def test_reftime(self):
t = time.time()
f = TimeFilter(rules={"days": 1}, reftime=t)
assert f.reftime == t
time.sleep(SHORTTIME)
f = TimeFilter(rules={"days": 1})
assert f.reftime > t
def test_multicat_rules_yield_union_of_singlecat_rules(self):
N = 10
MAXCOUNT = 16
def rndcount(): return randint(1, MAXCOUNT)
for _ in range(N):
rules = {
"years": rndcount(),
"months": rndcount(),
"weeks": rndcount(),
"days": rndcount(),
"hours": rndcount(),
"recent": rndcount()
}
single_results = set()
for category, timecount in rules.iteritems():
single_rule = dict.fromkeys(rules, 0)
single_rule[category] = timecount
a, _ = TimeFilter(single_rule, self.now).filter(self.fses)
assert len(a) == timecount
single_results.update(a)
multi_result, _ = TimeFilter(rules, self.now).filter(self.fses)
assert len(multi_result) == len(single_results)
assert set(multi_result) == single_results
def test_periodic_filtering_is_stable(self):
start = datetime(2016, 1, 1, 23, 0)
items = []
# create items every 57 minutes, old enough, so they don't fall in the
# 'recent' category. Choose the times so that they initially fall into
# separate buckets when the timefilter is run at start.
previous = start - timedelta(hours=3, minutes=20)
for _ in range(3):
items.append(FilterItem(moddate=previous))
previous = previous - timedelta(minutes=57)
rules = { "hours": 50 } # within the test period, everything should be
# retained.
# check precondition: when filtered at start, each item falls ito a
# separate bucket -- in other words, items is what could have been left
# by the 50-hours rule run at start time, even though the individual
# items are less than 60 minutes apart.
a, _ = TimeFilter(rules, start).filter(items)
assert len(a) == len(items)
# check stability: given that the oldest item is far from being dropped
# (way newer than 50 hours), every run within the following hour should
# leave what was left by the first run.
current = start
for _ in range(60):
a, _ = TimeFilter(rules, current).filter(items)
assert len(a) == len(items)
current = current + timedelta(minutes=1)
def test_requesting_less_than_available_retrieves_most_recent(self):
for category, fses in self.fses10.iteritems():
f = TimeFilter({category: 5}, self.reftime)
a, r = f.filter(fses)
assert len(a) == 5
assert len(r) == 5
def moddates(fses): return map(lambda fse: fse.moddate, fses)
assert min(moddates(a)) > max(moddates(r))
def test_requesting_one_retrieves_most_recent(self):
for category, fses in self.fses10.iteritems():
f = TimeFilter({category: 1}, self.reftime)
a, r = f.filter(fses)
assert len(a) == 1
def moddates(fses): return map(lambda fse: fse.moddate, fses)
assert a[0].moddate == max(moddates(fses))
assert len(r) == 9
assert a[0] not in r
def test_hours_one_accepted_one_rejected(self):
f = TimeFilter(rules={"hours": 1})
fse1 = FilterItem(modtime=time.time()-60*60*1.5)
fse2 = FilterItem(modtime=time.time()-60*60*1.6)
a, r = f.filter(objs=[fse1, fse2])
r = list(r)
# The younger one must be accepted.
assert a[0] == fse1
assert len(a) == 1
assert r[0] == fse2
assert len(r) == 1
def test_minimal_functionality_and_types(self):
# Create filter with reftime self.reftime
f = TimeFilter(rules={"hours": 1}, reftime=self.reftime)
# Create mock that is 1.5 hours old. Must end up in accepted list,
# since it's 1 hour old and one item should be kept from the 1-hour-
# old-category
fse = FilterItem(moddate=self.reftime-timedelta(hours=1.5))
a, r = f.filter([fse])
# http://stackoverflow.com/a/1952655/145400
assert isinstance(a, collections.Iterable)
assert isinstance(r, collections.Iterable)
assert a[0] == fse
assert len(r) == 0
def test_minimal_functionality_and_types(self):
# Create filter with reftime NOW (if not specified otherwise)
# and simple rules.
f = TimeFilter(rules={"hours": 1})
# Create mock that is 1.5 hours old. Must end up in accepted list,
# since it's 1 hour old and one item should be kept from the 1-hour-
# old-category
fse = FilterItem(modtime=time.time()-60*60*1.5)
a, r = f.filter(objs=[fse])
# http://stackoverflow.com/a/1952655/145400
assert isinstance(a, collections.Iterable)
assert isinstance(r, collections.Iterable)
assert a[0] == fse
# Rejected list `r` is expected to be an interator, so convert to
# list before evaluating length.
assert len(list(r)) == 0
def test_request_less_than_available_distant(self):
# only distant items are present (at the beginning of the rule period)
fses = [self.yearsago[10], self.yearsago[9]]
rules = {"years": 10}
a, r = TimeFilter(rules, self.reftime).filter(fses)
assert set(a) == set(fses)
assert len(r) == 0
def test_10_days_2_weeks(self):
# Further define category 'overlap' behavior. {"days": 10, "weeks": 2}
# -> week 0 is included in the 10 days, week 1 is only partially
# included in the 10 days, and week 2 (14 days and older) is not
# included in the 10 days.
# Having 15 FSEs, 1 to 15 days in age, the first 10 of them must be
# accepted according to the 10-day-rule. According to the 2-weeks-rule,
# the 7th and 14th FSEs must be accepted. The 7th FSE is included in
# the first 10, so items 1-10 and 14 are the accepted ones.
now = datetime(2016, 1, 3)
nowminusXdays = (now - timedelta(days=i)
for i in range(1, 16))
fses = [FilterItem(moddate=d) for d in nowminusXdays]
rules = {"days": 10, "weeks": 2}
a, r = TimeFilter(rules, now).filter(fses)
r = list(r)
assert len(a) == 11
# Check if first 11 fses are in accepted list (order can be predicted
# according to current implementation, but should not be tested, as it
# is not guaranteed according to the current specification).
for fse in fses[:10]:
assert fse in a
# Check if 14th FSE is accepted.
assert fses[13] in a
# Check if FSEs 12, 13, 15 are rejected.
assert len(r) == 4
for i in (10, 11, 12, 14):
assert fses[i] in r
def main():
t0 = time.time()
now = datetime.now()
fses = list(fsegen(ref=now, N_per_cat=5 * 10**4, max_timecount=9))
shuffle(fses)
nbr_fses = len(fses)
n = 8
rules = {
"years": n,
"months": n,
"weeks": n,
"days": n,
"hours": n,
"recent": n
}
sduration = time.time() - t0
log.info("Setup duration: %.3f s", sduration)
log.info("Profiling...")
pr = cProfile.Profile()
pr.enable()
a, r = TimeFilter(rules, now).filter(fses)
pr.disable()
s = StringIO.StringIO()
ps = pstats.Stats(pr, stream=s).sort_stats('time')
ps.print_stats(20)
print s.getvalue()
def test_request_less_than_available_close(self):
# only close items are present (at the end of the rule period)
fses = [self.yearsago[1], self.yearsago[2]]
rules = {"years": 10}
a, r = TimeFilter(rules, self.reftime).filter(fses)
assert set(a) == set(fses)
assert len(r) == 0
def test_10_days_2_weeks(self):
# Further define category 'overlap' behavior. {"days": 10, "weeks": 2}
# -> week 0 is included in the 10 days, week 1 is only partially
# included in the 10 days, and week 2 (14 days and older) is not
# included in the 10 days.
# Having 15 FSEs, 1 to 15 days in age, the first 10 of them must be
# accepted according to the 10-day-rule. The 11th, 12th, 13th FSE (11,
# 12, 13 days old) are categorized as 1 week old (their age A fulfills
# 7 days <= A < 14 days). According to the 2-weeks-rule, the most
# recent 1-week-old not affected by younger categories has to be
# accepted, which is the 11th FSE. Also according to the 2-weeks-rule,
# the most recent 2-week-old (not affected by a younger category, this
# is always condition) has to be accepted, which is the 14th FSE.
# In total FSEs 1-11,14 must be accepted, i.e. 12 FSEs. 15 FSEs are
# used as input (1-15 days old), i.e. 3 are to be rejected (FSEs 12,
# 13, 15).
now = time.time()
nowminusXdays = (now-(60*60*24*i+1) for i in range(1, 16))
fses = [FilterItem(modtime=t) for t in nowminusXdays]
rules = {"days": 10, "weeks": 2}
a, r = TimeFilter(rules, now).filter(fses)
r = list(r)
assert len(a) == 12
# Check if first 11 fses are in accepted list (order can be predicted
# according to current implementation, but should not be tested, as it
# is not guaranteed according to the current specification).
for fse in fses[:11]:
assert fse in a
# Check if 14th FSE is accepted.
assert fses[13] in a
# Check if FSEs 12, 13, 15 are rejected.
assert len(r) == 3
for i in (11, 12, 14):
assert fses[i] in r
def test_1_recent_1_years(self):
rules = {
"years": 1,
"recent": 1
}
a, _ = TimeFilter(rules, self.now).filter(self.fses)
assert len(a) == 2
def test_10_days_order(self):
# Having 15 FSEs, 1 to 15 days in age, the first 10 of them must be
# accepted according to the 10-day-rule. The last 5 must be rejected.
# This test is focused on the right internal ordering when making the
# decision to accept or reject an item. The newest ones are expected to
# be accepted, while the oldest ones are expected to be rejected.
# In order to test robustness against input order, the list of mock
# FSEs is shuffled before filtering. The filtering and checks are
# repeated a couple of times.
# It is tested whether all of the youngest 10 FSEs are accepted. It is
# not tested if these 10 FSEs have a certain order within the accepted-
# list, because we don't make any guarantees about the
# accepted-internal ordering.
now = time.time()
nowminusXdays = (now-(60*60*24*i+1) for i in range(1, 16))
fses = [FilterItem(modtime=t) for t in nowminusXdays]
rules = {"days": 10}
shuffledfses = fses[:]
for _ in range(100):
shuffle(shuffledfses)
a, r = TimeFilter(rules, now).filter(shuffledfses)
r = list(r)
assert len(a) == 10
assert len(r) == 5
for fse in fses[:10]:
assert fse in a
for fse in fses[10:]:
assert fse in r
def test_requesting_newer_than_available_retrieves_none(self):
# excluding the "recent" category which will always accept the newest N
# items.
categories = ("hours", "days", "weeks", "months", "years")
# generate items 6-10 per category, in reverse order to increase
# the chance of discovering order dependencies in the filter.
fses10to6 = {cat : sorted(self.fses10[cat],
key=lambda x: x.moddate,
reverse=True)[5:]
for cat in categories}
# now ask for the first 5 items of each category.
for category, fses in fses10to6.iteritems():
f = TimeFilter({category: 5}, self.reftime)
a, r = f.filter(fses)
assert len(a) == 0
assert set(r) == set(fses)
def test_1_recent_1_years(self):
rules = {
"years": 1,
"recent": 1
}
a, r = TimeFilter(rules, self.now).filter(self.fses9)
assert len(a) == 2
assert len(list(r)) == self.N*6 - 2
def test_create_recent_allow_old(self):
now = time.time()
nowminusXseconds = (now - (i + 1) for i in range(1, 16))
fses = [FilterItem(modtime=t) for t in nowminusXseconds]
rules = {"years": 1}
a, r = TimeFilter(rules, now).filter(fses)
r = list(r)
assert len(a) == 0
assert len(r) == 15
def test_create_recent_dont_request_recent(self):
# Create a few young items (recent ones). Then don't request any.
now = time.time()
nowminusXseconds = (now - (i + 1) for i in range(1, 16))
fses = [FilterItem(modtime=t) for t in nowminusXseconds]
rules = {"years": 1, "recent": 0}
a, r = TimeFilter(rules, now).filter(fses)
r = list(r)
assert len(a) == 0
assert len(r) == 15
def test_overlapping_rules_dont_accept_additional_items(self):
# check first rule: 24 hours, overlapping one day
rules = { "hours": 24 }
ref_time = datetime(2016, 1, 1)
moddates = (ref_time - timedelta(hours=i)
for i in range(1, 29))
items = [FilterItem(moddate=d) for d in moddates]
a, _ = TimeFilter(rules, ref_time).filter(items)
# expect the first 24 items to be accepted
assert len(a) == 24
assert set(a) == set(items[:24])
# combine with an overlapping "days1" rule
rules = { "hours": 24, "days": 1 }
a, _ = TimeFilter(rules, ref_time).filter(items)
# the result shouldn't change: the most recent 1-day old item is
# the same as the most recent 24-hour old item
assert len(a) == 24
assert set(a) == set(items[:24])
def test_requesting_newer_categories_than_available_retrieves_none(self):
categories = ("years", "months", "weeks", "days", "hours", "recent")
fses = [self.fses4[cat] for cat in categories]
for n in range(1, len(categories)):
older_fses = list(chain.from_iterable(islice(fses, n)))
rules = {categories[n]: 4}
a, r = TimeFilter(rules, self.reftime).filter(older_fses)
assert len(a) == 0
assert set(r) == set(older_fses)
def test_create_old_allow_recent(self):
# Create a few old items, between 1 and 15 years. Then only request one
# recent item. This discovered a mean bug, where items to be rejected
# ended up in the recent category.
now = time.time()
nowminusXyears = (now-(60*60*24*365 * i + 1) for i in range(1, 16))
fses = [FilterItem(modtime=t) for t in nowminusXyears]
rules = {"recent": 1}
a, r = TimeFilter(rules, now).filter(fses)
r = list(r)
assert len(a) == 0
assert len(r) == 15
def test_2_years_2_allowed(self):
# Request to keep more than available.
# Produce one 1 year old, one 2 year old, keep 10 years.
nowminus10years = time.time() - (60*60*24*365 * 2 + 1)
nowminus09years = time.time() - (60*60*24*365 * 1 + 1)
fse1 = FilterItem(modtime=nowminus10years)
fse2 = FilterItem(modtime=nowminus09years)
a, r = TimeFilter(rules={"years": 2}).filter(objs=[fse1, fse2])
r = list(r)
# All should be accepted.
assert len(a) == 2
assert len(r) == 0
def test_singlecat_rules(self):
n = 8
ryears = {"years": n}
rmonths = {"months": n}
rweeks = {"weeks": n}
rdays = {"days": n}
rhours = {"hours": n}
rrecent = {"recent": n}
# Run single-category filter on these fses.
for rules in (ryears, rmonths, rweeks, rdays, rhours, rrecent):
a, r = TimeFilter(rules, self.now).filter(self.fses)
assert len(a) == n
assert len(list(r)) == len(self.fses) - n
def test_realistic_scheme(self):
rules = {
"years": 4,
"months": 11,
"weeks": 6,
"days": 10,
"hours": 48,
"recent": 5
}
a, _ = TimeFilter(rules, self.now).filter(self.fses)
# 4+11+6+10+48+5 = 84; there is 1 reducing overlap between days and weeks
# and two more between hours and days -> 81 accepted items are expected.
assert len(a) == 81
def test_two_recent(self):
fse1 = FilterItem(modtime=time.time())
time.sleep(SHORTTIME)
fse2 = FilterItem(modtime=time.time())
# fse2 is a little younger than fse1.
time.sleep(SHORTTIME) # Make sure ref is newer than fse2.modtime.
a, r = TimeFilter(rules={"recent": 1}).filter(objs=[fse1, fse2])
r = list(r)
# The younger one must be accepted.
assert a[0] == fse2
assert len(a) == 1
assert r[0] == fse1
assert len(r) == 1
def test_fixed_rules_week_month_overlap(self):
n = 8
rules = {
"years": n,
"months": n,
"weeks": n,
"days": n,
"hours": n,
"recent": n
}
# See test_random_times_mass_singlecat_rules for likelihood discussion.
# The rules say that we want 8 items accepted of each time category.
# There are two time categories with a 'reducing overlap' in this case:
# weeks and months. All other category pairs do not overlap at all or
# overlap without reduction. Explanation/specification:
# 8 hours:
# 'Younger' categories can steal from older ones. The 'recent'
# cat cannot steal anything:
# -> 8 items expected for the hours category.
# category. 8 hours have no overlap with days (8 hours are 0 days),
# so the hours category cannot steal from the days category
# -> 8 items expected for the days category.
# 8 days:
# day 7 and 8 could be categorized as 1 week, but become categorized
# within the days dict (7 and 8 days are requested per days-rule).
# Non-reducing overlap: 9 to 13 days are categorized as 1 week, which
# is requested, and 9-day-old items actually are in the data set.
# They are not stolen by younger categories (than week) and end up
# in the 1-week-list.
# -> 8 items expected from the weeks category.
# 8 weeks:
# 1-month-olds are all stolen by the 8-weeks-rule.
# Items of age 8 weeks, i.e. 8*7 days = 56 days could be categorized
# as 1 month, but become categorized within the weeks dictionary
# (8 weeks old, which is requested per weeks-rule).
# Reducing overlap: 9-week-old items in the data set, which are not
# requested per weeks-rule are 9*7 days = 63 days old, i.e. 2 months
# (2 months are 2*30 days = 60 days). These 2-month-old items are
# not affected by younger data sets (than months), so they end up in
# the 2-months-list.
# -> In other words: there is no 1-month-list, since items of these
# ages are *entirely* consumed by the weeks-rule. The oldest item
# classified as 8 weeks old is already 2 months old:
# 8.99~ weeks == 62.00~ days > 60 days == 2 months.
# -> the months-rule returns only 7 items (not 8, like the others)
# 8 months:
# no overlap with years (0 years for all requested months)
a, r = TimeFilter(rules, self.now).filter(self.fses9)
# 8 items for all categories except for months (7 items expected).
assert len(a) == 6*8-1
assert len(list(r)) == self.N*6 - (6*8-1)
def test_realistic_scheme(self):
rules = {
"years": 4,
"months": 12,
"weeks": 6,
"days": 10,
"hours": 48,
"recent": 5
}
a, r = TimeFilter(rules, self.now).filter(self.fses62)
# 4+12+6+10+48+5 = 85; there is 1 reducing overlap between hours and
# days -> 84 accepted items are expected.
assert len(a) == 84
assert len(list(r)) == self.N*6 - 84
def test_2_recent_10_allowed(self):
# Request to keep more than available.
fse1 = FilterItem(modtime=time.time())
time.sleep(SHORTTIME)
fse2 = FilterItem(modtime=time.time())
time.sleep(SHORTTIME)
a, r = TimeFilter(rules={"recent": 10}).filter(objs=[fse1, fse2])
r = list(r)
# All should be accepted. Within `recent` category,
# items must be sorted by modtime, with the newest element being the
# last element.
assert a[0] == fse1
assert a[1] == fse2
assert len(a) == 2
assert len(r) == 0
def test_10_days_overlap(self):
# Category 'overlap' must be possible (10 days > 1 week).
# Having 15 FSEs, 1 to 15 days in age, the first 10 of them must be
# accepted according to the 10-day-rule. The last 5 must be rejected.
now = time.time()
nowminusXdays = (now-(60*60*24*i+1) for i in range(1, 16))
fses = [FilterItem(modtime=t) for t in nowminusXdays]
rules = {"days": 10}
a, r = TimeFilter(rules, now).filter(fses)
r = list(r)
assert len(a) == 10
assert len(r) == 5
for fse in fses[:10]:
assert fse in a
for fse in fses[10:]:
assert fse in r
def test_invalid_object(self):
f = TimeFilter(rules={"days": 1})
with raises(AttributeError):
# AttributeError: 'NoneType' object has no attribute 'modtime'
f.filter([None])
def test_not_iterable(self):
f = TimeFilter(rules={"days": 1})
with raises(TypeError):
# TypeError: 'NoneType' object is not iterable
f.filter(None)
