Пример #1
0
def cloneTree(root: TreeNode) -> TreeNode:
    if root:
        newRoot = TreeNode(root.val)
        newRoot.left = cloneTree(root.left)
        newRoot.right = cloneTree(root.right)
        return newRoot
    return None
 def convertBSTImpl(root: TreeNode, v: int) -> (TreeNode, int):
     if not root:
         return None, 0
     newRight, sumRight = convertBSTImpl(root.right, v)
     newRoot = TreeNode(root.val + sumRight + v)
     newLeft, sumLeft = convertBSTImpl(root.left, newRoot.val)
     newRoot.left = newLeft
     newRoot.right = newRight
     return newRoot, sumLeft + root.val + sumRight
Пример #3
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 def trimBST(self, root: TreeNode, low: int, high: int) -> TreeNode:
     if not root:
         return None
     if root.val > high:
         return self.trimBST(root.left, low, high)
     if root.val < low:
         return self.trimBST(root.right, low, high)
     root.left = self.trimBST(root.left, low, high)
     root.right = self.trimBST(root.right, low, high)
     return root
Пример #4
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 def helper(beg: int, end: int) -> TreeNode:
     if beg > end:
         return None
     mid = beg + (end - beg) // 2
     left = helper(beg, mid - 1)
     root = TreeNode(self.head.val)
     self.head = self.head.next
     root.left = left
     root.right = helper(mid + 1, end)
     return root
Пример #5
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 def impl(pre_b: int, pre_e: int, in_b: int, in_e: int) -> TreeNode:
     if pre_b == pre_e:
         return None
     val = preorder[pre_b]
     root = TreeNode(val)
     m = inorder_index[val]
     left_end = pre_b + 1 + m - in_b
     root.left = impl(pre_b + 1, left_end, in_b, m)
     root.right = impl(left_end, pre_e, m + 1, in_e)
     return root
Пример #6
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        def impl(root: TreeNode) -> TreeNode:
            if not root:
                return None
            left_end = impl(root.left)
            right_end = impl(root.right)
            right = root.right
            root.right = root.left
            root.left = None
            if left_end:
                left_end.right = right
            else:
                root.right = right

            if right_end:
                return right_end
            if left_end:
                return left_end

            return root
Пример #7
0
Runtime: 40 ms, faster than 89.58% of Python3 online submissions for Path Sum.
Memory Usage: 15.4 MB, less than 98.89% of Python3 online submissions for Path Sum.
"""
class Solution:
    def hasPathSum(self, root: TreeNode, sum: int) -> bool:
        if root is None:
            return False
        if root.left is None and root.right is None:
            return sum == root.val
        if self.hasPathSum(root.left, sum - root.val):
            return True
        return self.hasPathSum(root.right, sum - root.val)


t1 = TreeNode(5)
t1.left = TreeNode(4)
t1.right = TreeNode(8)

t1.left.left = TreeNode(11)
t1.left.left.left = TreeNode(7)
t1.left.left.right = TreeNode(2)

t1.right.left = TreeNode(13)
t1.right.right = TreeNode(4)

t1.right.right.right = TreeNode(1)

tests = [
    (t1, 22, True)
]
# Memory Usage: 18.8 MB, less than 5.07% of Python3 online submissions for Convert BST to Greater Tree.
from Common.Leetcode import TreeNode
from Common.TreeUtils import printTree


class Solution:
    def convertBST(self, root: TreeNode) -> TreeNode:
        def convertBSTImpl(root: TreeNode, v: int) -> (TreeNode, int):
            if not root:
                return None, 0
            newRight, sumRight = convertBSTImpl(root.right, v)
            newRoot = TreeNode(root.val + sumRight + v)
            newLeft, sumLeft = convertBSTImpl(root.left, newRoot.val)
            newRoot.left = newLeft
            newRoot.right = newRight
            return newRoot, sumLeft + root.val + sumRight

        return convertBSTImpl(root, 0)[0]


root1 = TreeNode(4)
root1.left = TreeNode(1)
root1.right = TreeNode(6)
root1.left.left = TreeNode(0)
root1.left.right = TreeNode(2)
root1.left.right.right = TreeNode(3)
root1.right.left = TreeNode(5)
root1.right.right = TreeNode(7)
root1.right.right.right = TreeNode(8)

printTree(Solution().convertBST(root1))
            if L[1] > R[1]:
                return L[0], L[1] + 1
            if R[1] > L[1]:
                return R[0], R[1] + 1
            return root, L[1] + 1
        return dfs(root)[0]


def printTree(root: TreeNode):
    def printTreeImpl(root: TreeNode):
        if root is None:
            return
        printTreeImpl(root.left)
        print(root.val, ' ', end='')
        printTreeImpl(root.right)
    printTreeImpl(root)
    print()


root = TreeNode(3)
root.left = TreeNode(5)
root.left.left = TreeNode(6)
root.left.right = TreeNode(2)
root.left.right.left = TreeNode(7)
root.left.right.right = TreeNode(4)
root.right = TreeNode(1)
root.right.left = TreeNode(0)
root.right.right = TreeNode(8)

res = Solution().lcaDeepestLeaves(root)
printTree(res)
Пример #10
0

class Solution:
    @staticmethod
    def isLeave(root: TreeNode):
        return root.left is None and root.right is None

    def sumOfLeftLeavesImpl(self, root: TreeNode, isLeft: bool) -> int:
        if Solution.isLeave(root):
            return root.val if isLeft else 0
        sumleft = sumright = 0
        if root.left:
            sumleft = self.sumOfLeftLeavesImpl(root.left, True)
        if root.right:
            sumright = self.sumOfLeftLeavesImpl(root.right, False)
        return sumleft + sumright

    def sumOfLeftLeaves(self, root: TreeNode) -> int:
        if root is None:
            return 0
        return self.sumOfLeftLeavesImpl(root, False)


t1 = TreeNode(3)
t1.left = TreeNode(9)
t1.right = TreeNode(20)
t1.right.left = TreeNode(15)
t1.right.right = TreeNode(7)

print(Solution().sumOfLeftLeaves(t1))  # 24
        if root is None:
            return 0

        dl = dr = 0

        if root.left:
            dl = self.minDepth(root.left)

        if root.right:
            dr = self.minDepth(root.right)

        if dl > 0 and dr > 0:
            return 1 + min(dl, dr)

        if dl > 0:
            return dl + 1
        return dr + 1


tree1 = TreeNode(3)
tree1.left = TreeNode(9)
tree1.right = TreeNode(20)
tree1.right.left = TreeNode(15)
tree1.right.right = TreeNode(7)

tree2 = TreeNode(1)
tree2.left = TreeNode(2)

tests = [(tree1, 2), (tree2, 2)]

run_functional_tests(Solution().minDepth, tests)
Пример #12
0
class Solution:
    def binaryTreePaths(self, root: TreeNode) -> List[str]:
        def binaryTreePathsImpl(root: TreeNode, result: List[str], path: str):
            if root is None:
                return
            newpath: str = path
            if len(newpath) > 0:
                newpath += "->"
            newpath += str(root.val)
            if root.left is None and root.right is None:
                result.append(newpath)
            else:
                if root.left is not None:
                    binaryTreePathsImpl(root.left, result, newpath)
                if root.right is not None:
                    binaryTreePathsImpl(root.right, result, newpath)

        result: List[str] = []
        binaryTreePathsImpl(root, result, "")
        return result


t1 = TreeNode(1)
t1.left = TreeNode(2)
t1.left.right = TreeNode(5)
t1.right = TreeNode(3)

tests = [(t1, ['1->2->5', '1->3'])]

run_functional_tests(Solution().binaryTreePaths, tests)
Пример #13
0
        self.verticalTraversalImpl(cache, root, 0, 0)

        result: List[List[int]] = []

        for d in sorted(cache):
            result.append([])
            for s in sorted(cache[d]):
                for v in sorted(cache[d][s]):
                    result[-1].append(v)

        return result

# [0,2,1,3,null,null,null,4,5,null,7,6,null,10,8,11,9]

root1 = TreeNode(3)
root1.left = TreeNode(9)
root1.right = TreeNode(20)
root1.right.left = TreeNode(15)
root1.right.right = TreeNode(7)

root2 = TreeNode(1)
root2.left = TreeNode(2)
root2.left.left = TreeNode(4)
root2.left.right = TreeNode(5)
root2.right = TreeNode(3)
root2.right.left = TreeNode(6)
root2.right.right = TreeNode(7)

tests = [
    (root1, [[9],[3,15],[20],[7]]),
    (root2, [[4],[2],[1,5,6],[3],[7]])
            if not current.left and not current.right:
                if len(nodes) <= 1:
                    result += 1
            dfs(current.left)
            dfs(current.right)
            if current.val in nodes:
                nodes.remove(current.val)
            else:
                nodes.append(current.val)

        dfs(root)
        return result


root1 = TreeNode(2)
root1.left = TreeNode(3)
root1.left.left = TreeNode(3)
root1.left.right = TreeNode(1)
root1.right = TreeNode(1)
root1.right.right = TreeNode(1)

# if Solution().pseudoPalindromicPaths(root1) == 2:
#     print("PASS")
# else:
#     print("FAIL")

root2 = TreeNode(2)
root2.left = TreeNode(1)
root2.left.left = TreeNode(1)
root2.left.right = TreeNode(3)
root2.left.right.right = TreeNode(1)