def test_b_id_to_l_b_id_resolution_case_2(self):
"""Caso 1 - Dati inseriti nell'ordine DXF(l_b_id) -> Easyroom -> Edilizia"""
# A)
self.add_dxf_data()
self.add_easy_data()
# Adesso devono esistere DUE documenti relativi allo stesso building,
# uno con l_b_id e un altro con b_id
b1 = Building.find(self.db_building["easyroom"]["b_id"])
b2 = Building.find(self.db_building["dxf"]["l_b_id"])
self.assertTrue(b1 and b2)
self.assertTrue(b1.has_attr("easyroom"))
self.assertTrue(b2.has_attr("dxf"))
# B)
self.add_edil_data()
self.validate_single_document()
def retrieve_test_building(self):
b = Building.find( self.db_building["_id"] )
if not b:
return None
if "dxf" in b and "floors" in b["dxf"]:
for f in b["dxf"]["floors"]:
if "updated_at" in f:
del f["updated_at"]
return b
def validate_single_document(self, namespaces=None):
"""Valida che ci sia un documento che contiene tutte le info"""
b = self.retrieve_test_building()
if namespaces is None or ("edilizia" in namespaces):
self.assertTrue( b.has_attr("edilizia") )
self.assertEqual( b.attr("edilizia")["l_b_id"], "5703" )
if namespaces is None or ("dxf" in namespaces):
self.assertEqual(b.attr("dxf")["floors"], self.db_building["dxf"]["floors"])
self.assertEqual( b.attr("dxf")["floors"][0]["f_id"], "-05" )
if namespaces is None or ("easyroom" in namespaces):
self.assertTrue( b.has_attr("easyroom") )
self.assertEqual( b.attr("easyroom")["address"], "Via Celoria" )
# Non dev'esserci un documento con legacy building id
self.assertIsNone( Building.find(self.db_building["dxf"]["l_b_id"]) )
def retrieve_test_building(self):
b = Building.find( "21030" )
return b
