Exemplo n.º 1
0
def DeuxOpt(route):
    l = len(route) - 1
    best_tuple = (0, 0)
    best = 2e-5  # to avoid floating errors
    for i in range(l - 1):
        pi = const.instance[route[i]]
        spi = const.instance[route[i + 1]]

        for j in range(i + 2, l - 1):
            pj = const.instance[route[j]]
            spj = const.instance[route[j + 1]]
            d = (utile.distance(pi, spi) + utile.distance(pj, spj)) - \
                utile.distance(pi, pj) - utile.distance(spi, spj)

            if d > best:
                best_tuple = (i, j)
                best = d
    if best_tuple[0] != best_tuple[1]:
        cand = route.copy()
        cand[best_tuple[0] +
             1], cand[best_tuple[1]] = cand[best_tuple[1]], cand[best_tuple[0]
                                                                 + 1]
        return cand
    else:
        return route
Exemplo n.º 2
0
def compute_savings(lam, mu, nu):
    savings = []
    for i in range(len(const.instance)-1):
        s = 0
        for j in range(i+1, len(const.instance)-1):
            if (i == j):
                savings.append([0, (i+1, j+1)])
            else:
                s = utile.distance(const.instance[i+1], const.instance[0]) + utile.distance(const.instance[j+1], const.instance[0]) - lam*utile.distance(const.instance[i+1], const.instance[j+1]) + mu*abs(
                    utile.distance(const.instance[i+1], const.instance[0]) - utile.distance(const.instance[j+1], const.instance[0])) + (nu*(const.demand[i+1] + const.demand[j+1])/const.meanDemand)
                if s >= 0:
                    savings.append([s, (i+1, j+1)])
    savings.sort()
    return savings
Exemplo n.º 3
0
def decross_route(route, inst):
    route.append(0)
    d = (utile.distance(inst[route[2]], inst[route[1]]) +
         utile.distance(inst[route[0]], inst[route[-2]]) -
         utile.distance(inst[route[0]], inst[route[2]]) -
         utile.distance(inst[route[-2]], inst[route[1]]))
    if d > 0:
        cand = route.copy()
        cand.remove(route[1])
        cand.insert(-1, route[1])
        cand.pop()
        return cand
    else:
        route.pop()
        return route
Exemplo n.º 4
0
def max_depth(inst):
    d = 0
    for i in inst:
        di = utile.distance(i, (0, 0))
        if di > d:
            d = di
    return d
Exemplo n.º 5
0
def decross_route(route):
    inst = const.instance
    route.append(0)
    d = (utile.distance(inst[route[2]], inst[route[1]]) +
         utile.distance(inst[route[0]], inst[route[-2]]) -
         utile.distance(inst[route[0]], inst[route[2]]) -
         utile.distance(inst[route[-2]], inst[route[1]]))
    if d > 0:  # There is an improvement
        cand = route.copy()
        cand.remove(route[1])
        cand.insert(-1, route[1])
        cand.pop()
        return cand
    else:
        route.pop()
        return route
Exemplo n.º 6
0
def cost_sol(routes, inst, mode):
    c = 0
    for r in routes:

        if mode == "Float":
            for i in range(len(r)-1):
                a = inst[r[i]]
                b = inst[r[i+1]]
            
                c += utile.distance(a, b)
            c += utile.distance(inst[r[len(r)-1]], inst[r[0]])

        elif mode == "Int":
            for i in range(len(r)-1):
                a = inst[r[i]]
                b = inst[r[i+1]]
                c += round(utile.distance(a, b))
            c += round(utile.distance(inst[r[len(r)-1]], inst[r[0]]))
    return c
Exemplo n.º 7
0
def compute_savings(inst, demand, lam, mu, nu):
    savings = []
    d_bar = mean_demand(demand)
    for i in range(len(inst) - 1):
        s = 0
        for j in range(i + 1, len(inst) - 1):
            if (i == j):
                savings.append([0, (i + 1, j + 1)])
            else:
                s = utile.distance(inst[i + 1], inst[0]) + utile.distance(
                    inst[j + 1], inst[0]) - lam * utile.distance(
                        inst[i + 1], inst[j + 1]) + mu * abs(
                            utile.distance(inst[i + 1], inst[0]) -
                            utile.distance(inst[j + 1], inst[0])) + (
                                nu * (demand[i + 1] + demand[j + 1]) / d_bar)
                if s >= 0:
                    savings.append([s, (i + 1, j + 1)])
    savings.sort()
    return savings
Exemplo n.º 8
0
def voisins(k):
    v = []
    for i in range(len(instance)):
        vi = []
        couples = []
        for j in range(len(instance)):
            if i != j:
                vi.append([utile.distance(instance[i], instance[j]), j])
        vi.sort()
        for l in vi:
            couples.append(l[1])
        v.append(couples[:k])
    return v
Exemplo n.º 9
0
def cost_sol(solution, mode):
    c = 0
    for r in solution:

        # Distances are floating numbers
        if mode == "Float":
            for i in range(len(r) - 1):
                a = const.instance[r[i]]
                b = const.instance[r[i + 1]]

                c += utile.distance(a, b)
            c += utile.distance(const.instance[r[len(r) - 1]],
                                const.instance[r[0]])

        # Distances are int
        elif mode == "Int":
            for i in range(len(r) - 1):
                a = const.instance[r[i]]
                b = const.instance[r[i + 1]]
                c += round(utile.distance(a, b))
            c += round(
                utile.distance(const.instance[r[len(r) - 1]],
                               const.instance[r[0]]))
    return c
Exemplo n.º 10
0
def saving(i, ri, j, rj, inst):
    ri.append(0)
    rj.append(0)
    s = utile.distance(inst[ri[i]], inst[ri[i+1]])
    s += utile.distance(inst[ri[i]], inst[ri[i-1]])
    s -= utile.distance(inst[ri[i+1]], inst[ri[i-1]])
    s += utile.distance(inst[rj[j]], inst[rj[j+1]])
    s -= utile.distance(inst[ri[i]], inst[rj[j]])
    s -= utile.distance(inst[ri[i]], inst[rj[j+1]])
    ri.pop()
    rj.pop()
    return s
Exemplo n.º 11
0
def depth(i, j):
    return max(utile.distance(i, (0, 0)), utile.distance(j, (0, 0)))
Exemplo n.º 12
0
def cost(i, j, p):
    return utile.distance(i, j) * (1 + 0.1 * p)
Exemplo n.º 13
0
def width(i, j, G):
    theta = m.acos(G[1] / utile.distance(G, (0, 0)))
    proj_i = (i[0] * m.sin(theta), i[1] * m.cos(theta))
    proj_j = (j[0] * m.sin(theta), j[1] * m.cos(theta))
    return abs(utile.distance(i, proj_i) - utile.distance(j, proj_j))