Exemplo n.º 1
0
def odd_divisible_pandigitals():
    small_primes = prime_sieve(20)

    def sub_divides(number):
        if all( sub % prime == 0 for sub, prime
                in izip(substring_numbers(number,3,1),cycle(small_primes)) ):
            return True
        return False

    for pandigital in ifilter(sub_divides,pandigitals(10)):
        yield pandigital
Exemplo n.º 2
0
def smallest_odd_composite():
    def odd_numbers(start=1):
        num = start
        while True:
            yield num
            num += 2

    primes = set(prime_sieve(10000))
    odd_composites = ( i for i in odd_numbers(9)
            if i not in primes and i < 10000)

    for n in odd_composites:
        if any( (n - (2 * base ** 2)) in primes
                for base in xrange(1, (int(sqrt((n-2)/2))+1)) ):
            continue

        return n
Exemplo n.º 3
0
def largest_prime_seq(limit):
    primes = prime_sieve(limit)
    prime_set = set(primes)

    # determine the maximum allowable sequence length
    test_num = 0
    for max_seq_len, prime in enumerate(primes):
        test_num += prime
        if test_num > limit: break
        
    for length in xrange(max_seq_len,0,-1):
        for start in xrange(len(primes)-length):
            seq = primes[start:start+length]
            seq_sum = sum(seq)

            if seq_sum >= limit: break

            if seq_sum in prime_set:
                return seq
Exemplo n.º 4
0
# sum for a set of four primes with this property.
# 
# Find the lowest sum for a set of five primes for which any two 
# primes concatenate to produce another prime.

from itertools import dropwhile
from collections import defaultdict
from math import floor, log10

from p010 import prime_sieve
from p049 import is_prime

import psyco
psyco.full()

primes = prime_sieve(100000)
primes.remove(2) # Can never be in a set of more than one
primes.remove(5) # Can never be in a set of more than one

whitelist = defaultdict(set)
blacklist = defaultdict(set)
good_sets = defaultdict(list)

def is_concatenable_pair(x, y):
#    if y in blacklist[x]:
#        return False
    if y in whitelist[x]:
        return True
    if not (is_concatenable_combo(x, y) and is_concatenable_combo(y, x)):
        blacklist[x].add(y)
        return False