge":
            return self._solve_hinge_beams(*reactions)

        x = self.variable
        l = self.length
        C3 = Symbol('C3')
        C4 = Symbol('C4')

        shear_curve = limit(self.shear_force(), x, l)
        moment_curve = limit(self.bending_moment(), x, l)

        slope_eqs = []
        deflection_eqs = []

        slope_curve = integrate(self.bending_moment(), x) + C3
        for position, value in self._boundary_conditions['slope']:
            eqs = slope_curve.subs(x, position) - value
            slope_eqs.append(eqs)

        deflection_curve = integrate(slope_curve, x) + C4
        for position, value in self._boundary_conditions['deflection']:
            eqs = deflection_curve.subs(x, position) - value
            deflection_eqs.append(eqs)

        solution = list((linsolve([shear_curve, moment_curve] + slope_eqs
                            + deflection_eqs, (C3, C4) + reactions).args)[0])
        solution = solution[2:]

        self._reaction_loads = dict(zip(reactions, solution))
        self._load = self._load.subs(self._reaction_loads)
예제 #10
0
    def _solve_hinge_beams(self, *reactions):
        """Method to find integration constants and reactional variables in a
        composite beam connected via hinge.
        This method resolves the composite Beam into its sub-beams and then
        equations of shear force, bending moment, slope and deflection are
        evaluated for both of them separately. These equations are then solved
        for unknown reactions and integration constants using the boundary
        conditions applied on the Beam. Equal deflection of both sub-beams
        at the hinge joint gives us another equation to solve the system.

        Examples
        ========
        A combined beam, with constant fkexural rigidity E*I, is formed by joining
        a Beam of length 2*l to the right of another Beam of length l. The whole beam
        is fixed at both of its both end. A point load of magnitude P is also applied
        from the top at a distance of 2*l from starting point.

        >>> from sympy.physics.continuum_mechanics.beam import Beam
        >>> from sympy import symbols
        >>> E, I = symbols('E, I')
        >>> l=symbols('l', positive=True)
        >>> b1=Beam(l ,E,I)
        >>> b2=Beam(2*l ,E,I)
        >>> b=b1.join(b2,"hinge")
        >>> M1, A1, M2, A2, P = symbols('M1 A1 M2 A2 P')
        >>> b.apply_load(A1,0,-1)
        >>> b.apply_load(M1,0,-2)
        >>> b.apply_load(P,2*l,-1)
        >>> b.apply_load(A2,3*l,-1)
        >>> b.apply_load(M2,3*l,-2)
        >>> b.bc_slope=[(0,0), (3*l, 0)]
        >>> b.bc_deflection=[(0,0), (3*l, 0)]
        >>> b.solve_for_reaction_loads(M1, A1, M2, A2)
        >>> b.reaction_loads
        {A1: -5*P/18, A2: -13*P/18, M1: 5*P*l/18, M2: -4*P*l/9}
        >>> b.slope()
        Piecewise(((5*P*l*SingularityFunction(x, 0, 1)/18 - 5*P*SingularityFunction(x, 0, 2)/36
        + 5*P*SingularityFunction(x, l, 2)/36)/(E*I), l >= x), ((P*l**2/18 - 4*P*l*SingularityFunction(-l +
        x, 2*l, 1)/9 - 5*P*SingularityFunction(-l + x, 0, 2)/36 + P*SingularityFunction(-l + x, l, 2)/2
        - 13*P*SingularityFunction(-l + x, 2*l, 2)/36)/(E*I), x < 3*l))
        >>> b.deflection()
        Piecewise(((5*P*l*SingularityFunction(x, 0, 2)/36 - 5*P*SingularityFunction(x, 0, 3)/108
        + 5*P*SingularityFunction(x, l, 3)/108)/(E*I), l >= x), ((5*P*l**3/54 + P*l**2*(-l + x)/18
        - 2*P*l*SingularityFunction(-l + x, 2*l, 2)/9 - 5*P*SingularityFunction(-l + x, 0, 3)/108
        + P*SingularityFunction(-l + x, l, 3)/6 - 13*P*SingularityFunction(-l + x, 2*l, 3)/108)/(E*I), x < 3*l))
        """
        x = self.variable
        l = self._hinge_position
        E = self._elastic_modulus
        I = self._second_moment

        if isinstance(I, Piecewise):
            I1 = I.args[0][0]
            I2 = I.args[1][0]
        else:
            I1 = I2 = I

        load_1 = 0       # Load equation on first segment of composite beam
        load_2 = 0       # Load equation on second segment of composite beam

        # Distributing load on both segments
        for load in self.applied_loads:
            if load[1] < l:
                load_1 += load[0]*SingularityFunction(x, load[1], load[2])
                if load[2] == 0:
                    load_1 -= load[0]*SingularityFunction(x, load[3], load[2])
                elif load[2] > 0:
                    load_1 -= load[0]*SingularityFunction(x, load[3], load[2]) + load[0]*SingularityFunction(x, load[3], 0)
            elif load[1] == l:
                load_1 += load[0]*SingularityFunction(x, load[1], load[2])
                load_2 += load[0]*SingularityFunction(x, load[1] - l, load[2])
            elif load[1] > l:
                load_2 += load[0]*SingularityFunction(x, load[1] - l, load[2])
                if load[2] == 0:
                    load_2 -= load[0]*SingularityFunction(x, load[3] - l, load[2])
                elif load[2] > 0:
                    load_2 -= load[0]*SingularityFunction(x, load[3] - l, load[2]) + load[0]*SingularityFunction(x, load[3] - l, 0)

        h = Symbol('h')     # Force due to hinge
        load_1 += h*SingularityFunction(x, l, -1)
        load_2 -= h*SingularityFunction(x, 0, -1)

        eq = []
        shear_1 = integrate(load_1, x)
        shear_curve_1 = limit(shear_1, x, l)
        eq.append(shear_curve_1)
        bending_1 = integrate(shear_1, x)
        moment_curve_1 = limit(bending_1, x, l)
        eq.append(moment_curve_1)

        shear_2 = integrate(load_2, x)
        shear_curve_2 = limit(shear_2, x, self.length - l)
        eq.append(shear_curve_2)
        bending_2 = integrate(shear_2, x)
        moment_curve_2 = limit(bending_2, x, self.length - l)
        eq.append(moment_curve_2)

        C1 = Symbol('C1')
        C2 = Symbol('C2')
        C3 = Symbol('C3')
        C4 = Symbol('C4')
        slope_1 = S(1)/(E*I1)*(integrate(bending_1, x) + C1)
        def_1 = S(1)/(E*I1)*(integrate((E*I)*slope_1, x) + C1*x + C2)
        slope_2 = S(1)/(E*I2)*(integrate(integrate(integrate(load_2, x), x), x) + C3)
        def_2 = S(1)/(E*I2)*(integrate((E*I)*slope_2, x) + C4)

        for position, value in self.bc_slope:
            if position<l:
                eq.append(slope_1.subs(x, position) - value)
            else:
                eq.append(slope_2.subs(x, position - l) - value)

        for position, value in self.bc_deflection:
            if position<l:
                eq.append(def_1.subs(x, position) - value)
            else:
                eq.append(def_2.subs(x, position - l) - value)

        eq.append(def_1.subs(x, l) - def_2.subs(x, 0)) # Deflection of both the segments at hinge would be equal

        constants = list(linsolve(eq, C1, C2, C3, C4, h, *reactions))
        reaction_values = list(constants[0])[5:]

        self._reaction_loads = dict(zip(reactions, reaction_values))
        self._load = self._load.subs(self._reaction_loads)

        # Substituting constants and reactional load and moments with their corresponding values
        slope_1 = slope_1.subs({C1: constants[0][0], h:constants[0][4]}).subs(self._reaction_loads)
        def_1 = def_1.subs({C1: constants[0][0], C2: constants[0][1], h:constants[0][4]}).subs(self._reaction_loads)
        slope_2 = slope_2.subs({x: x-l, C3: constants[0][2], h:constants[0][4]}).subs(self._reaction_loads)
        def_2 = def_2.subs({x: x-l,C3: constants[0][2], C4: constants[0][3], h:constants[0][4]}).subs(self._reaction_loads)

        self._hinge_beam_slope = Piecewise((slope_1, x<=l), (slope_2, x<self.length))
        self._hinge_beam_deflection = Piecewise((def_1, x<=l), (def_2, x<self.length))
예제 #11
0
    def intersection(self, o):
        """ The intersection with other geometrical entity.

        Parameters
        ==========

        Point, Point3D, LinearEntity, LinearEntity3D, Plane

        Returns
        =======

        List

        Examples
        ========

        >>> from sympy import Point, Point3D, Line, Line3D, Plane
        >>> a = Plane(Point3D(1, 2, 3), normal_vector=(1, 1, 1))
        >>> b = Point3D(1, 2, 3)
        >>> a.intersection(b)
        [Point3D(1, 2, 3)]
        >>> c = Line3D(Point3D(1, 4, 7), Point3D(2, 2, 2))
        >>> a.intersection(c)
        [Point3D(2, 2, 2)]
        >>> d = Plane(Point3D(6, 0, 0), normal_vector=(2, -5, 3))
        >>> e = Plane(Point3D(2, 0, 0), normal_vector=(3, 4, -3))
        >>> d.intersection(e)
        [Line3D(Point3D(78/23, -24/23, 0), Point3D(147/23, 321/23, 23))]

        """
        from sympy.geometry.line import LinearEntity, LinearEntity3D
        if not isinstance(o, GeometryEntity):
            o = Point(o, dim=3)
        if isinstance(o, Point):
            if o in self:
                return [o]
            else:
                return []
        if isinstance(o, (LinearEntity, LinearEntity3D)):
            if o in self:
                p1, p2 = o.p1, o.p2
                if isinstance(o, Segment):
                    o = Segment3D(p1, p2)
                elif isinstance(o, Ray):
                    o = Ray3D(p1, p2)
                elif isinstance(o, Line):
                    o = Line3D(p1, p2)
                else:
                    raise ValueError('unhandled linear entity: %s' % o.func)
                return [o]
            else:
                x, y, z = map(Dummy, 'xyz')
                t = Dummy()  # unnamed else it may clash with a symbol in o
                a = Point3D(o.arbitrary_point(t))
                b = self.equation(x, y, z)

                # TODO: Replace solve with solveset, when this line is tested
                c = solve(b.subs(list(zip((x, y, z), a.args))), t)
                if not c:
                    return []
                else:
                    p = a.subs(t, c[0])
                    if p not in self:
                        return []  # e.g. a segment might not intersect a plane
                    return [p]
        if isinstance(o, Plane):
            if self.equals(o):
                return [self]
            if self.is_parallel(o):
                return []
            else:
                x, y, z = map(Dummy, 'xyz')
                a, b = Matrix([self.normal_vector]), Matrix([o.normal_vector])
                c = list(a.cross(b))
                d = self.equation(x, y, z)
                e = o.equation(x, y, z)
                result = list(linsolve([d, e], x, y, z))[0]
                for i in (x, y, z): result = result.subs(i, 0)
                return [Line3D(Point3D(result), direction_ratio=c)]
    def solve_slope_deflection(self):
        """
        Solves the differnetial equation of buckling to determine the
        deflection and slope equations.

        Examples
        ========

        A column of timber section is 8m long both ends being fixed.
        Young's modulus of the timber is E and second-moment I.
        The applied load on the column is 360KN.

        >>> from sympy.physics.continuum_mechanics.column import Column
        >>> from sympy import Symbol, symbols
        >>> E, I, P = symbols('E, I, P', positive=True)
        >>> c = Column(8, E, I, 360000, top="fixed", bottom="fixed")
        >>> c.end_conditions
        {'bottom': 'fixed', 'top': 'fixed'}
        >>> c.boundary_conditions
        {'deflection': [(0, 0), (8, 0)], 'slope': [(0, 0)]}
        >>> c.moment()
        -M + 360000*y(x)
        >>> c.solve_slope_deflection()
        >>> c.deflection()
        -M*cos(600*x/(sqrt(E)*sqrt(I)))/360000 + M/360000
        >>> c.slope()
        M*sin(600*x/(sqrt(E)*sqrt(I)))/(600*sqrt(E)*sqrt(I))
        """
        y = Function('y')
        x = self._variable
        P = Symbol('P', positive=True)

        C1, C2 = symbols('C1, C2')
        E = self._elastic_modulus
        I = self._second_moment

        # differnetial equation of Column buckling
        eq = E * I * y(x).diff(x, 2) + self._moment

        defl_sol = dsolve(Eq(eq, 0), y(x)).args[1]
        slope_sol = defl_sol.diff(x)

        constants = list(
            linsolve([defl_sol.subs(x, 0),
                      slope_sol.subs(x, 0)], C1, C2).args[0])

        self._deflection = defl_sol.subs({C1: constants[0], C2: constants[1]})
        self._slope = slope_sol.subs({C1: constants[0], C2: constants[1]})

        # if deflection is zero, no buckling occurs, which is not the case,
        # so trying to solve for the constants differently
        if self._deflection == 0:
            self._deflection = defl_sol
            self._slope = slope_sol

            defl_eqs = []
            # taking last two bounndary conditions which are actually
            # the initial boundary conditions.
            for point, value in self._boundary_conditions['deflection'][-2:]:
                defl_eqs.append(self._deflection.subs(x, point) - value)

            # solve for C1, C2 along with P
            solns = solve(defl_eqs, (P, C1, C2), dict=True)
            for sol in solns:
                if self._deflection.subs(sol) == 0:
                    # removing trivial solutions
                    solns.remove(sol)

            # checking if the constants are solved, and subtituting them in
            # the deflection and slope equation
            if C1 in solns[0].keys():
                self._deflection = self._deflection.subs(C1, solns[0][C1])
                self._slope = self._slope.subs(C1, solns[0][C1])
            if C2 in solns[0].keys():
                self._deflection = self._deflection.subs(C2, solns[0][C2])
                self._slope = self._slope.subs(C2, solns[0][C2])
            if P in solns[0].keys():
                self._critical_load = solns[0][P]
예제 #13
0
    def intersection(self, o):
        """ The intersection with other geometrical entity.

        Parameters
        ==========

        Point, Point3D, LinearEntity, LinearEntity3D, Plane

        Returns
        =======

        List

        Examples
        ========

        >>> from sympy import Point, Point3D, Line, Line3D, Plane
        >>> a = Plane(Point3D(1, 2, 3), normal_vector=(1, 1, 1))
        >>> b = Point3D(1, 2, 3)
        >>> a.intersection(b)
        [Point3D(1, 2, 3)]
        >>> c = Line3D(Point3D(1, 4, 7), Point3D(2, 2, 2))
        >>> a.intersection(c)
        [Point3D(2, 2, 2)]
        >>> d = Plane(Point3D(6, 0, 0), normal_vector=(2, -5, 3))
        >>> e = Plane(Point3D(2, 0, 0), normal_vector=(3, 4, -3))
        >>> d.intersection(e)
        [Line3D(Point3D(78/23, -24/23, 0), Point3D(147/23, 321/23, 23))]

        """
        from sympy.geometry.line import LinearEntity, LinearEntity3D

        if not isinstance(o, GeometryEntity):
            o = Point(o, dim=3)
        if isinstance(o, Point):
            if o in self:
                return [o]
            else:
                return []
        if isinstance(o, (LinearEntity, LinearEntity3D)):
            # recast to 3D
            p1, p2 = o.p1, o.p2
            if isinstance(o, Segment):
                o = Segment3D(p1, p2)
            elif isinstance(o, Ray):
                o = Ray3D(p1, p2)
            elif isinstance(o, Line):
                o = Line3D(p1, p2)
            else:
                raise ValueError("unhandled linear entity: %s" % o.func)
            if o in self:
                return [o]
            else:
                t = Dummy()  # unnamed else it may clash with a symbol in o
                a = Point3D(o.arbitrary_point(t))
                p1, n = self.p1, Point3D(self.normal_vector)

                # TODO: Replace solve with solveset, when this line is tested
                c = solve((a - p1).dot(n), t)
                if not c:
                    return []
                else:
                    c = [i for i in c if i.is_real is not False]
                    if len(c) > 1:
                        c = [i for i in c if i.is_real]
                    if len(c) != 1:
                        raise Undecidable("not sure which point is real")
                    p = a.subs(t, c[0])
                    if p not in o:
                        return []  # e.g. a segment might not intersect a plane
                    return [p]
        if isinstance(o, Plane):
            if self.equals(o):
                return [self]
            if self.is_parallel(o):
                return []
            else:
                x, y, z = map(Dummy, "xyz")
                a, b = Matrix([self.normal_vector]), Matrix([o.normal_vector])
                c = list(a.cross(b))
                d = self.equation(x, y, z)
                e = o.equation(x, y, z)
                result = list(linsolve([d, e], x, y, z))[0]
                for i in (x, y, z):
                    result = result.subs(i, 0)
                return [Line3D(Point3D(result), direction_ratio=c)]
예제 #14
0
def b(i):
    i = i + 1
    return integrate(b_intern, 0, 1, i)


M = zeros(n, n + 1)
for i in range(0, n):
    M[i, n] = b(i)
    M[i, i] = m(i, i)
    if (i - 1) >= 0:
        M[i, i - 1] = m(i, i - 1)
    if (i + 1) < n:
        M[i, i + 1] = m(i, i + 1)
coeficients = symbols('a_0:{}'.format(n))
solution, = linsolve(M, coeficients)


def function(solution, x):
    value = 0
    i = 0
    for c in solution:
        value += c * fi(i + 1, x)
        i = i + 1
    return value


def function_original(x):
    return ((x - 1) * (e**(-x) - 1))

예제 #15
0
def poly_solve(eqns_list, unknowns):
    """
    Description
    -----------

    Custom solver for linear system of symbolic equations.
    As  Sympy  solve()  function gets pretty slow on not that big systems (~10
    equations  and  10  unknowns  containing  symbolic variables), this solver
    might be faster for big systems.

    The  most  important  feature  is that it is possible to keep track of the
    solving  process (printed on the console), so the user can have an idea of
    the remaining time.

    This solver might however be slower if there are no symbolic variables.

    Parameters
    ----------

    eqns_list : list of Sympy expressions
        List of expressions (considered equal to 0)
    unknowns : sympy symbol list
        Variables to solve for

    Returns
    -------

    solution : dict
        Dictionary containing solutions

    """

    eqns = eqns_list.copy()

    # Choosing solver
    nb_sym = 0
    for eq in eqns:
        fs = eq.free_symbols
        fs.difference_update(unknowns)
        if len(fs) > 0:
            nb_sym += 1
    custom_solver = (nb_sym > 0)

    if custom_solver:
        # System solutions
        sol = {}
        solr = {xi: 0 for xi in unknowns}

        # Found solutions
        found_vars = []

        for w, eqn in enumerate(eqns):
            print("Trajectory generation - Finding solution: " +
                  ("%.0f" % (100 * w / len(eqns))) + " %")
            variable = 0
            for var in unknowns:
                if var in eqn.free_symbols and var not in found_vars:
                    variable = var
                    break
            if variable == 0:
                continue
            sol[variable] = list(linsolve([eqn], [variable]))[0][0]
            solr[variable] = sol[variable]
            for i, eq in enumerate(eqns):
                eqns[i] = eq.subs(sol).simplify(rational=False)
            found_vars.append(variable)

        # Simplifying solution
        # dct = [[len(solr[a].free_symbols) for a in solr],
        #        [a for a in solr]]
        dct = []
        for a in solr:
            try:
                sym_len = len(solr[a].free_symbols)
            except AttributeError:
                sym_len = 0
            dct.append([sym_len, a])
        # dct = list(map(list, zip(*dct)))
        dct.sort(key=lambda x: x[0])
        for j, s in enumerate(dct):
            print("Trajectory generation - Simplifying solution: " + "%.0f" %
                  (100 * j / len(dct)) + " %")
            for i, sol_i in enumerate(solr):
                try:
                    solr[sol_i] = solr[sol_i].subs(s[1], solr[s[1]]) \
                        .simplify(rational=False).factor().cancel() \
                        .nsimplify(tolerance=1e-10).evalf()
                except AttributeError:
                    pass
        print("Done.")
        return solr
    else:
        return solve(eqns, unknowns)
예제 #16
0
from sympy import symbols, Matrix
from sympy.solvers import linsolve

l, C, D = symbols('l C D')

A = Matrix([[2, 3 * l, 4 * l**2, C], [1, 2 * l, 3 * l**2, C / 2],
            [8, 18 * l, 144 / 5 * l**2, D]])

a2, a3, a4 = symbols("a2 a3 a4")
sol, = linsolve(A, [a2, a3, a4])

print(sol)