Exemplo n.º 1
0
def cooperation_matrix(interactions):
    """
    The cooperation matrix from a single round robin.

    Parameters
    ----------
    interactions : dictionary
        A dictionary of the form:

        e.g. for a round robin between Cooperator, Defector and Alternator
        with 2 turns per round:
        {
            (0, 0): [(C, C), (C, C)].
            (0, 1): [(C, D), (C, D)],
            (0, 2): [(C, C), (C, D)],
            (1, 1): [(D, D), (D, D)],
            (1, 2): [(D, C), (D, D)],
            (2, 2): [(C, C), (D, D)]
        }

        i.e. the key is a pair of player index numbers and the value, a list of
        plays. The list contains one pair per turn in the round robin.
        The dictionary contains one entry for each combination of players.

    nplayers : integer
        The number of players in the round robin

    Returns
    -------
    list
        The cooperation matrix (C) of the form:

            [
                [a, b, c],
                [d, e, f],
                [g, h, i],
            ]

        i.e. an n by n matrix where n is the number of players. Each row (i)
        and column (j) represents an individual player and the the value Cij
        is the number of times player i cooperated against opponent j.
    """
    nplayers = player_count(interactions)
    cooperation = [[0 for i in range(nplayers)] for j in range(nplayers)]
    for players, actions in interactions.items():
        p1_actions, p2_actions = zip(*actions)
        p1_cooperation = p1_actions.count(C)
        p2_cooperation = p2_actions.count(C)
        cooperation[players[0]][players[1]] = p1_cooperation
        if players[0] != players[1]:
            cooperation[players[1]][players[0]] = p2_cooperation
    return cooperation
Exemplo n.º 2
0
def cooperation_matrix(interactions):
    """
    The cooperation matrix from a single round robin.

    Parameters
    ----------
    interactions : dictionary
        A dictionary of the form:

        e.g. for a round robin between Cooperator, Defector and Alternator
        with 2 turns per round:
        {
            (0, 0): [(C, C), (C, C)].
            (0, 1): [(C, D), (C, D)],
            (0, 2): [(C, C), (C, D)],
            (1, 1): [(D, D), (D, D)],
            (1, 2): [(D, C), (D, D)],
            (2, 2): [(C, C), (D, D)]
        }

        i.e. the key is a pair of player index numbers and the value, a list of
        plays. The list contains one pair per turn in the round robin.
        The dictionary contains one entry for each combination of players.

    nplayers : integer
        The number of players in the round robin

    Returns
    -------
    list
        The cooperation matrix (C) of the form:

            [
                [a, b, c],
                [d, e, f],
                [g, h, i],
            ]

        i.e. an n by n matrix where n is the number of players. Each row (i)
        and column (j) represents an individual player and the the value Cij
        is the number of times player i cooperated against opponent j.
    """
    nplayers = player_count(interactions)
    cooperation = [[0 for i in range(nplayers)] for j in range(nplayers)]
    for players, actions in interactions.items():
        p1_actions, p2_actions = zip(*actions)
        p1_cooperation = p1_actions.count(C)
        p2_cooperation = p2_actions.count(C)
        cooperation[players[0]][players[1]] = p1_cooperation
        if players[0] != players[1]:
            cooperation[players[1]][players[0]] = p2_cooperation
    return cooperation
Exemplo n.º 3
0
 def test_player_count(self):
     nplayers = ap.player_count(self.interactions)
     self.assertEqual(nplayers, 3)
     nplayers = ap.player_count({"test": "test"})
     self.assertEqual(nplayers, 1)
Exemplo n.º 4
0
 def test_player_count(self):
     nplayers = ap.player_count(self.interactions)
     self.assertEqual(nplayers, 3)
     nplayers = ap.player_count({'test': 'test'})
     self.assertEqual(nplayers, 1)