def trending_concepts():
#first lets get out data from Keen
complist = connect.compList()
#print complist
keenOut = extractcompdata(complist)
for aggs in keenOut:
if aggs.has_key('aggtags'):
#turn to lower
for tags in aggs['aggtags']:
tags = tags.lower()
print len(keenOut)
print keenOut[0]['screen_names']
print keenOut[0]['aggtags']
comp_names =[]
hash_tags =[]
total = Counter()
compTotal = Counter()
for a in range(len(keenOut)):
if keenOut[a].has_key('aggtags'):
#access list and determine tweets with hashtags
total.update(keenOut[a]['aggtags'][b].lower() for b in range(len(keenOut[a]['aggtags'])))
#listof tuple of competitors and Collections
collectList=[]
# #loop through competitors and build counts
for comps in complist:
#create counter
temp = comps
print temp
temps = Counter()
for a in range(len(keenOut)):
if keenOut[a]['screen_names'] == comps and keenOut[a].has_key('aggtags'):
temps.update(element.lower() for element in keenOut[a]['aggtags'])
collectList.append(temps.most_common(5))
grandList = zip(complist,collectList)
#pprint.pprint (total.most_common(10))
#pprint.pprint( grandList)
return grandList
def competitors(): try: #get users time line competitors = connections.compList() outputList = [] print "we'll be searching and updating Keen IO with tweets from %s" % competitors for name in competitors: timeOutlist = usertimeline(name) if len(timeOutlist) > 0: outputList.append(timeOutlist) #tweetcounts(name,"User Timeline") print "FINAL - - - - -" print "count of List output %d" % len(outputList) #pprint.pprint (outputList) return outputList except Exception, e: print e
def trending_concepts_total(time_period):
#first lets get out data from Keen
complist = connect.compList()
#print complist
keenOut = extractcompdata_time(complist,time_period)
for aggs in keenOut:
if aggs.has_key('hashtags'):
#turn to lower
for tags in aggs['hashtags']:
tags = tags.lower()
print len(keenOut)
comp_names =[]
hash_tags =[]
total = Counter()
compTotal = Counter()
for a in range(len(keenOut)):
print keenOut[a]
if keenOut[a].has_key('hashtags'):
#access list and determine tweets with hashtags
total.update(keenOut[a]['hashtags'][b].lower() for b in range(len(keenOut[a]['hashtags'])))
return total.most_common(5)