Exemplo n.º 1
0
    def test_unique_masked(self):
        # issue 8664
        x = np.array([64, 0, 1, 2, 3, 63, 63, 0, 0, 0, 1, 2, 0, 63, 0],
                     dtype='uint8')
        y = np.ma.masked_equal(x, 0)

        v = np.unique(y)
        v2, i, c = np.unique(y, return_index=True, return_counts=True)

        msg = 'Unique returned different results when asked for index'
        assert_array_equal(v.data, v2.data, msg)
        assert_array_equal(v.mask, v2.mask, msg)
Exemplo n.º 2
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 def test_unique_sort_order_with_axis(self):
     # These tests fail if sorting along axis is done by treating subarrays
     # as unsigned byte strings.  See gh-10495.
     fmt = "sort order incorrect for integer type '%s'"
     for dt in 'bhilq':
         a = np.array([[-1], [0]], dt)
         b = np.unique(a, axis=0)
         assert_array_equal(a, b, fmt % dt)
Exemplo n.º 3
0
def in1d(ar1, ar2, assume_unique=False, invert=False):
    """
    Test whether each element of a 1-D array is also present in a second array.

    Returns a boolean array the same length as `ar1` that is True
    where an element of `ar1` is in `ar2` and False otherwise.

    We recommend using :func:`isin` instead of `in1d` for new code.

    Parameters
    ----------
    ar1 : (M,) array_like
        Input array.
    ar2 : array_like
        The values against which to test each value of `ar1`.
    assume_unique : bool, optional
        If True, the input arrays are both assumed to be unique, which
        can speed up the calculation.  Default is False.
    invert : bool, optional
        If True, the values in the returned array are inverted (that is,
        False where an element of `ar1` is in `ar2` and True otherwise).
        Default is False. ``np.in1d(a, b, invert=True)`` is equivalent
        to (but is faster than) ``np.invert(in1d(a, b))``.

        .. versionadded:: 1.8.0

    Returns
    -------
    in1d : (M,) ndarray, bool
        The values `ar1[in1d]` are in `ar2`.

    See Also
    --------
    isin                  : Version of this function that preserves the
                            shape of ar1.
    numpy.lib.arraysetops : Module with a number of other functions for
                            performing set operations on arrays.

    Notes
    -----
    `in1d` can be considered as an element-wise function version of the
    python keyword `in`, for 1-D sequences. ``in1d(a, b)`` is roughly
    equivalent to ``np.array([item in b for item in a])``.
    However, this idea fails if `ar2` is a set, or similar (non-sequence)
    container:  As ``ar2`` is converted to an array, in those cases
    ``asarray(ar2)`` is an object array rather than the expected array of
    contained values.

    .. versionadded:: 1.4.0

    Examples
    --------
    >>> test = np.array([0, 1, 2, 5, 0])
    >>> states = [0, 2]
    >>> mask = np.in1d(test, states)
    >>> mask
    array([ True, False,  True, False,  True])
    >>> test[mask]
    array([0, 2, 0])
    >>> mask = np.in1d(test, states, invert=True)
    >>> mask
    array([False,  True, False,  True, False])
    >>> test[mask]
    array([1, 5])
    """
    # Ravel both arrays, behavior for the first array could be different
    ar1 = np.asarray(ar1).ravel()
    ar2 = np.asarray(ar2).ravel()

    # Check if one of the arrays may contain arbitrary objects
    contains_object = ar1.dtype.hasobject or ar2.dtype.hasobject

    # This code is run when
    # a) the first condition is true, making the code significantly faster
    # b) the second condition is true (i.e. `ar1` or `ar2` may contain
    #    arbitrary objects), since then sorting is not guaranteed to work
    if len(ar2) < 10 * len(ar1)**0.145 or contains_object:
        if invert:
            mask = np.ones(len(ar1), dtype=bool)
            for a in ar2:
                mask &= (ar1 != a)
        else:
            mask = np.zeros(len(ar1), dtype=bool)
            for a in ar2:
                mask |= (ar1 == a)
        return mask

    # Otherwise use sorting
    if not assume_unique:
        ar1, rev_idx = np.unique(ar1, return_inverse=True)
        ar2 = np.unique(ar2)

    ar = np.concatenate((ar1, ar2))
    # We need this to be a stable sort, so always use 'mergesort'
    # here. The values from the first array should always come before
    # the values from the second array.
    order = ar.argsort(kind='mergesort')
    sar = ar[order]
    if invert:
        bool_ar = (sar[1:] != sar[:-1])
    else:
        bool_ar = (sar[1:] == sar[:-1])
    flag = np.concatenate((bool_ar, [invert]))
    ret = np.empty(ar.shape, dtype=bool)
    ret[order] = flag

    if assume_unique:
        return ret[:len(ar1)]
    else:
        return ret[rev_idx]
Exemplo n.º 4
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    def test_unique_1d(self):
        def check_all(a, b, i1, i2, c, dt):
            base_msg = 'check {0} failed for type {1}'

            msg = base_msg.format('values', dt)
            v = unique(a)
            assert_array_equal(v, b, msg)

            msg = base_msg.format('return_index', dt)
            v, j = unique(a, 1, 0, 0)
            assert_array_equal(v, b, msg)
            assert_array_equal(j, i1, msg)

            msg = base_msg.format('return_inverse', dt)
            v, j = unique(a, 0, 1, 0)
            assert_array_equal(v, b, msg)
            assert_array_equal(j, i2, msg)

            msg = base_msg.format('return_counts', dt)
            v, j = unique(a, 0, 0, 1)
            assert_array_equal(v, b, msg)
            assert_array_equal(j, c, msg)

            msg = base_msg.format('return_index and return_inverse', dt)
            v, j1, j2 = unique(a, 1, 1, 0)
            assert_array_equal(v, b, msg)
            assert_array_equal(j1, i1, msg)
            assert_array_equal(j2, i2, msg)

            msg = base_msg.format('return_index and return_counts', dt)
            v, j1, j2 = unique(a, 1, 0, 1)
            assert_array_equal(v, b, msg)
            assert_array_equal(j1, i1, msg)
            assert_array_equal(j2, c, msg)

            msg = base_msg.format('return_inverse and return_counts', dt)
            v, j1, j2 = unique(a, 0, 1, 1)
            assert_array_equal(v, b, msg)
            assert_array_equal(j1, i2, msg)
            assert_array_equal(j2, c, msg)

            msg = base_msg.format(('return_index, return_inverse '
                                   'and return_counts'), dt)
            v, j1, j2, j3 = unique(a, 1, 1, 1)
            assert_array_equal(v, b, msg)
            assert_array_equal(j1, i1, msg)
            assert_array_equal(j2, i2, msg)
            assert_array_equal(j3, c, msg)

        a = [5, 7, 1, 2, 1, 5, 7] * 10
        b = [1, 2, 5, 7]
        i1 = [2, 3, 0, 1]
        i2 = [2, 3, 0, 1, 0, 2, 3] * 10
        c = np.multiply([2, 1, 2, 2], 10)

        # test for numeric arrays
        types = []
        types.extend(np.typecodes['AllInteger'])
        types.extend(np.typecodes['AllFloat'])
        types.append('datetime64[D]')
        types.append('timedelta64[D]')
        for dt in types:
            aa = np.array(a, dt)
            bb = np.array(b, dt)
            check_all(aa, bb, i1, i2, c, dt)

        # test for object arrays
        dt = 'O'
        aa = np.empty(len(a), dt)
        aa[:] = a
        bb = np.empty(len(b), dt)
        bb[:] = b
        check_all(aa, bb, i1, i2, c, dt)

        # test for structured arrays
        dt = [('', 'i'), ('', 'i')]
        aa = np.array(list(zip(a, a)), dt)
        bb = np.array(list(zip(b, b)), dt)
        check_all(aa, bb, i1, i2, c, dt)

        # test for ticket #2799
        aa = [1. + 0.j, 1 - 1.j, 1]
        assert_array_equal(np.unique(aa), [1. - 1.j, 1. + 0.j])

        # test for ticket #4785
        a = [(1, 2), (1, 2), (2, 3)]
        unq = [1, 2, 3]
        inv = [0, 1, 0, 1, 1, 2]
        a1 = unique(a)
        assert_array_equal(a1, unq)
        a2, a2_inv = unique(a, return_inverse=True)
        assert_array_equal(a2, unq)
        assert_array_equal(a2_inv, inv)

        # test for chararrays with return_inverse (gh-5099)
        a = np.chararray(5)
        a[...] = ''
        a2, a2_inv = np.unique(a, return_inverse=True)
        assert_array_equal(a2_inv, np.zeros(5))

        # test for ticket #9137
        a = []
        a1_idx = np.unique(a, return_index=True)[1]
        a2_inv = np.unique(a, return_inverse=True)[1]
        a3_idx, a3_inv = np.unique(a, return_index=True,
                                   return_inverse=True)[1:]
        assert_equal(a1_idx.dtype, np.intp)
        assert_equal(a2_inv.dtype, np.intp)
        assert_equal(a3_idx.dtype, np.intp)
        assert_equal(a3_inv.dtype, np.intp)
Exemplo n.º 5
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 def test_unique_zero_sized(self):
     # Ticket #205
     assert_array_equal([], np.unique(np.array([])))