Exemplo n.º 1
0
    def _get_sorted_index(self):
        """Get index of samples indexed by reference and ordered by start pos.

        :returns: {ref_name: [sample dicts sorted by start]}
        """

        ref_names = defaultdict(list)

        for key, f in self.samples:
            d = Sample.decode_sample_name(key)
            if d is not None:
                d['key'] = key
                d['filename'] = f
                ref_names[d['ref_name']].append(d)

        # sort dicts so that refs are in order and within a ref, chunks are in order
        ref_names_ordered = OrderedDict()

        get_major_minor = lambda x: tuple((int(i) for i in x.split('.')))
        # sort by start and -end so that if we have two samples with the same
        # start but differrent end points, the longest sample comes first
        sorter = lambda x: (get_major_minor(x['start']) + tuple((-i for i in get_major_minor(x['end']))))
        for ref_name in sorted(ref_names.keys()):
            ref_names[ref_name].sort(key=sorter)
            ref_names_ordered[ref_name] = ref_names[ref_name]

        return ref_names_ordered
Exemplo n.º 2
0
    def test_decode_sample_name(self):
        expected = [
            {
                'ref_name': 'contig1',
                'start': '0.0',
                'end': '4.3'
            },
            {
                'ref_name': 'contig1',
                'start': '4.1',
                'end': '7.0'
            },
        ]

        for expt, sample in zip(expected, self.samples):
            self.assertEqual(expt, Sample.decode_sample_name(sample.name))
Exemplo n.º 3
0
    def _get_sorted_index(self):
        """Get index of samples indexed by reference and ordered by start pos.

        :returns: {ref_name: [sample dicts sorted by start]}
        """

        ref_names = defaultdict(list)

        for key, f in self.samples:
            d = Sample.decode_sample_name(key)
            if d is not None:
                d['key'] = key
                d['filename'] = f
                ref_names[d['ref_name']].append(d)

        # sort dicts so that refs are in order and within a ref, chunks are in order
        ref_names_ordered = OrderedDict()
        for ref_name in sorted(ref_names.keys()):
            sorter = lambda x: float(x['start'])
            ref_names[ref_name].sort(key=sorter)
            ref_names_ordered[ref_name] = ref_names[ref_name]

        return ref_names_ordered