ts += 1
tiranum = tria(ts)
if tiranum == current:
equal += 1
break
elif tiranum < current:
pass
else:
current = tiranum
ref = 0
break
# the hexagonal loop
while True:
ps += 1
pentnum = pent(ps)
if pentnum == current:
equal += 1
break
elif pentnum < current:
pass
else:
current = pentnum
ref = 1
break
# if triangle == pentagonal == hexagonal
if equal == 2:
return current, ts, ps, hs
print solve()
print runningTime('solve()', 10)
return sum([x*x for x in mathlib.getDigits(num)])
def solve():
to01, to89 = [1], [89]
result = 10000000 - 1
for ref in range(1, 9*9*7+1):
if ref == 1 or ref == 89:
pass
else:
i = squareAdd(ref)
while True:
if i in to89:
to89.append(ref)
break
elif i in to01:
to01.append(ref)
break
else:
i = squareAdd(i)
for num in range(1, 10000000):
if squareAdd(num) in to01:
result -= 1
else:
pass
return result
print solve()
print utillib.runningTime("solve()", 1)
# way, we note the following:
# * d2d3d4=406 is divisible by 2
# * d3d4d5=063 is divisible by 3
# * d4d5d6=635 is divisible by 5
# * d5d6d7=357 is divisible by 7
# * d6d7d8=572 is divisible by 11
# * d7d8d9=728 is divisible by 13
# * d8d9d10=289 is divisible by 17
# Find the sum of all 0 to 9 pandigital numbers with this property.
#brute force method~
def solveSlow():
numbers = mathlib.permute(list('1234567890'))
result = 0
for item in numbers:
if int(item[7:10]) % 17 == 0:
if int(item[6:9]) % 13 == 0:
if int(item[5:8]) % 11 == 0:
if int(item[4:7]) % 7 == 0:
if int(item[3:6]) % 5 == 0:
if int(item[2:5]) % 3 == 0:
if int(item[1:4]) % 2 == 0:
result += int(item)
return result
print solveSlow()
print utillib.runningTime('solveSlow()', 1)