Exemplo n.º 1
0
    def test_job_graph_allows_soft_dependencies(self):
        parent = model.Job('parent')
        child = model.Job('child')
        child.dependencies = frozenset(
            [model.JobDependency(parent.name, True)])

        # With the parent
        graph = model.JobGraph()
        graph.addJob(parent)
        graph.addJob(child)
        self.assertEqual(graph.getParentJobsRecursively(child.name), [parent])

        # Skip the parent
        graph = model.JobGraph()
        graph.addJob(child)
        self.assertEqual(graph.getParentJobsRecursively(child.name), [])
Exemplo n.º 2
0
    def test_job_graph_disallows_circular_dependencies(self):
        graph = model.JobGraph()
        jobs = [model.Job('job%d' % i) for i in range(0, 10)]
        prevjob = None
        for j in jobs[:3]:
            if prevjob:
                j.dependencies = frozenset([model.JobDependency(prevjob.name)])
            graph.addJob(j)
            prevjob = j
        # 0 triggers 1 triggers 2 triggers 3...

        # Cannot depend on itself
        with testtools.ExpectedException(
                Exception, "Dependency cycle detected in job jobX"):
            j = model.Job('jobX')
            j.dependencies = frozenset([model.JobDependency(j.name)])
            graph.addJob(j)

        # Disallow circular dependencies
        with testtools.ExpectedException(
                Exception, "Dependency cycle detected in job job3"):
            jobs[4].dependencies = frozenset(
                [model.JobDependency(jobs[3].name)])
            graph.addJob(jobs[4])
            jobs[3].dependencies = frozenset(
                [model.JobDependency(jobs[4].name)])
            graph.addJob(jobs[3])

        jobs[5].dependencies = frozenset([model.JobDependency(jobs[4].name)])
        graph.addJob(jobs[5])

        with testtools.ExpectedException(
                Exception, "Dependency cycle detected in job job3"):
            jobs[3].dependencies = frozenset(
                [model.JobDependency(jobs[5].name)])
            graph.addJob(jobs[3])

        jobs[3].dependencies = frozenset([model.JobDependency(jobs[2].name)])
        graph.addJob(jobs[3])
        jobs[6].dependencies = frozenset([model.JobDependency(jobs[2].name)])
        graph.addJob(jobs[6])
Exemplo n.º 3
0
    def test_job_graph_allows_soft_dependencies4(self):
        # A more complex scenario with multiple parents at each level
        parents = [model.Job('parent%i' % i) for i in range(6)]
        child = model.Job('child')
        child.dependencies = frozenset([
            model.JobDependency(parents[0].name, True),
            model.JobDependency(parents[1].name)
        ])
        parents[0].dependencies = frozenset([
            model.JobDependency(parents[2].name),
            model.JobDependency(parents[3].name, True)
        ])
        parents[1].dependencies = frozenset([
            model.JobDependency(parents[4].name),
            model.JobDependency(parents[5].name)
        ])
        # Run them all
        graph = model.JobGraph()
        for j in parents:
            graph.addJob(j)
        graph.addJob(child)
        self.assertEqual(set(graph.getParentJobsRecursively(child.name)),
                         set(parents))

        # Skip first parent, therefore its recursive dependencies don't appear
        graph = model.JobGraph()
        for j in parents:
            if j is not parents[0]:
                graph.addJob(j)
        graph.addJob(child)
        self.assertEqual(
            set(graph.getParentJobsRecursively(child.name)),
            set(parents) - set([parents[0], parents[2], parents[3]]))

        # Skip a leaf node
        graph = model.JobGraph()
        for j in parents:
            if j is not parents[3]:
                graph.addJob(j)
        graph.addJob(child)
        self.assertEqual(set(graph.getParentJobsRecursively(child.name)),
                         set(parents) - set([parents[3]]))