def remove(map, key):
    """
    Elimina la pareja llave,valor, donde llave == key.
    Args:
        map: La tabla de simbolos
        key: La llave asociada a la pareja
    Returns:
        La tabla de simbolos
    Raises:
        Exception
    """
    if (map['type'] == 'BST'):
        return bst.remove(map, key)
    else:
        return rbt.remove(map, key)
Пример #2
0
def test_remove(tree):
    tree = bst.put(tree, 21, 'book21')
    tree = bst.put(tree, 7, 'book7')
    tree = bst.put(tree, 30, 'book30')
    tree = bst.put(tree, 5, 'book5')
    tree = bst.put(tree, 4, 'book4')
    tree = bst.put(tree, 3, 'book3')
    tree = bst.put(tree, 20, 'book20')
    tree = bst.put(tree, 25, 'book25')
    tree = bst.put(tree, 35, 'book35')
    tree = bst.put(tree, 29, 'book29')
    tree = bst.put(tree, 11, 'book11')
    tree = bst.put(tree, 15, 'book15')
    tree = bst.remove(tree, 21)
    tree = bst.put(tree, 10, 'book10')
    tree = bst.put(tree, 10, 'book10A')
    assert bst.contains(tree, 29) is True
    assert bst.contains(tree, 28) is False
    assert bst.minKey(tree) == 3
    assert bst.maxKey(tree) == 35
    bst.deleteMin(tree)
    assert bst.contains(tree, 3) is False