Exemplo n.º 1
0
def simp_not(x):
    if isinstance(x, Not):
        return x.args[0]
    if is_true(x):
        return Or()
    if is_false(x):
        return And()
    return Not(x)
Exemplo n.º 2
0
def simp_or(x, y):
    if is_false(x):
        return y
    if is_true(x):
        return x
    if is_false(y):
        return x
    if is_true(y):
        return y
    return Or(x, y)
Exemplo n.º 3
0
def extensionality(destrs):
    if not destrs:
        return Or()
    c = []
    sort = destrs[0].sort.dom[0]
    x, y = Variable("X", sort), Variable("Y", sort)
    for d in destrs:
        vs = variables(d.sort.dom[1:])
        eqn = Equals(d(*([x] + vs)), d(*([y] + vs)))
        if vs:
            eqn = lg.ForAll(vs, eqn)
        c.append(eqn)
    res = Implies(And(*c), Equals(x, y))
    return res
Exemplo n.º 4
0
 def to_constraint(self):
     if isinstance(self.args[1],Some):
         if self.args[1].if_value() != None:
             return And(Implies(self.args[1].args[1],
                                lg.Exists([self.args[1].args[0]],
                                          And(self.args[1].args[1],Equals(self.args[0],self.args[1].if_value())))),
                        Or(lg.Exists([self.args[1].args[0]],self.args[1].args[1]),
                           Equals(self.args[0],self.args[1].else_value())))
         return lg.ForAll([self.args[1].args[0]],
                          Implies(self.args[1].args[1],
                                  lu.substitute(self.args[1].args[1],{self.args[1].args[0]:self.args[0]})))
     if is_individual(self.args[0]):
         return Equals(*self.args)
     return Iff(*self.args)
Exemplo n.º 5
0
    def _process_rule(self, a, b):
        # right part first

        # a -> b & c    -->  a -> b  ;  a -> c
        # (?) FIXME this is only correct when b & c != null !
        if isinstance(b, And):
            for barg in b.args:
                self.process_rule(a, barg)

        # a -> b | c    -->  !b & !c -> !a
        #               -->   a & !b -> c
        #               -->   a & !c -> b
        elif isinstance(b, Or):
            # detect tautology first
            if not isinstance(a, Logic):    # Atom
                # tautology:  a -> a|c|...
                if a in b.args:
                    raise TautologyDetected(a,b, 'a -> a|c|...')
            self.process_rule(And(*[Not(barg) for barg in b.args]), Not(a))

            for bidx in range(len(b.args)):
                barg = b.args[bidx]
                brest= b.args[:bidx] + b.args[bidx+1:]
                self.process_rule(And(a, Not(barg)), Or(*brest))

        # left part

        # a & b -> c    -->  IRREDUCIBLE CASE -- WE STORE IT AS IS
        #                    (this will be the basis of beta-network)
        elif isinstance(a, And):
            if b in a.args:
                raise TautologyDetected(a,b, 'a & b -> a')
            self.proved_rules.append((a,b))
            # XXX NOTE at present we ignore  !c -> !a | !b

        elif isinstance(a, Or):
            if b in a.args:
                raise TautologyDetected(a,b, 'a | b -> a')
            for aarg in a.args:
                self.process_rule(aarg, b)

        else:
            # both `a` and `b` are atoms
            self.proved_rules.append((a,b))     # a  -> b
            self.proved_rules.append((Not(b), Not(a)))   # !b -> !a
Exemplo n.º 6
0
                # no caching of unknown results
                print "z3 returned: {}".format(res)
                assert False
                result.append(None)
    return result


if __name__ == '__main__':
    S = UninterpretedSort('S')
    X, Y, Z = (Var(n, S) for n in ['X', 'Y', 'Z'])
    BinRel = FunctionSort(S, S, Boolean)
    leq = Const('leq', BinRel)
    transitive1 = ForAll((X, Y, Z),
                         Implies(And(leq(X, Y), leq(Y, Z)), leq(X, Z)))
    transitive2 = ForAll((X, Y, Z),
                         Or(Not(leq(X, Y)), Not(leq(Y, Z)), leq(X, Z)))
    transitive3 = Not(
        Exists((X, Y, Z), And(leq(X, Y), leq(Y, Z), Not(leq(X, Z)))))
    antisymmetric = ForAll((X, Y),
                           Implies(And(leq(X, Y), leq(Y, X), true), Eq(Y, X)))

    print z3_implies(transitive1, transitive2)
    print z3_implies(transitive2, transitive3)
    print z3_implies(transitive3, transitive1)
    print z3_implies(transitive3, antisymmetric)
    print

    print z3_implies(true, Iff(transitive1, transitive2))
    print

    x, y = (Const(n, S) for n in ['x', 'y'])
Exemplo n.º 7
0
    ('-', [alpha, alpha, alpha]),
    ('/', [alpha, alpha, alpha]),
]

polymorphic_symbols = dict(
    (x, lg.Const(x, lg.FunctionSort(*y))) for x, y in polymorphic_symbols_list)

polymorphic_macros_map = {
    '<=': '<',
    '>': '<',
    '>=': '<',
}

macros_expansions = {
    '<=':
    lambda t: Or(normalize_symbol(t.func)(*t.args), Equals(*t.args)),
    '>':
    lambda t: normalize_symbol(t.func)(t.args[1], t.args[0]),
    '>=':
    lambda t: Or(
        normalize_symbol(t.func)(t.args[1], t.args[0]), Equals(*t.args)),
}


def is_macro(term):
    return isinstance(
        term, lg.Apply
    ) and term.func.name in macros_expansions and iu.ivy_use_polymorphic_macros


def expand_macro(term):
Exemplo n.º 8
0
from logic import Symbol, And, Or, Not, Implication, Biconditional, model_check

AKnight = Symbol("A is a Knight")
AKnave = Symbol("A is a Knave")

BKnight = Symbol("B is a Knight")
BKnave = Symbol("B is a Knave")

CKnight = Symbol("C is a Knight")
CKnave = Symbol("C is a Knave")

# Puzzle 0
# A says "I am both a knight and a knave."
knowledge0 = And(
    # Structure of the generic problem
    Or(AKnight, AKnave),
    Not(And(AKnight, AKnave)),

    # Information about what the characters said
    Implication(AKnight, And(AKnight, AKnave)),
    Implication(AKnave, Not(And(AKnight, AKnave)))
)

# Puzzle 1
# A says "We are both knaves."
# B says nothing.
knowledge1 = And(
    # Structure of the generic problem
    Or(AKnight, AKnave),
    Or(BKnight, BKnave),
    Not(And(AKnight, AKnave)),
Exemplo n.º 9
0
from logic import Symbol, And, Or, Implication, Biconditional, Not, model_check

AKnight = Symbol("A is a Knight")
AKnave = Symbol("A is a Knave")

BKnight = Symbol("B is a Knight")
BKnave = Symbol("B is a Knave")

CKnight = Symbol("C is a Knight")
CKnave = Symbol("C is a Knave")

OnlyOneKindForEach = And(Or(AKnave, AKnight), Or(BKnight, BKnave),
                         Or(CKnave, CKnight))

# Puzzle 0
# A says "I am both a knight and a knave."
knowledge0 = And(OnlyOneKindForEach, Implication(AKnight, And(AKnight,
                                                              AKnave)))

# Puzzle 1
# A says "We are both knaves."
# B says nothing.

WereBothKnaves = And(BKnave, AKnave)
knowledge1 = And(
    OnlyOneKindForEach,
    Implication(AKnight, WereBothKnaves),
    Implication(AKnave, Not(WereBothKnaves)),
)

# Puzzle 2
Exemplo n.º 10
0
    X, Y, Z = (Var(n, S) for n in ['X', 'Y', 'Z'])

    r = Const('r', BinaryRelationS)
    n = Const('n', BinaryRelationS)
    p = Const('p', UnaryRelationS)
    q = Const('q', UnaryRelationS)
    u = Const('u', UnaryRelationS)

    c11 = Concept([X], And(p(X), q(X)))
    c10 = Concept([X], And(p(X), Not(q(X))))
    c01 = Concept([X], And(Not(p(X)), q(X)))
    c00 = Concept([X], And(Not(p(X)), Not(q(X))))
    cu = Concept([X], u(X))

    crn = Concept([X, Y], Or(r(X,Y), n(X,Y)))

    combiners = get_standard_combiners()
    combinations = get_standard_combinations()

    test('c11')
    test('c10')
    test('c01')
    test('c00')
    test('cu')
    test('crn')
    print
    for k, v in combiners.iteritems():
        print k, ':', v
    print
Exemplo n.º 11
0
from logic import And, Or, Symbol, Biconditional, Implication, Not, model_check

AKnight = Symbol("A is a Knight")
AKnave = Symbol("A is a Knave")

BKnight = Symbol("B is a Knight")
BKnave = Symbol("B is a Knave")

CKnight = Symbol("C is a Knight")
CKnave = Symbol("C is a Knave")

# Puzzle 0
# A says "I am both a knight and a knave."
knowledge0 = And(Or(AKnight, AKnave), Implication(AKnight, Not(AKnave)),
                 Implication(AKnave, Not(AKnight)),
                 Biconditional(AKnight, And(AKnight, AKnave)))

# Puzzle 1
# A says "We are both knaves."
# B says nothing.
knowledge1 = And(Or(AKnight, AKnave), Implication(AKnight, Not(AKnave)),
                 Implication(AKnave, Not(AKnight)), Or(BKnight, BKnave),
                 Implication(BKnight, Not(BKnave)),
                 Implication(BKnave, Not(BKnight)),
                 Biconditional(AKnight, And(AKnave, BKnave)))

# Puzzle 2
# A says "We are the same kind."
# B says "We are of different kinds."
knowledge2 = And(
    Or(AKnight, AKnave), Implication(AKnight, Not(AKnave)),
Exemplo n.º 12
0
    X, Y, Z = (Var(n, S) for n in ['X', 'Y', 'Z'])

    r = Const('r', BinaryRelationS)
    n = Const('n', BinaryRelationS)
    p = Const('p', UnaryRelationS)
    q = Const('q', UnaryRelationS)
    u = Const('u', UnaryRelationS)

    c11 = Concept('both',[X], And(p(X), q(X)))
    c10 = Concept('onlyp',[X], And(p(X), Not(q(X))))
    c01 = Concept('onlyq',[X], And(Not(p(X)), q(X)))
    c00 = Concept('none',[X], And(Not(p(X)), Not(q(X))))
    cu = Concept('u',[X], u(X))

    crn = Concept('r_or_n',[X, Y], Or(r(X,Y), n(X,Y)))

    combiners = get_standard_combiners()
    combinations = get_standard_combinations()

    test('c11')
    test('c10')
    test('c01')
    test('c00')
    test('cu')
    test('crn')
    print
    for k, v in combiners.iteritems():
        print k, ':', v
    print
                         ['xy', 'other', 'x', 'y'],
                         ['nstar', 'nplus'],
                     ))]),
    )

    facts = cd.get_facts()
    print "facts = ["
    for tag, formula in facts:
        print '   ', tag, formula, ','
    print "]\n"

    state = And(
        ForAll([X, Y, Z],
               And(
                   nstar(X, X),
                   Implies(And(nstar(X, Y), nstar(Y, X)), Eq(X, Y)),
                   Implies(And(nstar(X, Y), nstar(Y, Z)), nstar(X, Z)),
                   Implies(And(nstar(X, Y), nstar(X, Z)),
                           Or(nstar(Y, Z), nstar(Z, Y))),
               )),
        nstar(x, y),
        Not(Eq(x, y)),
        ForAll([Z], Implies(And(nstar(x, Z), Not(Eq(x, Z))), nstar(y, Z))),
    )

    abstract_value = alpha(cd, state)
    print "abstract_value = ["
    for tag, value in abstract_value:
        print '   ', tag, value, ','
    print "]\n"
Exemplo n.º 14
0
festas = Symbol("festas")
musica = Symbol("musica")
jogos = Symbol("jogos")
biblioteca = Symbol("biblioteca")
escritorio = Symbol("escritorio")

rooms = [
    hall, estar, cozinha, jantar, festas, musica, jogos, biblioteca, escritorio
]

# Initialize symbols list and knowledge base
symbols = characters + weapons + rooms

# The answer must contain one person, room, and weapon
knowledge = And(
    Or(Mostarda, Black, Violeta, Marinho, Rosa, Branca),
    Or(faca, castical, revolver, corda, cano, chave),
    Or(hall, estar, cozinha, jantar, festas, musica, jogos, biblioteca,
       escritorio))

# If one person, room or weapon is in the answer,
# it implicates that the others aren't
"""
for character1 in characters:
    for character2 in characters:
        if character1 != character2:
            knowledge.add(Implication(character1,
                          Not(character2)))

for weapon1 in weapons:
    for weapon2 in weapons:
Exemplo n.º 15
0
knowledge = And()

# Enter number of players
n_players = 4

# Add another player, the cards of player 0 will be the answer
n_players += 1

# Add cards to symbols list
for card in cards:
    for index in range(n_players):
        symbols.append(Symbol(f"{card}{index}"))

# The answer must contain one person, room, and weapon
knowledge = And(
    Or(Symbol("Mostarda0"), Symbol("Black0"), Symbol("Violeta0"),
       Symbol("Marinho0"), Symbol("Rosa0"), Symbol("Branca0")),
    Or(Symbol("faca0"), Symbol("castical0"), Symbol("revoler0"),
       Symbol("corda0"), Symbol("cano0"), Symbol("chave0")),
    Or(Symbol("hall0"), Symbol("estar0"),
       Symbol("cozinha0"), Symbol("jantar0"), Symbol("festas0"),
       Symbol("musica0"), Symbol("jogos0"), Symbol("biblioteca0"),
       Symbol("escritorio0")))

# If one person, room or weapon is in the answer,
# it implicates that the others aren't
for character1 in characters:
    for character2 in characters:
        if character1 != character2:
            knowledge.add(
                Implication(Symbol(f"{character1}0"),
                            Not(Symbol(f"{character2}0"))))
Exemplo n.º 16
0
from logic import Symbol, And, Or, Not, Implication, Biconditional, model_check

AKnight = Symbol("A is a Knight")
AKnave = Symbol("A is a Knave")

BKnight = Symbol("B is a Knight")
BKnave = Symbol("B is a Knave")

CKnight = Symbol("C is a Knight")
CKnave = Symbol("C is a Knave")

# Puzzle 0
# A says "I am both a knight and a knave."
knowledge0 = And(
    #Puzzle constraints, a person must be either a Knigh or a Knave, not both
    And(Or(AKnight, AKnave), Not(And(AKnight, AKnave))),

    #Suposing that A is Knight
    Implication(AKnight, And(AKnight, AKnave)),
    #Suposing that A is Knave
    Implication(AKnave, Or(Not(AKnight), Not(AKnave))))

# Puzzle 1
# A says "We are both knaves."
# B says nothing.
knowledge1 = And(And(Or(AKnight, AKnave), Not(And(AKnight, AKnave))),
                 And(Or(BKnight, BKnave), Not(And(BKnight, BKnave))),
                 Implication(AKnight, And(AKnave, BKnave)),
                 Implication(AKnave, Not(And(AKnave, BKnave))))

# Puzzle 2