def addNum(self, num):
"""
Adds a num into the data structure.
:type num: int
:rtype: void
"""
if len(self.left) > len(self.right):
if num > self.median:
heapq.heappush(self.right, num)
else:
heapq.heappush(self.right, -heapq.heappop(self.left))
heapq.heappush(self.left, -num)
self.median = (-self.left[0] + self.right[0]) / 2.0
elif len(self.left) == len(self.right):
if num > self.median:
heapq.heappush(self.right, num)
self.median = self.right[0]
else:
heapq.heappush(self.left, -num)
self.median = -self.left[0]
else:
if num < self.median:
heapq.heappush(self.left, -num)
else:
heapq.heappush(self.left, -heapq.heappop(self.right))
heapq.heappush(self.right, num)
self.median = (-self.left[0] + self.right[0]) / 2.0
def _get_server(self):
"""
Get server to use for request.
Also process inactive server list, re-add them after given interval.
"""
with self._lock:
inactive_server_count = len(self._inactive_servers)
for i in range(inactive_server_count):
try:
ts, server, message = heapq.heappop(self._inactive_servers)
except IndexError:
pass
else:
if (ts + self.retry_interval) > time():
# Not yet, put it back
heapq.heappush(self._inactive_servers,
(ts, server, message))
else:
self._active_servers.append(server)
logger.warn("Restored server %s into active pool",
server)
# if none is old enough, use oldest
if not self._active_servers:
ts, server, message = heapq.heappop(self._inactive_servers)
self._active_servers.append(server)
logger.info("Restored server %s into active pool", server)
server = self._active_servers[0]
self._roundrobin()
return server
def _vsids_calculate(self):
"""
VSIDS Heuristic Calculation
Examples
========
>>> from sympy.logic.algorithms.dpll2 import SATSolver
>>> l = SATSolver([set([2, -3]), set([1]), set([3, -3]), set([2, -2]),
... set([3, -2])], set([1, 2, 3]), set([]))
>>> l.lit_heap
[(-2.0, -3), (-2.0, 2), (-2.0, -2), (0.0, 1), (-2.0, 3), (0.0, -1)]
>>> l._vsids_calculate()
-3
>>> l.lit_heap
[(-2.0, -2), (-2.0, 2), (0.0, -1), (0.0, 1), (-2.0, 3)]
"""
if len(self.lit_heap) == 0:
return 0
# Clean out the front of the heap as long the variables are set
while self.variable_set[abs(self.lit_heap[0][1])]:
heappop(self.lit_heap)
if len(self.lit_heap) == 0:
return 0
return heappop(self.lit_heap)[1]
def huff_encode(text):
freq = defaultdict(int)
for s in text:
freq[s] += 1
tree = [ [f, [s, ""]] for s,f in freq.items() ]
heapify(tree)
while len(tree) > 1:
l = heappop(tree)
h = heappop(tree)
for n in l[1:]:
n[1] = '0' + n[1]
for n in h[1:]:
n[1] = '1' + n[1]
heappush(tree, [l[0] + h[0]] + l[1:] + h[1:])
root = heappop(tree)[1:]
codes = dict([(s, "0b"+c) for s,c in root])
# Header
enc = BitArray()
for s,c in root:
enc += BitArray(bytes=s)
enc += BitArray(uint=len(c), length=8)
enc += BitArray("0b"+c)
enc.prepend(BitArray(uint=len(root), length=8))
for s in text:
enc += BitArray(codes[s])
return enc
def create_binary_tree(self):
"""
Create a binary Huffman tree using stored vocabulary word counts. Frequent words
will have shorter binary codes. Called internally from `build_vocab()`.
"""
logger.info("constructing a huffman tree from %i words" % len(self.vocab))
# build the huffman tree
heap = self.vocab.values()
heapq.heapify(heap)
for i in xrange(len(self.vocab) - 1):
min1, min2 = heapq.heappop(heap), heapq.heappop(heap)
heapq.heappush(heap, Vocab(count=min1.count + min2.count, index=i + len(self.vocab), left=min1, right=min2))
# recurse over the tree, assigning a binary code to each vocabulary word
if heap:
max_depth, stack = 0, [(heap[0], [], [])]
while stack:
node, codes, points = stack.pop()
if node.index < len(self.vocab):
# leaf node => store its path from the root
node.code, node.point = codes, points
max_depth = max(len(codes), max_depth)
else:
# inner node => continue recursion
points = array(list(points) + [node.index - len(self.vocab)], dtype=uint32)
stack.append((node.left, array(list(codes) + [0], dtype=uint8), points))
stack.append((node.right, array(list(codes) + [1], dtype=uint8), points))
logger.info("built huffman tree with maximum node depth %i" % max_depth)
def skyline(buildings):
if not buildings:
return []
points = []
for l, r, h in buildings:
points.append([l, -h])
points.append([r, h])
# sort the points to ensure that all points are sorted from left to right
points.sort()
result = []
queue = [0]
prev = 0
for e in points:
if e[1] < 0:
# whenever we see start point of the building
# we put the height of the building into the heapq
heapq.heappush(queue, e[1])
else:
# if we arrive at the end point of the building
# we remove the height of the building from the heapq
if queue[0] == -e[1]:
heapq.heappop(queue)
else:
queue.remove(-e[1])
heapq.heapify(queue)
curr = queue[0]
if curr != prev:
# if the tallest building in the heapq changes
# then we need to put that into the final result
result.append([e[0], -curr])
prev = curr
return result
def test_buscar_el_mayor_y_menor_valor_de_una_lista(self): import heapq nums = [1, 8, 2, 23, 7, -4, 18, 23, 42, 37, 2] tres_mayores = heapq.nlargest(3,nums) self.assertEqual(tres_mayores,[42,37,23]) tres_menores = heapq.nsmallest(3,nums) self.assertEqual(tres_menores,[-4,1,2]) mayor = max(nums) menor = min(nums) self.assertEqual(mayor ,42) self.assertEqual(menor ,-4) heap = list(nums) #Pone el primer elemento en la posicion 0 heapq.heapify(heap) self.assertEqual(heap,[-4, 2, 1, 23, 7, 2, 18, 23, 42, 37, 8]) #heappop saca el primer elemento, y lo sustituye por el menor de la lista # asi heappop siempre sacara el elemento mas pequeño menor =heapq.heappop(heap) self.assertEqual(menor,-4) menor =heapq.heappop(heap) self.assertEqual(menor, 1)
def _build_tree(self, a):
heapq.heapify(a)
while len(a) > 1:
left = heapq.heappop(a)
right = heapq.heappop(a)
heapq.heappush(a, (left[0] + right[0], left, right))
return a[0]
def get_next_task(self):
"""get the next task if there's one that should be processed,
and return how long it will be until the next one should be
processed."""
if _debug: TaskManager._debug("get_next_task")
# get the time
now = _time()
task = None
delta = None
if self.tasks:
# look at the first task
when, nxttask = self.tasks[0]
if when <= now:
# pull it off the list and mark that it's no longer scheduled
heappop(self.tasks)
task = nxttask
task.isScheduled = False
if self.tasks:
when, nxttask = self.tasks[0]
# peek at the next task, return how long to wait
delta = max(when - now, 0.0)
else:
delta = when - now
# return the task to run and how long to wait for the next one
return (task, delta)
def largestSumAfterKNegations(self, A: List[int], K: int) -> int:
s = sneg = neg = 0
absmin = math.inf
negpq = []
for a in A:
absmin = min(absmin, abs(a))
if a >= 0:
s += a
else:
heapq.heappush(negpq, a)
neg += 1
sneg += a
if K < neg:
while K:
s -= heapq.heappop(negpq)
K -= 1
while negpq:
s += heapq.heappop(negpq)
else:
s -= sneg
if (K - neg) & 1:
s -= absmin * 2
return s
def nextTime(self): while True: (t, k, o) = self._heap[0] if k in self._dict: break heapq.heappop(self._heap) return t
def getImminent(self, time):
"""
Returns a list of all models that transition at the provided time, with a specified epsilon deviation allowed.
:param time: timestamp to check for models
.. warning:: For efficiency, this method only checks the **first** elements, so trying to invoke this function with a timestamp higher than the value provided with the *readFirst* method, will **always** return an empty set.
"""
#assert debug("Asking all imminent models")
imm_children = []
t, age = time
try:
# Age must be exactly the same
first = self.heap[0]
while (abs(first[0][0] - t) < self.epsilon) and (first[0][1] == age):
# Check if the found event is actually still active
if(first[2]):
# Active, so event is imminent
imm_children.append(first[3])
first[2] = False
else:
# Wasn't active, but we will have to pop this to get the next
# So we can lower the number of invalids
self.invalids -= 1
# Advance the while loop
heappop(self.heap)
first = self.heap[0]
except IndexError:
pass
return imm_children
def generateAckPacket(self, packet):
'''
Generate ACK packet
1) If packet.pck_id == self.lastOrderedPacketID+1, the packet is the packet to be expected
else, push the pck_id to the out of order queue
2) Generate ACK packet with the lastOrderedPacketID
3) set the same timestamp for the ACK Packet as the original Data Packet
Args:
packet: the Data Packet received
'''
if packet.pck_id <= self.lastOrderedPacketID:
pass
else:
if packet.pck_id == self.lastOrderedPacketID+1:
self.lastOrderedPacketID += 1
while self.outOfOrderPackets and self.outOfOrderPackets[0] == self.lastOrderedPacketID+1:
heapq.heappop(self.outOfOrderPackets)
self.lastOrderedPacketID +=1
else:
heapq.heappush(self.outOfOrderPackets, packet.pck_id)
ack_packet = DataPacket(packet.destination, packet.source, self, self.engine.getCurrentTime(), ACK_PACKET_SIZE,
True, self.lastOrderedPacketID + 1)
ack_packet.setOriginalPacketTimestamp(packet.timestamp)
return ack_packet
def __init__(self, search_strategy):
if search_strategy == _DEPTH_FIRST:
#use stack for OPEN set (last in---most recent successor
#added---is first out)
self.open = []
self.insert = self.open.append
self.extract = self.open.pop
elif search_strategy == _BREADTH_FIRST:
#use queue for OPEN (first in---earliest node not yet
#expanded---is first out)
self.open = deque()
self.insert = self.open.append
self.extract = self.open.popleft
elif search_strategy == _BEST_FIRST:
#use priority queue for OPEN (first out is node with
#lowest hval)
self.open = []
#set node less than function to compare hvals only
sNode.lt_type = _H
self.insert = lambda node: heapq.heappush(self.open, node)
self.extract = lambda: heapq.heappop(self.open)
elif search_strategy == _ASTAR:
#use priority queue for OPEN (first out is node with
#lowest fval = gval+hval)
self.open = []
#set node less than function to compare sums of hval and gval
sNode.lt_type = _SUM_HG
self.insert = lambda node: heapq.heappush(self.open, node)
self.extract = lambda: heapq.heappop(self.open)
def generate_huffman_table(frequencies):
encoding_table = {}
decoding_table = {}
for position_id, histogram in frequencies.iteritems():
encoding_table[position_id] = [None] * 256
# create a mapping table for characters
ordinal_freq = [(histogram["%02x" % ordinal], ordinal) if histogram.has_key("%02x" % ordinal) else (1, ordinal) for ordinal in xrange(256)]
heap = []
for node in ordinal_freq:
heapq.heappush(heap, node)
while len(heap) > 1:
left = heapq.heappop(heap)
right = heapq.heappop(heap)
new_node = (left[0] + right[0], (left[1], right[1]))
heapq.heappush(heap, new_node)
total, huffman = heap[0]
fill_table(huffman, "", encoding_table[position_id])
decoding_table[position_id] = huffman
return encoding_table, decoding_table
def first_k_most_relevant(doc_scores): """If there are more than k documents containing terms in a query, return the k documents with the highest scores, tiebroken by least docID first. If there are less than k documents, return them, sorted by highest scores, and tiebroken by least docID first. O(n) + O(k lg n) :param doc_scores: A dictionary of docID to its corresponding document's score. :return: List of k docIDs of string type, which are the most relevant (i.e. have the highest scores) """ scores = [(-score, docID) for docID, score in doc_scores.iteritems()] # invert the scores so that heappop gives us the smallest score heapq.heapify(scores) most_relevant_docs = [] for _ in range(k): if not scores: break most_relevant_docs.append(heapq.heappop(scores)) if not most_relevant_docs: return most_relevant_docs # deals with equal-score cases kth_score, kth_docID = most_relevant_docs[-1] while scores: next_score, next_docID = heapq.heappop(scores) if next_score == kth_score: most_relevant_docs.append((next_score, next_docID)) else: break return sort_relevant_docs(most_relevant_docs)
def streaming_median(stream):
''' Given an umlimited stream of numbers, compute
the exact median of the values:
:param stream: The stream to observe
:returns: The median of the stream
>>> streaming_median(range(101))
50
:param stream: The stream of incoming numbers
:returns: The median of the given stream
'''
max_heap, min_heap = [], [] # max_heap is a min heap holding the large values
for el in stream: # min_heap is a max heap holding the small values
if min_heap and el > min_heap[0]:
heapq.heappush(min_heap, el)
else: heapq.heappush(max_heap, -el)
if abs(len(min_heap) - len(max_heap)) > 1:
if len(min_heap) > len(max_heap):
heapq.heappush(max_heap, -heapq.heappop(min_heap))
else:
heapq.heappush(min_heap, -heapq.heappop(max_heap))
if len(min_heap) > len(max_heap): return min_heap[0]
elif len(max_heap) > len(max_heap): return -max_heap[0]
else: return (min_heap[0] - max_heap[0]) / 2
def dijkstra(self, node_from):
graph = type(self)(copy.deepcopy(self.nodes), copy.deepcopy(self.vertex_map))
# Set the distance for the start node to zero
graph.set_node_distance(node_from, 0)
# Put tuple pair into the priority queue
unvisited_queue = graph.get_nodes_unvisited()
heapq.heapify(unvisited_queue)
while len(unvisited_queue):
distance, node_current = heapq.heappop(unvisited_queue)
graph.set_node_visited(node_current)
del distance
for node_adj in graph.vertex_map.get(node_current, {}).keys():
if graph.vertex_map[node_current][node_adj].get('visited', False):
continue
new_dist = graph.get_node_distance(node_current) + graph.vertex_map[node_current][node_adj]['distance']
if new_dist < graph.get_node_distance(node_adj):
graph.set_node_distance(node_adj, new_dist)
graph.set_node_previous(node_adj, node_current)
# Rebuild heap
# 1. Pop every item
while len(unvisited_queue):
heapq.heappop(unvisited_queue)
# 2. Put all vertices not visited into the queue
unvisited_queue = graph.get_nodes_unvisited()
heapq.heapify(unvisited_queue)
return graph
def _merge_file_iters(self, iters, key=lambda x: x):
heap = []
for iter, root in iters:
try:
heap.append((next(iter), iter, root))
except StopIteration:
pass
heapq.heapify(heap)
while heap:
value, iter, root = heapq.heappop(heap)
try:
heapq.heappush(heap, (next(iter), iter, root))
except StopIteration:
pass
items = [(value, root)]
while heap:
cand, iter, root = heapq.heappop(heap)
if key(cand) == key(value):
items.append((cand, root))
try:
heapq.heappush(heap, (next(iter), iter, root))
except StopIteration:
pass
else:
heapq.heappush(heap, (cand, iter, root))
break
yield items
def pop(self):
return_item = heappop(self)[1]
while return_item not in self._item_set:
return_item = heappop(self)[1]
self._item_set.remove(return_item)
self.sweep()
return return_item
def findMedian(self):
"""
Returns the median of current data stream
:rtype: float
"""
# If odd total len, then the value on lower heap
# If even total len, avg of both heaps.
res = []
if len(self.lower) > 0:
res.append(-heapq.heappop(self.lower))
if len(self.higher) > 0:
res.append(heapq.heappop(self.higher))
if len(res) > 0:
heapq.heappush(self.lower, -res[0])
if len(res) > 1:
heapq.heappush(self.higher, res[1])
if len(res) > 0:
if len(self.lower) > len(self.higher):
return float(res[0])
else:
return (res[0] + res[1])/float(2)
return -0.0
# Your MedianFinder object will be instantiated and called as such:
# mf = MedianFinder()
# mf.addNum(1)
# mf.findMedian()
def minMeetingRooms(self, intervals):
"""
:type intervals: List[Interval]
:rtype: int
"""
"""
用一个min-heap, 非空且下一个interval.start >= 上一个的end时, 意味不需要another room,
pop; 不然, 需要一个新的room. heap里按end比较,所以存的是(interval.end, interval)
"""
import heapq
if not intervals:
return 0
intervals = sorted(intervals, key=lambda x: x.start)
queue = []
max_len = 1
for i in xrange(len(intervals)):
while queue and intervals[i].start >= queue[0][0]:
heapq.heappop(queue)
heapq.heappush(queue, (intervals[i].end, intervals[i])) # 注意heap中用end来比较
max_len = max(max_len, len(queue))
return max_len
def print_topK(): print "size of priority q" + str(len(topKQ)) for item in topKQ: (val,key) = heapq.heappop(topKQ) print key, "st \t", int(val) (val,key) = heapq.heappop(topKQ) print key, "st \t", int(val)
def run(self):
headers = bam_headers(self.input)
writer = Bam_writer(self.prefix+'.bam', headers)
chrom = None
endpoints = [ ]
total = 0
discarded = 0
for record in Bam_reader(self.input):
if record.flag & FLAG_UNMAPPED: continue
total += 1
if chrom != record.rname:
chrom = record.rname
endpoints = [ ]
while endpoints and endpoints[0] <= record.pos:
heapq.heappop(endpoints)
if len(endpoints) >= self.depth:
discarded += 1
continue
heapq.heappush(endpoints, record.pos+record.length)
record.flag &= ~(FLAG_PAIRED|FLAG_PROPER|FLAG_MATE_UNMAPPED|FLAG_MATE_REVERSE|FLAG_FIRST|FLAG_SECOND)
record.mrnm = '*'
record.mpos = 0
writer.write(record)
writer.close()
self.log.log('Discarded %s alignments out of %s.\n' % (grace.pretty_number(discarded),grace.pretty_number(total)))
def _query(self, p, k=1, eps=0, distance_upper_bound=np.inf):
if not self.root:
return []
dist_to_ctr = self.distance(p, self.data[self.root.ctr_idx])
min_distance = max(0.0, dist_to_ctr - self.root.radius)
# priority queue for chasing nodes
# entries are:
# minimum distance between the node area and the target
# distance between node center and target
# the node
q = [(min_distance,
dist_to_ctr,
self.root)]
# priority queue for the nearest neighbors
# furthest known neighbor first
# entries are (-distance, i)
neighbors = []
if eps == 0:
epsfac = 1
else:
epsfac = 1 / (1 + eps)
while q:
min_distance, dist_to_ctr, node = heappop(q)
if isinstance(node, CoverTree._LeafNode):
# brute-force
for i in node.idx:
if i == node.ctr_idx:
d = dist_to_ctr
else:
d = self.distance(p, self.data[i])
if d <= distance_upper_bound:
if len(neighbors) == k:
heappop(neighbors)
heappush(neighbors, (-d, i))
if len(neighbors) == k:
distance_upper_bound = -neighbors[0][0]
else:
# we don't push nodes that are too far onto the queue at
# all, but since the distance_upper_bound decreases, we
# might get here even if the cell's too far
if min_distance > distance_upper_bound * epsfac:
# since this is the nearest node, we're done, bail out
break
for child in node.children:
if child.ctr_idx == node.ctr_idx:
d = dist_to_ctr
else:
d = self.distance(p, self.data[child.ctr_idx])
min_distance = max(0.0, d - child.radius)
# child might be too far, if so, don't bother pushing it
if min_distance <= distance_upper_bound * epsfac:
heappush(q, (min_distance, d, child))
return sorted([(-d, i) for (d, i) in neighbors])
def _merge_terms(self, iterlist):
# Merge-sorts terms coming from a list of term iterators.
# Create a map so we can look up each iterator by its id() value
itermap = {}
for it in iterlist:
itermap[id(it)] = it
# Fill in the list with the head term from each iterator.
current = []
for it in iterlist:
term = next(it)
current.append((term, id(it)))
heapify(current)
# Number of active iterators
active = len(current)
while active:
# Peek at the first term in the sorted list
term = current[0][0]
# Re-iterate on all items in the list that have that term
while active and current[0][0] == term:
it = itermap[current[0][1]]
try:
nextterm = next(it)
heapreplace(current, (nextterm, id(it)))
except StopIteration:
heappop(current)
active -= 1
# Yield the term
yield term
def isPossible(self, nums: List[int]) -> bool:
"""
(length, last)
heap sortest first
>= 3, then drop
split when duplicate
"""
h = []
for n in nums:
while h and h[0].end + 1 < n:
itvl = heapq.heappop(h)
if itvl.length < 3:
return False
if not h:
heapq.heappush(h, Interval(n, 1))
elif h[0].end + 1 == n:
itvl = heapq.heappop(h)
heapq.heappush(h, Interval(n, itvl.length + 1))
else: # n == end
heapq.heappush(h, Interval(n, 1))
for itvl in h:
if itvl.length < 3:
return False
return True
def pump(self, *arg, **kwarg):
"""
Pumps all events that are applicable to be called.
"""
# TODO: Reconfigure to use a number provided in pump method arguments
while self.event_queue and self.event_queue[0][0] <= video.get_time():
heapq.heappop(self.event_queue)[1](*arg, **kwarg)
def heap_merged(items_lists, combiner):
heap = []
def pushback(it):
try:
k,v = it.next()
# put i before value, so do not compare the value
heapq.heappush(heap, (k, i, v))
except StopIteration:
pass
for i, it in enumerate(items_lists):
if isinstance(it, list):
items_lists[i] = it = (k for k in it)
pushback(it)
if not heap: return
last_key, i, last_value = heapq.heappop(heap)
pushback(items_lists[i])
while heap:
k, i, v = heapq.heappop(heap)
if k != last_key:
yield last_key, last_value
last_key, last_value = k, v
else:
last_value = combiner(last_value, v)
pushback(items_lists[i])
yield last_key, last_value
def reorganizeString(self, S):
"""
:type S: str
:rtype: str
"""
if len(S) <= 1:
return S
l, c = len(S), [[-item[1], item[0]] for item in Counter(S).items()] + [[1, '#']]
heapq.heapify(c)
rls = ''
for i in range(l):
t1 = heapq.heappop(c)
t2 = heapq.heappop(c)
if rls == '' or t1[1] != rls[-1]:
rls += t1[1]
t1[0] += 1
else:
if t2[1] == '#':
return ''
rls += t2[1]
t2[0] += 1
if t1[0] != 0:
heapq.heappush(c, t1)
if t2[0] != 0:
heapq.heappush(c, t2)
return rls
# https://www.acmicpc.net/problem/2211
# 이름 : 네트워크 복구
# 번호 : 2211
# 난이도 : 골드 II
# 분류 : 그래프 이론, 다익스트라
import sys
from heapq import heappush, heappop
input = sys.stdin.readline
INF = sys.maxsize
N, M = map(int, input().split())
graph = [[] for _ in range(N + 1)]
for _ in range(M):
A, B, C = map(int, input().split())
graph[A].append((C, B))
graph[B].append((C, A))
ans = [''] * (N + 1)
dp = [INF] * (N + 1)
dp[1] = 0
heap = []
heappush(heap, [0, 1])
while heap:
dist, nx = heappop(heap)
for n_dist, x in graph[nx]:
temp = dist + n_dist
if dp[x] > temp:
dp[x] = temp
ans[x] = str(nx) + ' ' + str(x)
heappush(heap, [temp, x])
print(N - 1)
print('\n'.join(ans[2:]))
n = int(input())
a = [-int(j) for j in input().split()]
a.sort()
import heapq
l = [a[0]]
heapq.heapify(l)
ans = 0
for i in a[1:]:
heapq.heappush(l, i)
heapq.heappush(l, i)
p = heapq.heappop(l)
ans -= p
print(ans)
queue[0] # return 2 examine the first element
## Stack
stack = []
size = len(stack)
stack.append(1)
stack.append(2)
stack.pop() # return 2
## Priority Queue - https://docs.python.org/2/library/heapq.html
import heapq
heap = []
heapq.heappush(heap, 1) # heap [1]
heapq.heappush(heap, 3) # heap [1,3]
heapq.heappush(heap, 2) # heap [1,3,2]
heapq.heappop(heap) # 1
heapq.heappop(heap) # 2
heapq.heappop(heap) # 3
## Deque
import collections
dq = collections.deque()
dq.append(1) # [1]
dq.appendleft(2) # [2,1]
dq.popleft() # [1]
## Set
s = set({1,3,4,5,6,5}) # {1, 3, 4, 5, 6}
## List
def encode(file):
"""Encodes file into a smaller representation using huffman encoding.
The encoded file is written to the filename "compressed.txt"
Params: file - str
"""
# open the file
try:
s = open(file).read()
except IOError:
print("Error opening file: {}".format(file))
exit(1)
# build dict of character: frequency
freqs = make_dict(s)
# build the Huffman Tree.
# 1. Make leaf nodes, and store the letter and frequency.
# 2. Build a tree by taking the 2 nodes with the smallest frequency, and creating a parent with the
# letters concatenated and the frequencies summed.
# I used a minheap for log(N) access to the 2 nodes with the smallest frequency each time I pop from the heap.
minheap = []
for k, v in freqs.items():
heappush(minheap, TreeNode(k, v))
# ASSUMPTION: since the bitmap is of size 100 x 100 it must be separated by newlines \n,
# so there are at least 2 distinct characters in any input file.
parent_node = None # save the current parent node
# This is step 2 - building the tree by creating parent nodes and keeping track of child pointers.
while True:
node1, node2 = heappop(minheap), heappop(minheap)
parent_node = TreeNode(node1.letter + node2.letter, node1.freq + node2.freq)
parent_node.left = node1
parent_node.right = node2
if parent_node.freq == len(s):
break
else:
heappush(minheap, parent_node)
# We know the tree is built when a parent node's frequency equals the length of the original string.
# 3. Recursively iterate through the tree, creating encodings for all of the leaf nodes.
# Since there is a unique path from the root to any particular node, each encoding will be unique.
leaves = []
tree_dfs(parent_node, "", leaves)
encoding_to_char = {}
for leaf in leaves:
assert len(leaf.letter) == 1
assert leaf.encoding not in encoding_to_char # because the encodings should have been unique.
encoding_to_char[leaf.encoding] = leaf.letter
# 4. Create the dictionary that maps characters in our original file to their encodings.
char_to_encoding = {v: k for k, v in encoding_to_char.items()}
# Representation of the encoded file. First we convert it into a binary string and then hex to save space.
int_str = "".join([char_to_encoding[char] for char in s])
hex_str = hex(int(int_str, 2))
# hack to fix in the future - This way of getting the hex form does not preserve leading zeros,
# leading to occasional inaccuracy in converting back and forth between binary and hex.
num_zeros_to_add = 0
bin_str = bin(int(hex_str, 16))[2:]
while bin_str != int_str:
bin_str = '0' + bin_str
num_zeros_to_add+=1
# 5. Write out the compressed file. We will need both the string and dictionary to dencode at a later time.
try:
os.remove('compressed.txt')
except OSError:
pass
with open('compressed.txt', 'wb') as file:
pickle.dump((hex_str, char_to_encoding, num_zeros_to_add), file)
# A sanity check to make sure that the mapping and strings were written correctly.
with open('compressed.txt', 'rb') as file:
hs, mapping, add_zero = pickle.load(file)
assert mapping == char_to_encoding, "houston we have a problem"
assert bin_str == int_str, "{} {}".format(bin_str, int_str)
def run(self, run_to, node_state_grid=None,
plot_each_transition=False, plotter=None):
"""Run the model forward for a specified period of time.
Parameters
----------
run_to : float
Time to run to, starting from self.current_time
node_state_grid : 1D array of ints (x number of nodes) (optional)
Node states (if given, replaces model's current node state grid)
plot_each_transition : bool (optional)
Option to display the grid after each transition
plotter : CAPlotter object (optional)
Needed if caller wants to plot after every transition
"""
if node_state_grid is not None:
self.set_node_state_grid(node_state_grid)
# Continue until we've run out of either time or events
while self.current_time < run_to and self.event_queue:
if _DEBUG:
print('Current Time = ', self.current_time)
# Is there an event scheduled to occur within this run?
if self.event_queue[0].time <= run_to:
# If so, pick the next transition event from the event queue
ev = heappop(self.event_queue)
if _DEBUG:
print('Event:', ev.time, ev.link, ev.xn_to)
# ... and execute the transition
if _USE_CYTHON:
do_transition(ev, self.next_update,
self.grid.node_at_link_tail,
self.grid.node_at_link_head,
self.node_state, self.link_state,
self.san, self.link_orientation,
self.propid, self.prop_data,
self.n_xn, self.xn_to, self.xn_rate,
self.grid.links_at_node,
self.grid.active_link_dirs_at_node,
self.num_node_states, self.num_node_states_sq,
self.prop_reset_value, self.xn_propswap,
self.xn_prop_update_fn,
self.bnd_lnk, self.event_queue,
self,
plot_each_transition,
plotter)
else:
self.do_transition(ev, self.current_time,
plot_each_transition, plotter)
# Update current time
self.current_time = ev.time
# If there is no event scheduled for this span of time, simply
# advance current_time to the end of the current run period.
else:
self.current_time = run_to
def pop(self):
(priority, _, item) = heapq.heappop(self.heap)
return (item, priority)
import heapq
import sys
input = sys.stdin.readline
T, M, K = map(int, input().split())
KKK = list(map(int, input().split()))
arr = [list(map(int, input().split())) for i in range(M)]
dic = defaultdict(list)
for i, j, cost in arr:
dic[i].append((cost, j))
dic[j].append((cost, i))
Q = []
for n in KKK:
Q.extend(dic[n][:])
heapq.heapify(Q)
visit = [False] * (T + 1)
for n in KKK:
visit[n] = True
res = 0
size = K
while Q:
if size == T:
break
cost, next = heapq.heappop(Q)
if visit[next] == False:
visit[next] = True
res += cost
for i in dic[next]:
heapq.heappush(Q, i)
size += 1
print(res)
import heapq
import sys
N = int(input())
colors = list(map(int, input().strip().split()))
heapq.heapify(colors)
if (len(colors) % 2 == 0):
colors.append(0)
ans = 0
while (len(colors) > 2):
a = heapq.heappop(colors)
b = heapq.heappop(colors)
c = heapq.heappop(colors)
heapq.heappush(colors, a + b + c)
ans += a + b + c
print(ans)
def crawl_next(inlink, frontier, time_record, url_crawled, outlink,
url_response):
next_frontier = set()
frontier_size = len(frontier)
url_crawled_this_wave = set()
while frontier:
try:
(priority, url, parent) = heapq.heappop(frontier)
except Exception as ex:
continue
# 1. Check if this is a good url, if not, skip
if url in url_crawled:
if url in url_crawled_this_wave:
inlink[url].append(parent)
continue
if check_media(url):
continue
try:
# response = request.urlopen(url, timeout=5)
restriction = {"Accept-Language": "en-US,en;q=0.5"}
response = requests.get(url, headers=restriction, timeout=5)
url_component = parse.urlparse(url)
except Exception as ex:
continue
domain = url_component.netloc.lower()
scheme = url_component.scheme.lower()
if domain.split(
'.')[1] == 'wikipedia' and domain.split('.')[0] != 'en':
continue
if len(domain.split('.')) > 2:
if domain.split('.')[2] == 'gov':
continue
if not check_robot(scheme, domain, url):
continue
if not check_response(response):
continue
print("Crawled: " + str(len(url_crawled)) + " URL. Currently on: " +
url)
# 2. Get the next urls
# next_urls = get_next_urls(url, response)
if domain not in time_record:
time_record[domain] = time.time()
next_urls = get_next_urls(url, response)
else:
if (time.time() - time_record[domain]) < 1:
print("Sleep for" + str((time.time() - time_record[domain])))
time.sleep(time.time() - time_record[domain])
next_urls = get_next_urls(url, response)
else:
time_record[domain] = time.time()
next_urls = get_next_urls(url, response)
# 3. Saving information of the urls
url_response[url] = response
url_crawled.add(url)
if parent != None:
inlink[url].append(parent)
else:
if url in inlink:
pass
else:
inlink[url] = []
for next_url in next_urls:
next_frontier.add((next_url, url))
if next_url in url_crawled:
if str(url) != str(next_url):
inlink[next_url].append(url)
next_urls = list(next_urls)
outlink[url] = next_urls
# 4. Dump the web content when necessary.
if (len(url_crawled) % 10) == 0:
dump_inlink(inlink)
dump_url_crawled(url_crawled)
dump_frontier(frontier)
dump_content(outlink, url_response)
# Only process top 60% scored urls.
if (len(frontier) / frontier_size) < 0.4 and len(frontier) > 6:
break
# 5. Stop and exit when we crawled enough urls.
if len(url_crawled) >= 40300:
dump_inlink(inlink)
print("Finish crawling")
exit()
return next_frontier
import sys, heapq
sys.stdin = open('백준1937. 욕심쟁이 판다.txt', 'r')
d = [(0, 1), (0, -1), (1, 0), (-1, 0)]
n = int(input())
ground = [[0] * n for _ in range(n)]
matrix = [list(map(int, sys.stdin.readline().split())) for _ in range(n)]
heap = []
for r in range(n):
for c in range(n):
heapq.heappush(heap, (matrix[r][c], r, c))
answer = 0
while heap:
bamboo, r, c = heapq.heappop(heap)
for idx in range(4):
nr = r + d[idx][0]
nc = c + d[idx][1]
if 0 <= nr < n and 0 <= nc < n:
if matrix[r][c] > matrix[nr][nc]:
ground[r][c] = max(ground[r][c], ground[nr][nc])
ground[r][c] += 1
answer = max(answer, ground[r][c])
print(answer)
# DFS
# import sys
# input = sys.stdin.readline
# sys.setrecursionlimit(10**6)
def find_path(vertex1, vertex2, external_path):
# pdb.set_trace()
priority_queue = []
visited = set()
v1 = PriorityQueueVertex(vertex1, 0, None)
v1_key = Graph.compute_heuristic(vertex1, vertex2)
heapq.heappush(priority_queue, (v1_key, v1))
visited.add(vertex1)
# start search
path = []
destination_vertex = vertex2
occupied_edges = set()
while priority_queue[0][1] != destination_vertex:
# pdb.set_trace()
current_v = priority_queue[0][1]
current_cost = current_v.cost
visited.add(current_v.vertex)
# update edges that are currently occupied
for e in occupied_edges:
e.cost = Edge.UNOCCUPIED_COST
# set occupied edges
occupied_edges = set()
for i in range(1, 3):
try:
occupied_vertex = external_path[current_v.depth + i]
except IndexError:
continue
if i == 1:
for e in occupied_vertex.edges:
if e is not None:
other_edge = occupied_vertex.get_opposite_edge(e)
if other_edge is not None:
occupied_edges.add(other_edge)
if i == 2:
# update wait edge
e = occupied_vertex.edges[4]
occupied_edges.add(e)
for e in occupied_edges:
e.cost = Edge.OCCUPIED_COST
wait_flag = False
for e in current_v.vertex.edges:
if e is not None and e.cost == Edge.OCCUPIED_COST:
wait_flag = True
break
for e in current_v.vertex.edges:
if e is None:
continue
# calculate cost and heuristics, push onto PQ
v = e.destination
if wait_flag:
if v in visited and v != current_v.vertex:
continue
else:
if v in visited:
continue
v_cost = current_cost + e.cost
v_key = (v_cost + Graph.compute_heuristic(v, destination_vertex))
v_priority = PriorityQueueVertex(v, v_cost, current_v)
heapq.heappush(priority_queue, (v_key, v_priority))
if wait_flag:
# there might be duplicate entries in the priority queue.
# Only remove the smallest one
holder = [i for i in priority_queue if i[1] == current_v]
if len(holder) > 1:
holder.sort()
v_key = holder[0][0]
priority_queue.remove((v_key, current_v))
else:
priority_queue = [i for i in priority_queue if i[1] != current_v]
heapq.heapify(priority_queue)
# pdb.set_trace()
# Now get path
v_top = heapq.heappop(priority_queue)
v = v_top[1]
path = []
while True:
path.append(v.vertex)
v = v.previous_vertex
if v is None:
break
path.reverse()
return path
import heapq
for sadsf in range(int(input())):
n, m = map(int, input().split())
m -= 1
h = []
heapq.heappush(h, -n)
d = {n: 1}
j = n
while m > 0:
# print(d, h)
if d[j] > m:
break
m -= d[j]
if (j - 1) // 2 not in d:
d[(j - 1) // 2] = 0
heapq.heappush(h, -((j - 1) // 2))
d[(j - 1) // 2] += d[j]
if j // 2 not in d:
d[j // 2] = 0
heapq.heappush(h, -(j // 2))
d[j // 2] += d[j]
del d[j]
heapq.heappop(h)
j = -h[0]
print('Case #{}: {} {}'.format(sadsf + 1, j // 2, (j - 1) // 2))
def main(_):
#initial outer file
WordIndex = Word_Index()
EntTagIndex = Ent_Tag_Index()
TriTagIndex = Tri_Tag_Index()
PtagIndex = Ptag_Index()
Index = [EntTagIndex, TriTagIndex]
object_tag_Index = Index[FLAGS.object_id]
FLAGS.num_word = len(WordIndex.word2idex)
FLAGS.num_postag = len(PtagIndex.ptag2id)
FLAGS.num_class = object_tag_Index.num_class
df_test = pd.read_csv('datas/corpus/testdata_id.txt',
sep='#',
skip_blank_lines=False,
dtype={'len': np.int32})
df_train = pd.read_csv('datas/corpus/traindata_id.txt',
sep='#',
skip_blank_lines=False,
dtype={'len': np.int32})
# eval_size = int(len(df_train) * FLAGS.dev_rate)
# df_eval = df_train.iloc[-eval_size:]
# df_train = df_train.iloc[:-eval_size]
print('trainsize' + str(len(df_train)))
train_data_itor = DataItor(df_train, False)
# eval_data_itor = DataItor(df_eval,False)
test_data_itor = DataItor(df_test, False)
FLAGS.check_every_point = int(train_data_itor.size / FLAGS.batch_size)
if os.path.exists(FLAGS.pretrain_file) and FLAGS.use_pretrain_embedding:
print('initial!!!!!!!!!!')
# initial_embedding(WordIndex.word2idex)
FLAGS.pretrain_emb = initial_embedding(WordIndex.word2idex)
else:
FLAGS.pretrain_emb = None
myconfig = tf.ConfigProto(allow_soft_placement=True)
with tf.Session(config=myconfig) as sess:
model = ST_Model(FLAGS)
sess.run(tf.global_variables_initializer())
# xidx_eval, tidx_eval, lens_eval = eval_data_itor.next_all()
xidx_test, tidx_test, lens_test = test_data_itor.next_all()
# print('eval data size %f' % len(tidx_eval[0]))
# _, id2label = helper.loadMap(FLAGS.label2id_path)
saver = tf.train.Saver(max_to_keep=2)
previous_best_valid_f1_score = 0
previous_best_epoch = -1
bad_count = 0
heap_source, heap_trigger, heap_target = [], [], []
while train_data_itor.epoch < FLAGS.num_epochs:
x_train_batch, y_train_batch = train_data_itor.next_batch(
FLAGS.batch_size)
train_step, train_loss = model.train_model(
sess, x_train_batch, y_train_batch[FLAGS.object_id])
if train_data_itor.batch_time % FLAGS.check_every_point == 0:
print("current batch_time: %d" % (train_data_itor.batch_time))
# y_eval_pred, eval_loss = model.inference_for_single(sess, xidx_eval, tidx_eval[FLAGS.object_id])
y_test_pred, test_loss = model.inference_for_single(
sess, xidx_test, tidx_test[FLAGS.object_id])
if FLAGS.object_id == 0:
# precison, recall, f1_eval = helper.evaluate_ent(xidx_eval[0], tidx_eval[FLAGS.object_id],
# y_eval_pred, id2word=WordIndex.id2word,id2label=EntTagIndex.id2tag,seq_lens=lens_eval)
# print('evalution on eval data, target_eval_loss:%.4f,precison:%.4f,recall:%.4f,fscore:%.4f' % (
# eval_loss, precison, recall, f1_eval))
precison1, recall1, f1_test = helper.evaluate_ent(
xidx_test[0],
tidx_test[FLAGS.object_id],
y_test_pred,
id2word=WordIndex.id2word,
id2label=EntTagIndex.id2tag,
seq_lens=lens_test)
print(
'evalution on test data, target_eval_loss:%.3f,precison:%.4f,recall:%.4f,fscore:%.4f'
% (test_loss, precison1, recall1, f1_test))
else:
# precison, recall, f1_eval = helper.evaluate_tri(xidx_eval[0], tidx_eval[FLAGS.object_id], y_eval_pred,id2word=WordIndex.id2word,seq_lens=lens_eval)
# print('evalution on eval data, target_eval_loss:%.3f,precison:%.4f,recall:%.4f,fscore:%.4f' % (
# eval_loss, precison, recall, f1_eval))
precison1, recall1, f1_test = helper.evaluate_tri(
xidx_test[0],
tidx_test[FLAGS.object_id],
y_test_pred,
id2word=WordIndex.id2word,
seq_lens=lens_test)
print(
'evalution on test data, target_eval_loss:%.3f,precison:%.4f,recall:%.4f,fscore:%.4f'
% (test_loss, precison1, recall1, f1_test))
# early stop
if len(heap_target) < 5:
heapq.heappush(heap_target,
(f1_test, (precison1, recall1, f1_test)))
else:
if f1_test > heap_target[0][0]:
heapq.heappop(heap_target)
heapq.heappush(heap_target,
(f1_test,
(precison1, recall1, f1_test)))
if f1_test > previous_best_valid_f1_score:
helper.store_stl_result(
xidx_test[0],
tidx_test[FLAGS.object_id],
y_test_pred,
id2word=WordIndex.id2word,
id2label=Index[FLAGS.object_id].id2tag,
seq_lens=lens_test,
type_id=FLAGS.object_id)
previous_best_valid_f1_score = f1_test
bad_count = 0
else:
bad_count += 1
if bad_count >= FLAGS.patients:
print('early stop!')
break
print('Train Finished!!')
show_result(heap_target)
pass
def get(self): return heapq.heappop(self.elements)[1]
graph = defaultdict(list)
for u, v, w in data:
graph[u].append([v, w])
# perform
INF = 3000000
result = [INF for _ in range(V)]
heap = []
heapq.heappush(heap, (0, start_point))
result[start_point-1] = 0
while heap:
cur_weight, cur_point = heapq.heappop(heap)
if cur_weight > result[cur_point-1]:
print(cur_weight, result[cur_point-1])
continue
for pos, wei in graph[cur_point]:
tmp = cur_weight + wei
if tmp < result[pos-1]:
result[pos-1] = tmp
heapq.heappush(heap, (tmp, pos))
# output
for r in result:
if r == INF:
print("INF")
def get(self): # Pop and return the smallest item from the heap
return heapq.heappop(self.elements)[1]
def pop(self):
return heappop(self.q)
#21.02.02
import sys
import heapq
input = sys.stdin.readline
N = int(input())
rooms,query = [],[]
for _ in range(N):
query.append(list(map(int,input().strip().split())))
query=sorted(query,key=lambda x:x[0])
for i in range(N):
# print("i :",i,"rooms :",rooms,"Query :",query)
if len(rooms)!=0 and rooms[0]<=query[i][0]:
heapq.heappop(rooms)
heapq.heappush(rooms,query[i][1])
print(len(rooms))
import heapq
n, k1, k2 = map(int, input().split())
a = list(map(int, input().split()))[:n]
b = list(map(int, input().split()))[:n]
total = k1 + k2
arr = []
for i in range(n):
arr.append((-1) * abs(a[i] - b[i]))
heapq.heapify(arr)
while (total > 0):
item = (-1) * (heapq.heappop(arr))
heapq.heappush(arr, (-1) * abs(item - 1))
total -= 1
ans = 0
for i in range(len(arr)):
ans += (arr[i])**2
print(ans)
def pop_smallest(self):
""" Remove and return the smallest item from the queue
"""
smallest = heapq.heappop(self.heap)
del self.set[smallest]
return smallest
import heapq
# heapq.heappush()
# heapq.heappop()
# list를 heap구조로 사용하는 함수.
N = int(input())
heap = list()
result = list()
for _ in range(N):
data = int(input())
if data == 0:
if heap:
result.append(heapq.heappop(heap))
else:
result.append(0)
else:
heapq.heappush(heap, data)
for data in result:
print(data)
def start(self):
if not logging.getLogger().handlers:
# The IOLoop catches and logs exceptions, so it's
# important that log output be visible. However, python's
# default behavior for non-root loggers (prior to python
# 3.2) is to print an unhelpful "no handlers could be
# found" message rather than the actual log entry, so we
# must explicitly configure logging if we've made it this
# far without anything.
logging.basicConfig()
if self._stopped:
self._stopped = False
return
old_current = getattr(IOLoop._current, "instance", None)
IOLoop._current.instance = self
self._thread_ident = thread.get_ident()
self._running = True
# signal.set_wakeup_fd closes a race condition in event loops:
# a signal may arrive at the beginning of select/poll/etc
# before it goes into its interruptible sleep, so the signal
# will be consumed without waking the select. The solution is
# for the (C, synchronous) signal handler to write to a pipe,
# which will then be seen by select.
#
# In python's signal handling semantics, this only matters on the
# main thread (fortunately, set_wakeup_fd only works on the main
# thread and will raise a ValueError otherwise).
#
# If someone has already set a wakeup fd, we don't want to
# disturb it. This is an issue for twisted, which does its
# SIGCHILD processing in response to its own wakeup fd being
# written to. As long as the wakeup fd is registered on the IOLoop,
# the loop will still wake up and everything should work.
old_wakeup_fd = None
if hasattr(signal, 'set_wakeup_fd') and os.name == 'posix':
# requires python 2.6+, unix. set_wakeup_fd exists but crashes
# the python process on windows.
try:
old_wakeup_fd = signal.set_wakeup_fd(
self._waker.write_fileno())
if old_wakeup_fd != -1:
# Already set, restore previous value. This is a little racy,
# but there's no clean get_wakeup_fd and in real use the
# IOLoop is just started once at the beginning.
signal.set_wakeup_fd(old_wakeup_fd)
old_wakeup_fd = None
except ValueError: # non-main thread
pass
while True:
poll_timeout = _POLL_TIMEOUT
# Prevent IO event starvation by delaying new callbacks
# to the next iteration of the event loop.
with self._callback_lock:
callbacks = self._callbacks
self._callbacks = []
for callback in callbacks:
self._run_callback(callback)
# Closures may be holding on to a lot of memory, so allow
# them to be freed before we go into our poll wait.
callbacks = callback = None
if self._timeouts:
now = self.time()
while self._timeouts:
if self._timeouts[0].callback is None:
# the timeout was cancelled
heapq.heappop(self._timeouts)
self._cancellations -= 1
elif self._timeouts[0].deadline <= now:
timeout = heapq.heappop(self._timeouts)
self._run_callback(timeout.callback)
del timeout
else:
seconds = self._timeouts[0].deadline - now
poll_timeout = min(seconds, poll_timeout)
break
if (self._cancellations > 512 and self._cancellations >
(len(self._timeouts) >> 1)):
# Clean up the timeout queue when it gets large and it's
# more than half cancellations.
self._cancellations = 0
self._timeouts = [
x for x in self._timeouts if x.callback is not None
]
heapq.heapify(self._timeouts)
if self._callbacks:
# If any callbacks or timeouts called add_callback,
# we don't want to wait in poll() before we run them.
poll_timeout = 0.0
if not self._running:
break
if self._blocking_signal_threshold is not None:
# clear alarm so it doesn't fire while poll is waiting for
# events.
signal.setitimer(signal.ITIMER_REAL, 0, 0)
try:
event_pairs = self._impl.poll(poll_timeout)
except Exception as e:
# Depending on python version and IOLoop implementation,
# different exception types may be thrown and there are
# two ways EINTR might be signaled:
# * e.errno == errno.EINTR
# * e.args is like (errno.EINTR, 'Interrupted system call')
if (getattr(e, 'errno', None) == errno.EINTR or
(isinstance(getattr(e, 'args', None), tuple)
and len(e.args) == 2 and e.args[0] == errno.EINTR)):
continue
else:
raise
if self._blocking_signal_threshold is not None:
signal.setitimer(signal.ITIMER_REAL,
self._blocking_signal_threshold, 0)
# Pop one fd at a time from the set of pending fds and run
# its handler. Since that handler may perform actions on
# other file descriptors, there may be reentrant calls to
# this IOLoop that update self._events
self._events.update(event_pairs)
while self._events:
fd, events = self._events.popitem()
try:
if self._handlers.has_key(fd):
self._handlers[fd](fd, events)
except (OSError, IOError) as e:
if e.args[0] == errno.EPIPE:
# Happens when the client closes the connection
pass
else:
self.handle_callback_exception(self._handlers.get(fd))
except Exception:
self.handle_callback_exception(self._handlers.get(fd))
# reset the stopped flag so another start/stop pair can be issued
self._stopped = False
if self._blocking_signal_threshold is not None:
signal.setitimer(signal.ITIMER_REAL, 0, 0)
IOLoop._current.instance = old_current
if old_wakeup_fd is not None:
signal.set_wakeup_fd(old_wakeup_fd)
def irv_margin(election, winner=None, elim_order=None, ub=None, trace=False, timeout=1e75):
'''Compute the exact IRV margin of the election.
@type election: L{Election}
@param election: The election.
@type winner: number
@param winner: The winner of the election. If C{None}, it will be computed.
@type elim_order: list
@param elim_order: The elimination order. If C{None}, it will be computed.
@type ub: number
@param ub: An upper bound on the margin. If C{None}, it will be computed via L{irv_ub}.
@type trace: boolean
@param trace: If C{True}, print a trace of the computation.
@type timeout: number
@param timeout: The amount of time to spend computing the margin.
@rtype: number
@return: Returns the IRV margin.
'''
if ilp is None:
raise Exception('Cannot compute irv_margin() because no optimizer library could be loaded.')
then = time.time()
if winner is None or elim_order is None:
winner, _, elim_order = irv(election)
if ub is None:
ub = irv_ub(election, winner=winner, elim_order=elim_order)
# We can eliminate candidates who _must_ be eliminated first. The
# reasoning is that for them to not be eliminated, more votes would have to
# be shifted than the upper bound on the margin.
root = election.profile.deepcopy()
while True:
esets = []
_elimination_set(root, all_sets=esets, rules=SF_RCV_RULES)
max_eset = set()
candidates = root.children()
for eset in esets:
if len(eset) <= len(max_eset):
continue
lb = min(root.get_child(c).value for c in candidates - eset) - \
sum(root.get_child(c).value for c in eset)
if lb > ub:
max_eset = eset
if not max_eset:
break
for c in max_eset:
if trace:
print 'Eliminating candidate %d' % c
root.eliminate(c)
# This is the algorithm from Magrino et al., more or less
candidates = root.children()
k = len(candidates)
tertiary = []
elims = set((winner,))
j = len(elim_order)-1
for i in range(1, k+1):
if i >= len(elims):
elims = elims.union(elim_order[j])
j -= 1
tertiary.append(elims)
if trace:
print tertiary
ranks = election.ranks
fringe = []
for c in candidates:
if c == winner:
continue
if trace:
print '\t', '(%d)' % c, 0, -1, 0
heapq.heappush(fringe, (0, -1, 0, [c]))
while True:
d, s, t, elim = heapq.heappop(fringe)
if trace:
print tuple(elim), d, s, t
if len(elim) == k:
return d
now = time.time()
timeout -= now - then
if timeout <= 0.0:
return -1
then = now
elim_set = set(elim)
prefixes = candidates - elim_set
for c in prefixes:
reduced = root.deepcopy()
for e in prefixes - set((c,)):
reduced.eliminate(e)
new_elim = [c] + elim
if trace:
print '\t', tuple(new_elim),
sys.stdout.flush()
d = ilp.distance_to(reduced, ranks, new_elim, timeout)
if d == -1:
return -1
if d <= ub:
s = -len(new_elim)
t = len(set(new_elim) - tertiary[len(new_elim)-1])
if trace:
print d, s, t
heapq.heappush(fringe, (d, s, t, new_elim))
elif trace:
print d
def pop_state(
self, next_states: List[Tuple[int, int,
PuzzleState]]) -> PuzzleState:
return heapq.heappop(next_states)[2]
def best_first_search(
R, zf, K, optimal_detection, N, complexity, constellation
): # best first serach 其實類似BFS search，只不過變為priority queue
# R為H進行QR分解後的R矩陣
# zf向量為zero forcing detection後尚未demapping的結果、K為選擇branch時要選擇離soft value最近的K個節點
# optimal_detection向量為最終detection後得到的結果
# N為傳送向量長度
# complexity有3個元素，分別記錄經過幾個node、做幾次加法運算、做幾次乘法運算
# constellation為星座圖，也就是向量中元素的值域
priority_queue = []
# tree的第一層時對應到的soft value為zf[N-1, 0]
# 我們接下來要看哪些星座點離zf[N-1, 0]最近
select = [0] * len(
constellation
) # 若select[i] == 0 代表不選擇星座點i，若select[i] == 1 代表會選擇星座點i
lt = [[0] * 2 for i in range(len(constellation))]
for i in range(len(constellation)):
lt[i][0] = i # 代表這是第i個星座點，待會排序後可以知道到底哪個星座點與soft value最近
lt[i][1] = abs(zf[N - 1, 0] -
constellation[i]) # 代表此星座點與這個soft value間的距離
lt.sort(key=lambda cust: cust[1]
) # 以星座點與 soft value間的距離為依據來排序，間距越小者排越前面
# 若lt[0][0] = 3 代表星座點3與soft value最近
# 若lt[1][0] = 1 代表星座點1與soft value第二近
# 若lt[2][0] = 0 代表星座點0與soft value第三近
# 注意到我們現在只要選擇K個離soft value最近的星座點
# 所以現在開始來選擇
count = 0
for i in range(len(constellation)):
select[lt[i][0]] = 1
count += 1
if count >= K:
break
# 再來將tree中第一層離soft value zf[N-1, 0]較近的星座點丟到priority queue中
for i in range(len(constellation)):
if select[
i] == 0: # 若星座點i 離soft value zf[N-1, 0]較遠，就不選擇此星座點了
continue
vector = np.matrix([0j] * (N)).transpose()
vector[N - 1, 0] = constellation[i]
heapq.heappush(
priority_queue,
(abs(z[N - 1, 0] - R[N - 1, N - 1] * constellation[i])
**2, vector, 1))
# 將( (abs(z[N-1,0] - R[N-1,N-1]*constellation[i])**2, vector, 1) ) 丟到priority queue中
# 其中(abs(z[N-1,0] - R[N-1,N-1]*constellation[i])**2值越小的話，優先權越大
# vector則存放選擇後的向量結果
# 1代表這個向量只有1個元素
complexity[0] += 1 # 經過node點數加1
# 做一次乘法運算時，我們會採用以下的方法，所以記錄成做一次加法
# 因為detect[j,0]的值域在64QAM時為 -7, -5, -3, -1, 1, 3, 5, 7
# 乘上1，相當於0次加法
# 乘上3，相當往左shift一個bit(x2)再做一次加法 = 一次加法
# 乘上5，相當往左shift兩個bit(x4)再做一次加法 = 一次加法
# 乘上7，相當往左shift三個bit(x8)再做一次減法 = 一次加法
if constellation[i] != 1 and constellation[i] != -1:
complexity[1] += 1 # 代表加法運算次數加1
complexity[1] += 1 # 因為有做一次減法，所以加法運算次數加1
complexity[2] += 1 # 因為最後有取絕對值平方，所以乘法運算次數加1
# 接下來可以開始進行best first search了 (其過程類似BFS，只不過此處的queue變為priority queue)
while True:
#先取出priority queue中優先權最高的元素
first_element = heapq.heappop(priority_queue)
# first_element[0] 存放上一層的accumulated_metric
# first_element[1] 存放上一層的vector
# first_element[2] 則代表上一層的vector有幾個元素
if first_element[2] == N: # 若搜尋完畢
break
# 搜尋此節點的下層節點
# tree的這一層對應到的soft value為zf[N-1-first_element[2], 0]
# 我們接下來要看哪些星座點離zf[N-1-first_element[2], 0]最近
select = [0] * len(
constellation
) # 若select[i] == 0 代表不選擇星座點i，若select[i] == 1 代表會選擇星座點i
lt = [[0] * 2 for i in range(len(constellation))]
for i in range(len(constellation)):
lt[i][
0] = i # 代表這是第i個星座點，待會排序後可以知道到底哪個星座點與soft value最近
lt[i][1] = abs(
zf[N - 1 - first_element[2], 0] -
constellation[i]) # 代表此星座點與這個soft value間的距離
lt.sort(key=lambda cust: cust[1]
) # 以星座點與 soft value間的距離為依據來排序，間距越小者排越前面
# 若lt[0][0] = 3 代表星座點3與soft value最近
# 若lt[1][0] = 1 代表星座點1與soft value第二近
# 若lt[2][0] = 0 代表星座點0與soft value第三近
# 注意到我們現在只要選擇K個離soft value最近的星座點
# 所以現在開始來選擇
count = 0
for i in range(len(constellation)):
select[lt[i][0]] = 1
count += 1
if count >= K:
break
for i in range(len(constellation)):
if select[
i] == 0: # 若星座點i 離soft value zf[N - 1 - first_element[2], 0]較遠，就不選擇此星座點了
continue
vector = np.matrix(first_element[1])
vector[N - 1 - first_element[2], 0] = constellation[i]
complexity[0] += 1 # 經過node點數加1
# 接下來計算accumulated_metric
accumulated_metric = z[N - 1 - first_element[2], 0]
for j in range(N - 1, N - 2 - first_element[2], -1):
accumulated_metric -= R[
N - 1 - first_element[2],
j] * vector[j, 0] # 注意到每次都有一個減法 and 乘法運算
# 做一次乘法運算時，我們會採用以下的方法，所以記錄成做一次加法
# 因為detect[j,0]的值域在64QAM時為 -7, -5, -3, -1, 1, 3, 5, 7
# 乘上1，相當於0次加法
# 乘上3，相當往左shift一個bit(x2)再做一次加法 = 一次加法
# 乘上5，相當往左shift兩個bit(x4)再做一次加法 = 一次加法
# 乘上7，相當往左shift三個bit(x8)再做一次減法 = 一次加法
if vector[j, 0] != 1 and vector[j, 0] != -1:
complexity[1] += 1 # 代表加法運算次數加1
complexity[1] += 1 # 因為有做一次減法，所以加法運算次數加1
accumulated_metric = accumulated_metric**2
complexity[2] += 1 # 因為做一次平方運算=一次乘法運算
heapq.heappush(priority_queue,
(first_element[0] + accumulated_metric,
vector, first_element[2] + 1))
# accumulated_matrix 變為first_element[0]+accumulated_metric
# 所以要做一次加法運算
complexity[1] += 1
# first_element[1] 這個向量即為我們要的答案，將此向量的值複製到optimal_detection向量中
for i in range(len(optimal_detection)):
optimal_detection[i, 0] = first_element[1][i, 0]
import heapq, sys
N = int(input())
arr = []
for i in range(N):
a = -int(sys.stdin.readline())
if a == 0:
if arr:
print(-heapq.heappop(arr))
else:
print(0)
else:
heapq.heappush(arr, a)
def heappop(self):
return heapq.heappop(self)
def sphere_decoding_bfs(R, zf, K, optimal_detection, K1, N,
complexity, constellation):
# R為H進行QR分解後的R矩陣、zf向量為zero forcing detection後尚未demapping的結果、K為選擇branch時要選擇離soft value最近的K個節點
# optimal_detection向量為最終detection後得到的結果、K1為BFS搜尋中最多准許有幾個node出現
# N為傳送向量長度
# complexity有3個元素，分別記錄經過幾個node、做幾次加法運算、做幾次乘法運算
# constellation為星座圖，也就是向量中元素的值域
# 此處的bfs比較特別，這種bfs在搜尋一層樹時，每一條節點最多只會往下選擇其中離soft value較近的K個node
# 除此之外下一層最多總共只含K1個節點，所以我用priority queue來決定要選擇哪K1個node
queue = [[], []]
# 有兩個queue，a是要負責pop元素，b則push元素
# 等到其中a queue的元素pop完後
# 換b queue pop元素，a queue push元素
current = 0 # 利用current來決定目前是哪個queue要pop元素
# tree的第一層時對應到的soft value為zf[N-1, 0]
# 我們接下來要看哪些星座點離zf[N-1, 0]最近
select = [0] * len(
constellation
) # 若select[i] == 0 代表不選擇星座點i，若select[i] == 1 代表會選擇星座點i
lt = [[0] * 2 for i in range(len(constellation))]
for i in range(len(constellation)):
lt[i][0] = i # 代表這是第i個星座點，待會排序後可以知道到底哪個星座點與soft value最近
lt[i][1] = abs(zf[N - 1, 0] -
constellation[i]) # 代表此星座點與這個soft value間的距離
lt.sort(key=lambda cust: cust[1]
) # 以星座點與 soft value間的距離為依據來排序，間距越小者排越前面
# 若lt[0][0] = 3 代表星座點3與soft value最近
# 若lt[1][0] = 1 代表星座點1與soft value第二近
# 若lt[2][0] = 0 代表星座點0與soft value第三近
# 注意到我們現在只要選擇K個離soft value最近的星座點
# 所以現在開始來選擇
count = 0
for i in range(len(constellation)):
select[lt[i][0]] = 1
count += 1
if count >= K:
break
# 一開始將tree中第一層離soft value zf[N-1, 0]較近的節點丟到queue[current]中
for i in range(len(constellation)):
if select[i] == 0: # 若此點離soft value太遠就不選取
continue
vector = np.matrix([0j] * (N)).transpose()
vector[N - 1, 0] = constellation[i]
heapq.heappush(
queue[current],
(abs(z[N - 1, 0] - R[N - 1, N - 1] * constellation[i])
**2, vector, 1))
# 將( (abs(z[N-1,0] - R[N-1,N-1]*constellation[i])**2, vector, 1) ) 丟到priority queue中
# 其中(abs(z[N-1,0] - R[N-1,N-1]*constellation[i])**2值越小的話，優先權越大
# vector則存放選擇後的向量結果
# 1代表這個向量只有1個元素
complexity[0] += 1 # 經過node點數加1
# 做一次乘法運算時，我們會採用以下的方法，所以記錄成做一次加法
# 因為detect[j,0]的值域在64QAM時為 -7, -5, -3, -1, 1, 3, 5, 7
# 乘上1，相當於0次加法
# 乘上3，相當往左shift一個bit(x2)再做一次加法 = 一次加法
# 乘上5，相當往左shift兩個bit(x4)再做一次加法 = 一次加法
# 乘上7，相當往左shift三個bit(x8)再做一次減法 = 一次加法
if constellation[i] != 1 and constellation[i] != -1:
complexity[1] += 1 # 代表加法運算次數加1
complexity[1] += 1 # 因為有做一次減法，所以加法運算次數加1
complexity[2] += 1 # 因為最後有取絕對值平方，所以乘法運算次數加1
# 接下來要開始將queue[current]的元素pop到另一個queue[(current+1)%2]中
while True:
count = 0 # count用來紀錄queue[current] 目前pop幾個元素
while True: # 將queue[current]的元素pop出來，並根據此pop出來的元素從tree的下層選出其他節點加到queue[(current+1)%2]中
# 注意到queue[current]最多只會pop K個node
if len(queue[current]
) == 0: # 若該queue的元素都pop出來了，就直接break
break
elif count >= K1: # 若已經從queue[current]中pop K1個元素(代表從這一層的節點選取K1個節點了)
# 將queue[current]清空後在break
while True:
heapq.heappop(queue[current])
if len(queue[current]) == 0:
break
break
# 先取出priority queue中優先權最高的元素
first_element = heapq.heappop(queue[current])
# first_element[0] 存放上一層的accumulated_metric
# first_element[1] 存放上一層的vector
# first_element[2] 則代表上一層的vector有幾個元素
count += 1 # 因為queue[current] pop出一個元素了
if first_element[2] == N: # 代表BFS已搜尋到樹的最底端，搜尋結束
break
# 接下來搜尋此節點的下層節點
# 搜尋前我們要看，哪一個下層節點離下層soft value值較近，我們只選取離soft value值較近的K個節點
# 我們接下來要看哪些星座點離zf[N - 1 - first_element[2], 0]最近
select = [0] * len(
constellation
) # 若select[i] == 0 代表不選擇星座點i，若select[i] == 1 代表會選擇星座點i
lt = [[0] * 2 for i in range(len(constellation))]
for i in range(len(constellation)):
lt[i][
0] = i # 代表這是第i個星座點，待會排序後可以知道到底哪個星座點與soft value最近
lt[i][1] = abs(
zf[N - 1 - first_element[2], 0] -
constellation[i]) # 代表此星座點與這個soft value間的距離
lt.sort(key=lambda cust: cust[1]
) # 以星座點與 soft value間的距離為依據來排序，間距越小者排越前面
# 若lt[0][0] = 3 代表星座點3與soft value最近
# 若lt[1][0] = 1 代表星座點1與soft value第二近
# 若lt[2][0] = 0 代表星座點0與soft value第三近
# 注意到我們現在只要選擇K個離soft value最近的星座點
# 所以現在開始來選擇
count1 = 0
for i in range(len(constellation)):
select[lt[i][0]] = 1
count1 += 1
if count1 >= K:
break
for i in range(len(constellation)):
if select[i] == 0: # 若該星座點離此層的soft value值較遠就不選取
continue
vector = np.matrix(first_element[1])
vector[N - 1 - first_element[2],
0] = constellation[i]
complexity[0] += 1 # 經過node點數加1
# 接下來計算accumulated_metric
accumulated_metric = z[N - 1 - first_element[2], 0]
for j in range(N - 1, N - 2 - first_element[2],
-1):
accumulated_metric -= R[
N - 1 - first_element[2],
j] * vector[j, 0] # 注意到每次都有一個減法 and 乘法運算
# 做一次乘法運算時，我們會採用以下的方法，所以記錄成做一次加法
# 因為detect[j,0]的值域在64QAM時為 -7, -5, -3, -1, 1, 3, 5, 7
# 乘上1，相當於0次加法
# 乘上3，相當往左shift一個bit(x2)再做一次加法 = 一次加法
# 乘上5，相當往左shift兩個bit(x4)再做一次加法 = 一次加法
# 乘上7，相當往左shift三個bit(x8)再做一次減法 = 一次加法
if vector[j, 0] != 1 and vector[j, 0] != -1:
complexity[1] += 1 # 代表加法運算次數加1
complexity[1] += 1 # 因為有做一次減法，所以加法運算次數加1
accumulated_metric = accumulated_metric**2
complexity[2] += 1 # 因為做一次平方運算=一次乘法運算
heapq.heappush(
queue[(current + 1) % 2],
(first_element[0] + accumulated_metric, vector,
first_element[2] +
1)) # 將一個節點push到queue[(current+1)%2]中
# accumulated_matrix 變為first_element[0]+accumulated_metric
# 所以要做一次加法運算
complexity[1] += 1
current = (
current + 1
) % 2 # 因為待會負責pop的queue會變成要push、而剛剛負責push的queue則要負責pop
if first_element[2] == N:
break
# first_element[1] 這個向量即為我們要的答案，將此向量的值複製到optimal_detection向量中
for i in range(len(optimal_detection)):
optimal_detection[i, 0] = first_element[1][i, 0]
visited = [False]*(n+1)
edge = [[3, 6], [4, 3], [5, 2], [1, 3], [1, 5], [3, 5], [5, 6]]
for a, b in edge:
graph[a].append((a, b))
graph[b].append((b, a))
result[1] = 0
for i in range(len(graph[1])):
heapq.heappush(heapq_list, graph[1][i])
visited[1] = True
while(heapq_list):
print(heapq_list)
from_, to_ = heapq.heappop(heapq_list)
if visited[to_] == True:
continue
if result[from_]+1 < result[to_]:
result[to_] = result[from_]+1
for i in range(len(graph[to_])):
heapq.heappush(heapq_list, graph[to_][i])
visited[to_] = True
max_num = max(result)
count = 0
for num in result:
if num == max_num:
count += 1
print(result)
print(count)
def heap_sort(arr): heapq.heapify(arr) # O(n) time result = [] while len(arr) > 0: result.append(heapq.heappop(arr)) # Pop takes O(1) + O(log n) for re-heapification return result