Exemplos de reverse_bisect_left em Python

Linguagem de programação: Python

Espaço para nome / nome do pacote: sentry.api.paginator

Método / Função: reverse_bisect_left

Exemplos em hotexamples.com: 2

reverse_bisect_left em Python - 2 exemplos encontrados. Esses são os exemplos do mundo real mais bem avaliados de sentry.api.paginator.reverse_bisect_left em Python extraídos de projetos de código aberto. Você pode avaliar os exemplos para nos ajudar a melhorar a qualidade deles.

Exemplo n.º 1

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Arquivo: test_paginator.py Projeto: andrzej-tests-1/sentry-app

def test_reverse_bisect_left(): assert reverse_bisect_left([], 0) == 0 assert reverse_bisect_left([1], -1) == 1 assert reverse_bisect_left([1], 0) == 1 assert reverse_bisect_left([1], 1) == 0 assert reverse_bisect_left([1], 2) == 0 assert reverse_bisect_left([2, 1], -1) == 2 assert reverse_bisect_left([2, 1], 0) == 2 assert reverse_bisect_left([2, 1], 1) == 1 assert reverse_bisect_left([2, 1], 2) == 0 assert reverse_bisect_left([2, 1], 3) == 0 assert reverse_bisect_left([3, 2, 1], -1) == 3 assert reverse_bisect_left([3, 2, 1], 0) == 3 assert reverse_bisect_left([3, 2, 1], 1) == 2 assert reverse_bisect_left([3, 2, 1], 2) == 1 assert reverse_bisect_left([3, 2, 1], 3) == 0 assert reverse_bisect_left([3, 2, 1], 4) == 0 assert reverse_bisect_left([4, 3, 2, 1], -1) == 4 assert reverse_bisect_left([4, 3, 2, 1], 0) == 4 assert reverse_bisect_left([4, 3, 2, 1], 1) == 3 assert reverse_bisect_left([4, 3, 2, 1], 2) == 2 assert reverse_bisect_left([4, 3, 2, 1], 3) == 1 assert reverse_bisect_left([4, 3, 2, 1], 4) == 0 assert reverse_bisect_left([4, 3, 2, 1], 5) == 0 assert reverse_bisect_left([1, 1], 0) == 2 assert reverse_bisect_left([1, 1], 1) == 0 assert reverse_bisect_left([1, 1], 2) == 0 assert reverse_bisect_left([2, 1, 1], 0) == 3 assert reverse_bisect_left([2, 1, 1], 1) == 1 assert reverse_bisect_left([2, 1, 1], 2) == 0 assert reverse_bisect_left([2, 2, 1], 0) == 3 assert reverse_bisect_left([2, 2, 1], 1) == 2 assert reverse_bisect_left([2, 2, 1], 2) == 0 assert reverse_bisect_left([3, 2, 1], 2, hi=10) == 1

Exemplo n.º 2

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Arquivo: test_paginator.py Projeto: alexandrul/sentry

def test_reverse_bisect_left(): assert reverse_bisect_left([], 0) == 0 assert reverse_bisect_left([1], -1) == 1 assert reverse_bisect_left([1], 0) == 1 assert reverse_bisect_left([1], 1) == 0 assert reverse_bisect_left([1], 2) == 0 assert reverse_bisect_left([2, 1], -1) == 2 assert reverse_bisect_left([2, 1], 0) == 2 assert reverse_bisect_left([2, 1], 1) == 1 assert reverse_bisect_left([2, 1], 2) == 0 assert reverse_bisect_left([2, 1], 3) == 0 assert reverse_bisect_left([3, 2, 1], -1) == 3 assert reverse_bisect_left([3, 2, 1], 0) == 3 assert reverse_bisect_left([3, 2, 1], 1) == 2 assert reverse_bisect_left([3, 2, 1], 2) == 1 assert reverse_bisect_left([3, 2, 1], 3) == 0 assert reverse_bisect_left([3, 2, 1], 4) == 0 assert reverse_bisect_left([4, 3, 2, 1], -1) == 4 assert reverse_bisect_left([4, 3, 2, 1], 0) == 4 assert reverse_bisect_left([4, 3, 2, 1], 1) == 3 assert reverse_bisect_left([4, 3, 2, 1], 2) == 2 assert reverse_bisect_left([4, 3, 2, 1], 3) == 1 assert reverse_bisect_left([4, 3, 2, 1], 4) == 0 assert reverse_bisect_left([4, 3, 2, 1], 5) == 0 assert reverse_bisect_left([1, 1], 0) == 2 assert reverse_bisect_left([1, 1], 1) == 0 assert reverse_bisect_left([1, 1], 2) == 0 assert reverse_bisect_left([2, 1, 1], 0) == 3 assert reverse_bisect_left([2, 1, 1], 1) == 1 assert reverse_bisect_left([2, 1, 1], 2) == 0 assert reverse_bisect_left([2, 2, 1], 0) == 3 assert reverse_bisect_left([2, 2, 1], 1) == 2 assert reverse_bisect_left([2, 2, 1], 2) == 0