Exemplo n.º 1
0
def main():
    max = 0
    product = 0
    for a in range(-1000, 1001):
        for b in range(-1000, 1001):
            n = 0
            maxCount = 0
            while (lib.isPrime(n**2 + a * n + b)):
                n += 1
                maxCount += 1

            if maxCount > max:
                max = maxCount
                product = a * b

    return product
Exemplo n.º 2
0
from lib import isPrime
from math import sqrt

n = 7
while True:
    n += 2
    if isPrime(n): continue

    flag = False
    for i in range(2, n):
        if not isPrime(i): continue
        r = sqrt((n - i) / 2)
        if r == int(r):
            flag = True
            #print("%d = %d + 2x%d^2" % (n, i, int(r)))
            break

    if flag == False:
        print(n)
Exemplo n.º 3
0
from lib import isPrime

k = 4
n = 2
c = 0
while True:
    i = 2
    s = set()
    m = n
    while i <= m:
        if isPrime(i):
            while m % i == 0:
                s.add(i)
                m = int(m/i)
        if len(s) > k:
            s = set()
            break
        i+=1
    if len(s) == k:
        c += 1
    else:
        c = 0
    if c == k:
        print(n, len(s))
        break
    n+=1
Exemplo n.º 4
0
from lib import isPrime
from itertools import permutations

p = []

for n in range(1000, 10000):
    if isPrime(n):
        p.append(n)
print("Start")
for n in range(1000, 10000):
    if n % 1000 == 0:
        print(n)
    a = permutations(str(n))
    r = set()
    for x in a:
        x = int(''.join(x))
        if x in p:
            r.add(x)
    r = list(r)
    if len(r) < 3:
        continue
    r.sort()
    for i in range(0, len(r)):
        for j in range(i + 1, len(r)):
            for k in range(j + 1, len(r)):
                if r[i] + r[k] == 2 * r[j]:
                    print(r[i], r[j], r[k])
Exemplo n.º 5
0
from lib import isPrime

p = [0, 0]
d = 0
n = 1
c = 0
s = 1
t = 0
while True:
    if d == 0:
        p[0] += 1
        n += 1
        if abs(p[0]) == c:
            s += 1
            if isPrime(n): t += 1
        if abs(p[0]) > c:
            c += 1
            d += 1
            d %= 4
    elif d == 1:
        p[1] += 1
        n += 1
        if abs(p[1]) == c:
            d += 1
            d %= 4
            s += 1
            if isPrime(n): t += 1
    elif d == 2:
        p[0] -= 1
        n += 1
        if abs(p[0]) == c:
Exemplo n.º 6
0
from lib import isPrime

k = 1000000
n = 1
r = []
while n <= k:
    n += 1
    m = n
    if not isPrime(n): continue
    s = 0
    a = 0
    c = 0
    d = 0
    while s <= k:
        if isPrime(n):
            s += n
            c += 1
            if s <= k and isPrime(s):
                d = c
                a = s
        n += 1

    if [d, m, a] > r: r = [d, m, a]
    n = m

print(r)
Exemplo n.º 7
0
v = []
m = 0
digit = '0123456789'

#for _ in range(1000):
while True:
    s = str(n)
    char = list(set(s))
    form = []
    for x in char:
        form.append(s.replace(x, '*'))
    for f in form:
        if f in v:
            continue
        r = []
        for d in digit:
            t = f.replace('*', d)
            if t[0] == '0':
                continue
            if isPrime(int(t)):
                r.append(int(t))
        if len(r) > m:
            m = len(r)
            print(r)
        v.append(f)
    if n % 1000 == 0:
        print(n)
    n += 1

#[121313, 222323, 323333, 424343, 525353, 626363, 828383, 929393]