Exemplo n.º 1
0
def is_pandigital(n):
    return len(used_digits(n)) == num_digits(n)
Exemplo n.º 2
0
def is_pandigital(n):
    return len(used_digits(n)) == num_digits(n)
Exemplo n.º 3
0
# Author: Deddryk
"""
Solution to problem 38

"""

from utils.misc import used_digits, num_digits


def is_pandigital(n):
    return len(used_digits(n)) == num_digits(n)


concatenated_pandigitals = set()
for i in xrange(10, 10000):
    multiplier = 1
    concatenated_product = 0
    while num_digits(concatenated_product) < 9:
        next_part = i * multiplier
        multiplier += 1
        concatenated_product = concatenated_product * 10**num_digits(
            next_part) + next_part
        if not is_pandigital(concatenated_product): break
        if 0 in used_digits(concatenated_product): break
    else:
        if num_digits(concatenated_product) == 9:
            concatenated_pandigitals.add(concatenated_product)
print max(concatenated_pandigitals)
Exemplo n.º 4
0
# Author: Deddryk

"""
Solution to problem 38

"""

from utils.misc import used_digits, num_digits


def is_pandigital(n):
    return len(used_digits(n)) == num_digits(n)


concatenated_pandigitals = set()
for i in xrange(10, 10000):
    multiplier = 1
    concatenated_product = 0
    while num_digits(concatenated_product) < 9:
        next_part = i * multiplier
        multiplier += 1
        concatenated_product = concatenated_product * 10 ** num_digits(next_part) + next_part
        if not is_pandigital(concatenated_product):
            break
        if 0 in used_digits(concatenated_product):
            break
    else:
        if num_digits(concatenated_product) == 9:
            concatenated_pandigitals.add(concatenated_product)
print max(concatenated_pandigitals)