def _sort_screenshots_by_best_version(self, screenshot_list):
""" take a screenshot result dict from screenshots.debian.org
and sort it
"""
from softwarecenter.utils import version_compare
my_version = self.version
# discard screenshots which are more recent than the available version
for item in screenshot_list[:]:
v = item["version"]
if v and version_compare(my_version, v) < 0:
screenshot_list.remove(item)
# now sort from high to low
return sorted(
screenshot_list, cmp=lambda a, b: version_compare(a["version"] or "", b["version"] or ""), reverse=True
)
def warning(self):
# apturl minver matches
if not self.pkg_state == PkgStates.INSTALLED:
if self._app.request:
minver_matches = re.findall(r'minver=[a-z,0-9,-,+,.,~]*',
self._app.request)
if minver_matches and self.version:
minver = minver_matches[0][7:]
from softwarecenter.utils import version_compare
if version_compare(minver, self.version) > 0:
return _("Version %s or later not available.") % minver
# can we enable a source
if not self._pkg:
source_to_enable = None
if self.channelname and self._unavailable_channel():
source_to_enable = self.channelname
elif (self.component and
self.component not in ("independent", "commercial")):
source_to_enable = self.component
if source_to_enable:
sources = source_to_enable.split('&')
sources_length = len(sources)
if sources_length == 1:
warning = (_("Available from the \"%s\" source.") %
sources[0])
elif sources_length > 1:
# Translators: the visible string is constructed
# concatenating the following 3 strings like this:
# Available from the following sources: %s, ... %s, %s.
warning = _("Available from the following sources: ")
# Cycle through all, but the last
for source in sources[:-1]:
warning += _("\"%s\", ") % source
warning += _("\"%s\".") % sources[sources_length - 1]
return warning
def _sort_screenshots_by_best_version(self, screenshot_list):
""" take a screenshot result dict from screenshots.debian.org
and sort it
"""
from softwarecenter.utils import version_compare
my_version = self.version
# discard screenshots which are more recent than the available version
for item in screenshot_list[:]:
v = item['version']
if v and version_compare(my_version, v) < 0:
screenshot_list.remove(item)
# now sort from high to low
return sorted(screenshot_list,
cmp=lambda a, b: version_compare(a["version"] or '', b[
"version"] or ''),
reverse=True)
