def test_follow(self):
u1 = User(username='******', email='*****@*****.**')
u2 = User(username='******', email='*****@*****.**')
db.session.add(u1)
db.session.add(u2)
db.session.commit()
self.assertEqual(u1.followed.all(), [])
self.assertEqual(u1.followers.all(), [])
u1.follow(u2)
db.session.commit()
self.assertTrue(u1.is_following(u2))
self.assertEqual(u1.followed.count(), 1)
self.assertEqual(u1.followed.first().username, 'susan')
self.assertEqual(u2.followers.count(), 1)
self.assertEqual(u2.followers.first().username, 'john')
u1.unfollow(u2)
db.session.commit()
self.assertFalse(u1.is_following(u2))
self.assertEqual(u1.followed.count(), 0)
self.assertEqual(u2.followers.count(), 0)
def users_create():
t1 = time.clock()
for i in range(1, 1000):
ui = unicode(i)
u = User(email=ui+u'@qq.com', password=u'123', nickname=ui+u'q',
school=random.choice(schools), sex=random.choice(sex), status=random.choice(status), grade=u'国光13级硕士',
bday=u'1992-03-14', pubinfo=u'我的邮箱是123457568', contact=u'微信：6578678687', prinfo=u'我有很多很多秘密')
db.session.add(u)
db.session.add(u.follow(u))
db.session.commit() # 必须先提交。不然下面找不到id
"""自动在Visitors表里增加自己。 免得每次重复检测是否存在 add by lee @ 14.8.15"""
db.session.add(Visitors(user_id=u.id, visits=0))
db.session.commit()
t2 = time.clock()
return t2 -t1
def test_follow_posts(self):
# create four users
u1 = User(username='******', email='*****@*****.**')
u2 = User(username='******', email='*****@*****.**')
u3 = User(username='******', email='*****@*****.**')
u4 = User(username='******', email='*****@*****.**')
db.session.add_all([u1, u2, u3, u4])
# create four posts
now = datetime.utcnow()
p1 = Post(body="post from john",
author=u1,
timestamp=now + timedelta(seconds=1))
p2 = Post(body="post from susan",
author=u2,
timestamp=now + timedelta(seconds=4))
p3 = Post(body="post from mary",
author=u3,
timestamp=now + timedelta(seconds=3))
p4 = Post(body="post from david",
author=u4,
timestamp=now + timedelta(seconds=2))
db.session.add_all([p1, p2, p3, p4])
db.session.commit()
# setup the followers
u1.follow(u2) # john follows susan
u1.follow(u4) # john follows david
u2.follow(u3) # susan follows mary
u3.follow(u4) # mary follows david
db.session.commit()
# check the followed posts of each user
f1 = u1.followed_posts().all()
f2 = u2.followed_posts().all()
f3 = u3.followed_posts().all()
f4 = u4.followed_posts().all()
self.assertEqual(f1, [p2, p4, p1])
self.assertEqual(f2, [p2, p3])
self.assertEqual(f3, [p3, p4])
self.assertEqual(f4, [p4])
