def reconstitute_interface(args):
p,k,first,second,manual_input = [],999,True,True,False
# Gather up a list of n-pieces, with some moderately complex UI logic
# to help the user along
# Grammar: python main.py --reconstitute [piece 1] ... [piece n] [format]
if len(args) == 0:
while len(p) < k:
if len(args) == 0:
# The first time that we have information on k AND it's the user input
# ting manually, print the "$1 total pieces required, $2 to go" string
if len(p) > 0 and second:
k = (bitcoin.trial_and_error_decode(p[0]) / (256 ** 37)) % 256 - 147
print "%d total pieces required, %d to go" % (k, k-len(p))
second = False
if first: print "Enter the key parts:"
v = raw_input("> ")
manual_input = True
else: v = args.pop(0)
p.append(v)
if first and manual_input: first = False
# We have to do this at the end of the first round since the k
# parameter might actually be 1, in which case we should end the
# while loop after this immediately
k = (bitcoin.trial_and_error_decode(p[0]) / (256 ** 37)) % 256 - 147
# Too many pieces inputted, don't interpret an extra piece as the base
# parameter
while len(args) > 0 and get_format(args[0]) == -1: args.pop(0)
if len(args) == 0: args.append(raw_input(
"Please enter format: integer(10), hexadecimal(16) " + \
"or base58check wallet import format (58): "))
print bitcoin.reconstitute(p,get_format(args[0]))
def reconstitute_interface(args):
p, k, first, second, manual_input = [], 999, True, True, False
# Gather up a list of n-pieces, with some moderately complex UI logic
# to help the user along
# Grammar: python main.py --reconstitute [piece 1] ... [piece n] [format]
if len(args) == 0:
while len(p) < k:
if len(args) == 0:
# The first time that we have information on k AND it's the user input
# ting manually, print the "$1 total pieces required, $2 to go" string
if len(p) > 0 and second:
k = (bitcoin.trial_and_error_decode(p[0]) /
(256**37)) % 256 - 147
print "%d total pieces required, %d to go" % (k,
k - len(p))
second = False
if first: print "Enter the key parts:"
v = raw_input("> ")
manual_input = True
else:
v = args.pop(0)
p.append(v)
if first and manual_input: first = False
# We have to do this at the end of the first round since the k
# parameter might actually be 1, in which case we should end the
# while loop after this immediately
k = (bitcoin.trial_and_error_decode(p[0]) / (256**37)) % 256 - 147
# Too many pieces inputted, don't interpret an extra piece as the base
# parameter
while len(args) > 0 and get_format(args[0]) == -1:
args.pop(0)
if len(args) == 0: args.append(raw_input(
"Please enter format: integer(10), hexadecimal(16) " + \
"or base58check wallet import format (58): "))
print bitcoin.reconstitute(p, get_format(args[0]))
def split_interface(args):
# Splits a key
# Grammar: python main.py --split [privkey] [n] [k (1<=k<=n)]
if len(args) == 0:
args.append(bitcoin.trial_and_error_decode(raw_input(
"Enter private key (any format): ")))
if len(args) == 1:
args.append(raw_input(
"How many parts do you want to split your key into? (1-14): "))
if len(args) == 2:
args.append(raw_input(
"How many parts should be required to reconstitute your " + \
"key? (1-%d): " % int(args[1])))
v = bitcoin.split(args[0],int(args[2]),int(args[1]))
print "Write down the key parts:"
for i in v: print i
def split_interface(args):
# Splits a key
# Grammar: python main.py --split [privkey] [n] [k (1<=k<=n)]
if len(args) == 0:
args.append(
bitcoin.trial_and_error_decode(
raw_input("Enter private key (any format): ")))
if len(args) == 1:
args.append(
raw_input(
"How many parts do you want to split your key into? (1-14): "))
if len(args) == 2:
args.append(raw_input(
"How many parts should be required to reconstitute your " + \
"key? (1-%d): " % int(args[1])))
v = bitcoin.split(args[0], int(args[2]), int(args[1]))
print "Write down the key parts:"
for i in v:
print i
