Exemplo n.º 1
0
def q_hull(points):
    n = len(points)
    if n == 1:
        return set(points)
    f_ind = 0
    for i, pt in enumerate(points):
        if pt.y < points[f_ind].y or\
            (pt.y == points[f_ind].y and pt.x < points[f_ind].x):
            f_ind = i
    swap(points, 0, f_ind)
    s_ind = 1
    for i in range(1, len(points)):
        if prim.right(points[0], points[s_ind], points[i]) or\
           (prim.collinear(points[0], points[s_ind], points[i]) and\
            (prim.dist2(points[0], points[s_ind]) <
                prim.dist2(points[0], points[i]))):
            s_ind = i
    swap(points, n - 1, s_ind)
    hull = q_hull_rec(points, 0, n - 1)
    for pt in hull:
        pt.hilight("blue")
    return hull
Exemplo n.º 2
0
def q_hull_rec(points, start, end):
    if end - start == 1:  # two points
        ret_val = set([points[end], points[start]])
    else:
        part1, part2 = partition(points, start, end)
        #hilights points in current recursive call
        hilight_rec_call(points, start, end, part1, part2)
        res1 = q_hull_rec(points, part1, part2)
        res2 = q_hull_rec(points, part2, end)
        ret_val = res1.union(res2)
    # treats degenerated case
    if len(ret_val) == 3:
        ret_val = list(ret_val)
        if prim.collinear(ret_val[0], ret_val[1], ret_val[2]):
            if prim.on_segment(ret_val[0], ret_val[1], ret_val[2]):
                ret_val = set([ret_val[0], ret_val[1]])
            elif prim.on_segment(ret_val[0], ret_val[2], ret_val[1]):
                ret_val = set([ret_val[0], ret_val[2]])
            else:
                ret_val = set([ret_val[1], ret_val[2]])
        else:
            ret_val = set(ret_val)
    return ret_val
Exemplo n.º 3
0
    def __merge(self, startIndex, midIndex, endIndex):
        leftCopy = self.pointList[startIndex:midIndex + 1]
        rightCopy = self.pointList[midIndex + 1:endIndex + 1]

        leftIndex = 0
        rightIndex = 0
        sortIndex = startIndex

        while leftIndex < len(leftCopy) and rightIndex < len(rightCopy):
            if not left_on(self.pointList[0], rightCopy[rightIndex],
                           leftCopy[leftIndex]):
                self.pointList[sortIndex] = leftCopy[leftIndex]
                leftIndex = leftIndex + 1
            elif collinear(self.pointList[0], leftCopy[leftIndex],
                           rightCopy[rightIndex]):
                if dist2(self.pointList[0], leftCopy[leftIndex]) < dist2(
                        self.pointList[0], rightCopy[rightIndex]):
                    self.pointList[sortIndex] = leftCopy[leftIndex]
                    leftIndex = leftIndex + 1
                else:
                    self.pointList[sortIndex] = rightCopy[rightIndex]
                    rightIndex = rightIndex + 1
            else:
                self.pointList[sortIndex] = rightCopy[rightIndex]
                rightIndex = rightIndex + 1

            sortIndex = sortIndex + 1

        while leftIndex < len(leftCopy):
            self.pointList[sortIndex] = leftCopy[leftIndex]
            leftIndex = leftIndex + 1
            sortIndex = sortIndex + 1

        while rightIndex < len(rightCopy):
            self.pointList[sortIndex] = rightCopy[rightIndex]
            rightIndex = rightIndex + 1
            sortIndex = sortIndex + 1
Exemplo n.º 4
0
def Quickhull(P):
    '''Recebe uma coleção de pontos P e devolve seu fecho convexo'''
    n = len(P)
    if n == 1:
        return [P[0]]

    # encontra primeiro ponto extremo
    k = 0
    for i in range(n):
        # desempata por x
        if P[i].y < P[k].y or (P[i].y == P[k].y and P[i].x < P[k].x):
            k = i
    P[0], P[k] = P[k], P[0]

    # encontra extremo consecutivo ao primeiro
    i = 1
    dist = 0
    for j in range(2, n):
        if right(P[0], P[i], P[j]):
            i = j
        # desempata pelo mais distante
        elif collinear(P[0], P[i],
                       P[j]) and dist2(P[0], P[i]) < dist2(P[0], P[j]):
            i = j
    P[n - 1], P[i] = P[i], P[n - 1]

    P[0].lineto(P[n - 1], 'cyan')
    control.thaw_update()
    control.update()
    control.freeze_update()
    control.sleep()
    quick = quickhull_rec(P, 0, n - 1, Point(P[0].x, P[0].y),
                          Point(P[n - 1].x, P[n - 1].y))
    for p in quick:
        p.hilight('yellow')
    return quick
Exemplo n.º 5
0
def collinear (a, b, c):
	"retorna verdadeiro se a, b, c sao colineares"
	ret = prim.collinear (a, b, c)
	#triang (a, b, c)
	return ret
Exemplo n.º 6
0
def collinear(a, b, c):
    "retorna verdadeiro se a, b, c sao colineares"
    ret = prim.collinear(a, b, c)
    #triang (a, b, c)
    return ret
Exemplo n.º 7
0
 def _succ_comp(self, seg, reference):
     return right(seg.init, seg.to, reference) or\
            collinear(seg.init, seg.to, reference)
Exemplo n.º 8
0
 def _pred_comp(self, seg, reference):
     return left(seg.init, seg.to, reference) or\
            collinear(seg.init, seg.to, reference)
Exemplo n.º 9
0
 def _del_comp(self, seg1, seg2, reference):
     return left(seg1.init, seg1.to, reference) or\
            (collinear(seg1.init, seg1.to, reference) and #if ties
             left(seg1.init, seg1.to, seg2.init)) # looks at starting point
Exemplo n.º 10
0
 def _ins_comp(self, seg1, seg2, reference):
     return left(seg1.init, seg1.to, reference) or\
            (collinear(seg1.init, seg1.to, reference) and #if ties
             left(seg1.init, seg1.to, seg2.to)) # looks at endpoint
Exemplo n.º 11
0
 def __collinearWrap(self, i, j, k):
     return collinear(self.pointList[i], self.pointList[j],
                      self.pointList[k])