Пример #1
0
def is_palindrome(node):
    if node is None or node.nxt is None:
        return True

    s = Stack()
    a = b = node
    s.push(b)
    l = 1

    while a is not None and a.nxt is not None:
        a = a.nxt
        l += 1

        b = b.nxt
        s.push(b)

        a = a.nxt

        if a:
            l += 1

    s.pop()

    if l % 2 != 0:
        b = b.nxt

    while b is not None:
        if b.data != s.pop().data:
            return False

        b = b.nxt

    return True
Пример #2
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def find_celebrity(array):
    s = Stack()

    for ppl in array:
        s.push(ppl)

    a = s.pop()
    b = s.pop()

    while not s.is_empty():
        if does_a_know_b(a, b):
            a = s.pop()
        else:
            b = s.pop()

    if does_a_know_b(a, b):
        c = b
    else:
        c = a

    for person in array:
        if does_a_know_b(c, person) or not does_a_know_b(person, c):
            return None

    return c
Пример #3
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def evaluate(exp):
    s = Stack()

    i = 0
    while i < len(exp):
        if not is_operator(exp[i]):
            s.push(int(exp[i]))

        else:
            val1 = s.pop()
            val2 = s.pop()

            if exp[i] == '+':
                s.push(val1 + val2)

            elif exp[i] == '-':
                s.push(val2 - val1)

            elif exp[i] == '*':
                s.push(val1 * val2)

            elif exp[i] == '/':
                s.push(val2 / val1)

            else:
                s.push(val2 % val1)

    return s.pop()
Пример #4
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def is_leaf_order_same(root1, root2):
    s1 = Stack()
    s2 = Stack()

    done1 = False
    done2 = False

    val1 = None
    val2 = None

    curr1 = root1
    curr2 = root2

    while True:

        while not done1:
            if curr1:
                s1.push(curr1)
                curr1 = curr1.left
            else:
                if s1.is_empty():
                    done1 = True
                    val1 = None
                else:
                    curr1 = s1.pop()
                    val1 = curr1.data
                    if is_leaf(curr1):
                        done1 = True
                    curr1 = curr1.right

        while not done2:
            if curr2:
                s2.push(curr2)
                curr2 = curr2.left
            else:
                if s2.is_empty():
                    done2 = True
                    val2 = None
                else:
                    curr2 = s2.pop()
                    val2 = curr2.data
                    if is_leaf(curr2):
                        done2 = True
                    curr2 = curr2.right

        if done1 and done2:
            if val1 != val2:
                return False
            else:
                done1 = False
                done2 = False

        if val1 is None and val2 is None:
            return True

        if val1 is None or val2 is None:
            return False
Пример #5
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def is_sum_pair_present(root, target):
    s1 = Stack()
    s2 = Stack()

    done1 = False
    done2 = False

    val1 = None
    val2 = None

    curr1 = root
    curr2 = root

    while True:

        # in order
        while not done1:
            if curr1:
                s1.push(curr1)
                curr1 = curr1.left
            else:
                if s1.is_empty():
                    done1 = True
                else:
                    curr1 = s1.pop()
                    val1 = curr1.data
                    curr1 = curr1.right
                    done1 = True

        # reverse in order
        while not done2:
            if curr2:
                s2.push(curr2)
                curr2 = curr2.right
            else:
                if s2.is_empty():
                    done2 = True
                else:
                    curr2 = s2.pop()
                    val2 = curr2.data
                    curr2 = curr2.left
                    done2 = True

        # val1 != val2 makes sure that two of same values are not added
        if val1 != val2 and val1 + val2 == target:
            print 'pair found: {0} and {1}'.format(val1, val2)
            return True

        elif val1 + val2 < target:
            done1 = False

        elif val1 + val2 > target:
            done2 = False

        if val2 <= val1:
            return False
Пример #6
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def is_valid(string):
    s = Stack()
    for c in string:
        if c == 'a':
            s.push(c)
        elif c == 'b' and not s.is_empty():
            s.pop()
        else:
            return False

    return s.is_empty()
Пример #7
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def nge(array):
    s = Stack()

    for num in array:
        while not s.is_empty() and s.peek() < num:
            print s.pop(), '-', num

        s.push(num)

    while not s.is_empty():
        print s.pop(), '-', -1
Пример #8
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def simplify_linux_dir_path(path):
    places = [p for p in path.split("/") if p != "." and p != ""]
    s = Stack()

    for p in places:
        if p == ".." and not s.is_empty():
            s.pop()

        else:
            s.push(p)

    return "/" + '/'.join(s.get_list())
Пример #9
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def build_lowest_number_removing_k_digits(num, k):
    s = Stack()
    l = len(num) - k

    for c in num:
        if not s.is_empty() and int(s.peek()) > int(c) and k > 0:
            s.pop()
            k -= 1

        s.push(c)

    return ''.join(s.get_list()[:l])
Пример #10
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def nge(array):
    _nge = [-1 for i in array]
    s = Stack()

    for i in range(len(array)):
        element = array[i]

        while not s.is_empty() and element > array[s.peek()]:
            _nge[s.peek()] = i
            s.pop()

        s.push(i)

    return _nge
Пример #11
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def get_balanced_stack(string):
    s = Stack()

    for c in string:
        if c == '{' or s.is_empty():
            s.push(c)

        else:
            if s.peek() == '{':
                s.pop()

            else:
                s.push(c)

    return s
Пример #12
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def dupe_found(string):
    s = Stack()
    for c in string:
        exp = ""
        if c != ')':
            s.push(c)
        else:
            while not s.is_empty() and s.peek() != '(':
                char = s.pop()
                exp += char

            if not is_exp(exp):
                return True
            s.pop()

    return False
Пример #13
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def largest_valid_substring(string):
    stack = Stack()

    l_index = None
    r_index = None

    min_index = None
    max_index = None

    max_diff = 0

    for i in range(len(string)):
        if string[i] == '(':
            stack.push(i)
        elif string[i] == ')':
            try:
                l_index = stack.pop()
                r_index = i
            except Exception:
                pass

        if None not in [l_index, r_index]:
            diff = r_index - l_index
            if diff > max_diff:
                max_diff = diff
                min_index = l_index
                max_index = r_index

    if None in [l_index, r_index]:
        return None
    else:
        return string[min_index:max_index + 1]
def compute_left_smaller_diffs(array):
    s = Stack()
    diff_array = [None for i in array]

    for i in range(len(array)):
        element = array[i]
        while not s.is_empty() and s.peek() > element:
            s.pop()

        if s.is_empty():
            diff_array[i] = 0
        else:
            diff_array[i] = s.peek()

        s.push(element)

    return diff_array
Пример #15
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def calculate_span(stocks):
    spans = [-1 for i in stocks]
    s = Stack()
    s.push(-1)
    spans[0] = 1

    for i in range(len(stocks)):
        # pop until we find a taller element in stack
        while s.peek() != -1 and stocks[s.peek()] <= stocks[i]:
            s.pop()

        # calculate span
        spans[i] = i - s.peek()

        s.push(i)

    return spans
Пример #16
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def iterative_post_order(root):
    s1 = Stack()
    s2 = Stack()

    s1.push(root)

    while not s1.is_empty():
        node = s1.pop()
        if node.left:
            s1.push(node.left)

        if node.right:
            s1.push(node.right)

        s2.push(node)

    while not s2.is_empty():
        print s2.pop(),
def find_largest_area(hist):
    s = Stack()
    n = len(hist)

    max_area = 0

    i = 0
    while i < n:

        # Push as long as stack top is smaller
        if s.is_empty() or hist[s.peek()] <= hist[i]:
            s.push(i)
            i += 1

        else:
            # pop one by one and calculate area considering, the popped
            # elements height as the smallest. notice we are not
            # incrementing i here. Hence we keep popping until we find
            # a smaller height
            s_top = s.pop()

            # width is from top to i, but not including i
            width = i if s.is_empty() else i - s.peek() - 1
            area_with_top_as_smallest = hist[s_top] * width

            if max_area < area_with_top_as_smallest:
                max_area = area_with_top_as_smallest

    # pop entire stack to consider all elements
    while not s.is_empty():

        s_top = s.pop()

        # here i is N, so width will be from top to N, not
        # including N
        width = i if s.is_empty() else i - s.peek() - 1
        area_with_top_as_smallest = hist[s_top] * width

        if max_area < area_with_top_as_smallest:
            max_area = area_with_top_as_smallest

    return max_area
Пример #18
0
class Queue2(object):
    def __init__(self):
        self.stack1 = Stack()
        self.stack2 = Stack()

    def push(self, element):
        self.stack1.push(element)

    def pop(self):
        if self.stack2.is_empty():
            while not self.stack1.is_empty():
                self.stack2.push(self.stack1.pop())

        return self.stack2.pop()

    def peek(self):
        if self.stack2.is_empty():
            while not self.stack1.is_empty():
                self.stack2.push(self.stack1.pop())

        return self.stack2.peek()
Пример #19
0
class Queue3(object):
    def __init__(self):
        self.stack = Stack()
        self.element_to_pop = None
        self.element_to_peek = None

    def push(self, element):
        self.stack.push(element)

    def _pop(self):
        if not self.stack.is_empty():
            el = self.stack.pop()
            self._pop()

            if self.element_to_pop is None:
                self.element_to_pop = el
            else:
                self.stack.push(el)

    def _peek(self):
        if not self.stack.is_empty():
            el = self.stack.pop()
            self._pop()

            if self.element_to_pop is None:
                self.element_to_pop = el

            self.stack.push(el)

    def pop(self):
        self._pop()
        el = self.element_to_pop
        self.element_to_pop = None
        return el

    def peek(self):
        self._pop()
        el = self.element_to_pop
        self.element_to_peek = None
        return el
def convert(exp):
    k = -1
    exp = list(exp)

    s = Stack()

    for i in range(len(exp)):

        if is_operand(exp[i]):
            k += 1
            exp[k] = exp[i]

        elif exp[i] == '(':
            s.push(exp[i])

        elif exp[i] == ')':
            while not s.is_empty() and s.peek() != '(':
                k += 1
                exp[k] = s.pop()

            if not s.is_empty() and s.peek() != '(':
                return -1

            else:
                s.pop()  # pop off the '('

        else:
            while not s.is_empty() and precedence(exp[i]) <= precedence(
                    s.peek()):
                k += 1
                exp[k] = s.pop()

            s.push(exp[i])

    while not s.is_empty():
        k += 1
        exp[k] = s.pop()

    return ''.join(exp)[0:k + 1]
Пример #21
0
def iterative_pre_order(root):
    s = Stack()
    s.push(root)

    while not s.is_empty():
        node = s.pop()
        print node,

        if node.right:
            s.push(node.right)

        if node.left:
            s.push(node.left)
def find_max_len(string):
    n = len(string)
    result = 0

    s = Stack()
    s.push(-1)

    for i in range(n):
        if string[i] == '(':
            s.push(i)

        else:

            s.pop()

            if not s.is_empty():
                result = max(result, i - s.peek())

            else:
                s.push(i)

    return result
Пример #23
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def iterative_dfs(graph, source):
    s = Stack()
    s.push(source)
    visited = [False for i in graph.keys()]

    while not s.is_empty():
        node = s.pop()

        visited[node] = True

        for neighbour in graph[node]:
            if not visited[neighbour]:
                s.push(neighbour)
Пример #24
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def print_min_number(sequence):
    result = []
    s = Stack()

    for i in range(len(sequence) + 1):
        s.push(i + 1)

        if i == len(sequence) or sequence[i] == 'I':

            while not s.is_empty():
                result.append(s.pop())

    print ''.join(map(str, result))
Пример #25
0
def is_pre_order(array):
    s = Stack()
    root = -maxint

    for value in array:
        while not s.is_empty() and s.peek() < value:
            root = s.pop()

        if value < root:
            return False

        s.push(value)

    return True
Пример #26
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def spiral_print(root):
    s1 = Stack()
    s2 = Stack()
    s1.push(root)

    while not s1.is_empty() or not s2.is_empty():
        while not s1.is_empty():
            node = s1.pop()
            print node,

            if node.left:
                s2.push(node.left)
            if node.right:
                s2.push(node.right)

        while not s2.is_empty():
            node = s2.pop()
            print node,

            if node.right:
                s1.push(node.right)
            if node.left:
                s1.push(node.left)
def merge_overlapping_intervals(array):
    # sort based on start time
    array.sort()
    s = Stack()
    s.push(array[0])

    for i in range(1, len(array)):
        if not s.is_empty():
            element = s.pop()
            curr_element = array[i]
            if is_overlapping(element, curr_element):
                s.push(merge(element, curr_element))
            else:
                s.push(element)
                s.push(curr_element)

    print [(i.start, i.end) for i in s.items]
Пример #28
0
def print_common_nodes(root1, root2):
    s1 = Stack()
    s2 = Stack()

    while True:
        # push left nodes of trees to stack
        if root1:
            s1.push(root1)
            root1 = root1.left

        elif root2:
            s2.push(root2)
            root2 = root2.left

        elif not s1.is_empty() and not s2.is_empty():
            root1 = s1.peek()
            root2 = s2.peek()

            if root1.data == root2.data:
                # found match, check next in both trees
                print root1.data,
                s1.pop()
                s2.pop()

                root1 = root1.right
                root2 = root2.right

            elif root1.data < root2.data:
                # move to next node in first tree
                s1.pop()
                root1 = root1.right

                # set this to none or in the next iteration it gets
                # pushed to s2 again
                root2 = None

            else:
                s2.pop()
                root2 = root2.right
                root1 = None

        else:
            break
Пример #29
0
def iterative_in_order(root):
    current = root
    s = Stack()
    done = False

    while not done:
        if current is not None:
            s.push(current)
            current = current.left

        else:
            if not s.is_empty():
                current = s.pop()
                print current,

                current = current.right
            else:
                done = True
Пример #30
0
from G4G.Problems.stack.stack import Stack


def insert_at_bottom(stack, element):
    if stack.is_empty():
        stack.push(element)

    else:
        el = stack.pop()
        insert_at_bottom(stack, element)
        stack.push(el)


def reverse_stack(stack):
    if not stack.is_empty():
        el = stack.pop()
        reverse_stack(stack)
        insert_at_bottom(stack, el)


if __name__ == '__main__':
    s = Stack()
    s.push(1)
    s.push(2)
    s.push(3)

    reverse_stack(s)

    while not s.is_empty():
        print s.pop(),