Пример #1
0
def solution(myLinked):
    list = []
    size = len(myLinked)

    nowLinked = myLinked.head

    if size % 2 == 1:
        for i in range(int(size / 2)):
            list.append(nowLinked.value)
            nowLinked = nowLinked.next
        nowLinked = nowLinked.next

    else:
        for i in range(size / 2):
            list.append(nowLinked.value)
            nowLinked = nowLinked.next

    flag = True
    for i in range(1, int(size / 2) + 1):
        reverse = i * -1
        if (list[(-1) * i] != nowLinked.value):
            flag = False
        nowLinked = nowLinked.next
    return flag


ll_true = LinkedList([1, 2, 3, 4, 5, 4, 3, 2, 1])
print(solution(ll_true))
ll_false = LinkedList([1, 2, 3, 4, 5, 6, 7, 8, 9])
print(solution(ll_false))
def check10(longllData):
    if longllData.value > 10:
        longllData.next.value = longllData.next.value + 1
        longllData.value = longllData.value - 10


def solution(ll1, ll2):
    longll, shortll = ll1 if len(ll1) >= len(ll2) else ll2, ll1 if len(
        ll1) < len(ll2) else ll2
    nowLong = longll.head
    nowShort = shortll.head

    for i in range(len(shortll)):
        nowLong.value = nowLong.value + nowShort.value
        check10(nowLong)
        nowLong = nowLong.next
        nowShort = nowShort.next

    check10(nowLong)


ll_a = LinkedList()
ll_a.generate(2, 0, 9)
ll_b = LinkedList()
ll_b.generate(3, 0, 9)

solution(ll_a, ll_b)

print(ll_b)
Пример #3
0
from Chap2.LinkedList import LinkedList


def partition(ll, key):
    befLL = LinkedList()
    aftLL = LinkedList()
    keyLL = LinkedList()

    now = ll.head
    for _ in range(len(ll)):

        if now.value > key:
            aftLL.add(now.value)
        elif now.value == key:
            keyLL.add(now.value)
        elif now.value < key:
            befLL.add(now.value)
        now = now.next

    befLL.add_multiple(keyLL)
    befLL.add_multiple(aftLL)
    print(befLL)


ll = LinkedList()
ll.add_multiple([3, 5, 8, 5, 10, 2, 1])
key = 5
partition(ll, key)
Пример #4
0
def partition(ll, key):
    befLL = LinkedList()
    aftLL = LinkedList()
    keyLL = LinkedList()

    now = ll.head
    for _ in range(len(ll)):

        if now.value > key:
            aftLL.add(now.value)
        elif now.value == key:
            keyLL.add(now.value)
        elif now.value < key:
            befLL.add(now.value)
        now = now.next

    befLL.add_multiple(keyLL)
    befLL.add_multiple(aftLL)
    print(befLL)
Пример #5
0
from Chap2.LinkedList import LinkedList


def deleteMiddle(node):  #두 문장의 순서도 중요하다, 값 먼저 바꾸고 next 변경
    node.value = node.next.value
    node.next = node.next.next


ll = LinkedList()
ll.add_multiple([1, 2, 3, 4])
middle_node = ll.add(5)
ll.add_multiple([7, 8, 9])

print(ll)
deleteMiddle(middle_node)
print(ll)

#헤드 접근 없이 삭제할 노드에만 접근이 가능하다는 것 / 나는 c에는 접근할 수 있다.