def test_garage(self):
initial = [1, 2, 3, 0, 4]
final = [0, 3, 2, 1, 4]
steps, seq = garage(initial, final)
self.assertEqual(steps, 4)
self.assertListEqual(seq, [[0, 2, 3, 1, 4], [2, 0, 3, 1, 4],
[2, 3, 0, 1, 4], [0, 3, 2, 1, 4]])
def test_garage(self):
initial = [1, 2, 3, 0, 4]
final = [0, 3, 2, 1, 4]
steps, seq = garage(initial, final)
self.assertEqual(steps, 4)
self.assertListEqual(seq, [[0, 2, 3, 1, 4],
[2, 0, 3, 1, 4],
[2, 3, 0, 1, 4],
[0, 3, 2, 1, 4]])
of the parking lot and the final state. Each step we are only allowed to move a car out of its place and move it into the empty spot. The goal is to find out the least movement needed to rearrange the parking lot from the initial state to the final state. Say the initial state is an array: [1, 2, 3, 0, 4], where 1, 2, 3, 4 are different cars, and 0 is the empty spot. And the final state is [0, 3, 2, 1, 4]. We can swap 1 with 0 in the initial array to get [0, 2, 3, 1, 4] and so on. Each step swap with 0 only. Edit: Now also prints the sequence of changes in states. Output of this example :- initial= [1, 2, 3, 0, 4] final= [0, 3, 2, 1, 4] Steps = 4 Sequence : 0 2 3 1 4 2 0 3 1 4 2 3 0 1 4 0 3 2 1 4 """ from algorithms.arrays import garage initial = [1, 2, 3, 0, 4] final = [0, 3, 2, 1, 4] print(garage(initial, final))
