Пример #1
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def test_peek_doctest() -> None:
    """This is the doctest given in peek."""
    stack = Stack()
    stack.push(1)
    stack.push(2)
    assert peek(stack) == 2
    assert stack.pop() == 2
Пример #2
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def test_peek_general(items: List[int]) -> None:
    """Test that peek works for a large range of stack sizes."""
    stack = Stack()
    for item in items:
        stack.push(item)
    assert peek(stack) == items[-1]
    assert stack.pop() == items[-1]
Пример #3
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def test_reverse_top_two_doctest() -> None:
    """This is the doctest given in reverse_top_two."""
    stack = Stack()
    stack.push(1)
    stack.push(2)
    reverse_top_two(stack)
    assert stack.pop() == 1
    assert stack.pop() == 2
    assert stack.is_empty()
Пример #4
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def reverse_top_two(stack: Stack) -> None:
    """Reverse the top two elements on <stack>.

    Precondition: <stack> has at least two items.

    >>> stack = Stack()
    >>> stack.push(1)
    >>> stack.push(2)
    >>> reverse_top_two(stack)
    >>> stack.pop()
    1
    >>> stack.pop()
    2
    >>> stack.is_empty()
    True
    """
    stack_help = Stack()
    last_item = stack.pop()
    while not stack.is_empty():
        stack_help.push(stack.pop())
    first_item = stack_help.pop()
    stack.push(last_item)
    while not stack_help.is_empty():
        stack.push(stack_help.pop())
    stack.push(first_item)
Пример #5
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def check_params(lines):
    parenthesis_stack = Stack()
    for idx, line in enumerate(lines):
        for cidx, character in enumerate(line):
            if character == '(':
                parenthesis_stack.push(character)
            elif character == ')' and not parenthesis_stack.is_empty():
                parenthesis_stack.pop()
            elif character == ')' and parenthesis_stack.is_empty():
                print(
                    f'You have are closing a parenthesis without opening one on line {idx} on position {cidx}'
                )
                return False
    if parenthesis_stack.is_empty():
        return True
    else:
        return False
Пример #6
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def add_in_order(stack: Stack, lst: list) -> None:
    """
    Add all items in <lst> to <stack>, so that when items are removed from
    <stack>, they are returned in <lst> order.

    Precondition: stack.is_empty() is True

    >>> stack = Stack()
    >>> lst = [1, 2]
    >>> add_in_order(stack, lst)
    >>> results = [stack.pop(), stack.pop()]
    >>> lst == results
    True
    >>> stack.is_empty()
    True
    """
    for item in reversed(lst):
        stack.push(item)
Пример #7
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def reverse_top_two(stack: Stack) -> None:
    """Reverse the top two elements on <stack>.

    Precondition: <stack> has at least two items.

    >>> stack = Stack()
    >>> stack.push(1)
    >>> stack.push(2)
    >>> reverse_top_two(stack)
    >>> stack.pop()
    1
    >>> stack.pop()
    2
    >>> stack.is_empty()
    True
    """
    top_most = stack.pop()
    second = stack.pop()
    stack.push(top_most)
    stack.push(second)
Пример #8
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def peek(stack: Stack) -> Optional[Any]:
    """Return the top item on the given stack.

    If the stack is empty, return None.

    Unlike Stack.pop, this function should leave the stack unchanged when the
    function ends. You can (and should) still call pop and push, just make
    sure that if you take any items off the stack, you put them back on!

    >>> stack = Stack()
    >>> stack.push(1)
    >>> stack.push(2)
    >>> peek(stack)
    2
    >>> stack.pop()
    2
    """
    a = stack.pop()
    stack.push(a)
    return a
Пример #9
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def reverse_top_two(stack: Stack) -> None:
    """Reverse the top two elements on <stack>.

    Precondition: <stack> has at least two items.

    >>> stack = Stack()
    >>> stack.push(1)
    >>> stack.push(2)
    >>> reverse_top_two(stack)
    >>> stack.pop()
    1
    >>> stack.pop()
    2
    >>> stack.is_empty()
    True
    """
    # This is wrong
    temp1 = Stack()
    temp2 = Stack()
    temp1.push(stack.pop())
    temp1.push(stack.pop())
    temp2.push(temp1.pop())
    temp2.push(temp1.pop())
    stack.push(temp2.pop())
    stack.push(temp2.pop())
Пример #10
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def peek(stack: Stack) -> Optional[Any]:
    """Return the top item on the given stack.

    If the stack is empty, return None.

    Unlike Stack.pop, this function should leave the stack unchanged when the
    function ends. You can (and should) still call pop and push, just make
    sure that if you take any items off the stack, you put them back on!

    >>> stack = Stack()
    >>> stack.push(1)
    >>> stack.push(2)
    >>> peek(stack)
    2
    >>> stack.pop()
    2
    """
    temp1 = Stack()
    temp2 = Stack()
    if stack.is_empty():
        return None
    while not stack.is_empty():
        temp1.push(stack.pop())
    while not temp1.is_empty():
        value = temp1.pop()
        stack.push(value)
        temp2.push(value)
    return temp2.pop()
Пример #11
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def reverse_top_two(stack: Stack) -> None:
    """Reverse the top two elements on <stack>.

    Precondition: <stack> has at least two items.

    >>> stack = Stack()
    >>> stack.push(1)
    >>> stack.push(2)
    >>> reverse_top_two(stack)
    >>> stack.pop()
    1
    >>> stack.pop()
    2
    >>> stack.is_empty()
    True
    """
    popped = list()
    for x in range(0, 2):
        if not stack.is_empty():
            popped.append(stack.pop())
    for x in popped:
        stack.push(x)
Пример #12
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def remove_all_but_one(queue: Queue) -> None:
    """Remove all items from the given queue except the last one.

    Precondition: <queue> contains at least one item.
                  or: not queue.is_empty()

    >>> queue = Queue()
    >>> queue.enqueue(1)
    >>> queue.enqueue(2)
    >>> queue.enqueue(3)
    >>> remove_all_but_one(queue)
    >>> queue.is_empty()
    False
    >>> queue.dequeue()
    3
    >>> queue.is_empty()
    True
    """
    temp = Stack()
    while not queue.is_empty():
        temp.push(queue.dequeue())
    queue.enqueue(temp.pop())
Пример #13
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def peek(stack: Stack) -> Optional[Any]:
    """Return the top item on the given stack.

    If the stack is empty, return None.

    Unlike Stack.pop, this function should leave the stack unchanged when the
    function ends. You can (and should) still call pop and push, just make
    sure that if you take any items off the stack, you put them back on!
    Need to consider the case when stack is empty

    >>> stack = Stack()
    >>> stack.push(1)
    >>> stack.push(2)
    >>> peek(stack)
    2
    >>> stack.pop()
    2
    """
    if stack.is_empty():
        return None
    peek_result = stack.pop()
    stack.push(peek_result)
    return peek_result
Пример #14
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def reverse_top_two(stack: Stack) -> None:
    """Reverse the top two elements on <stack>.

    Precondition: <stack> has at least two items.

    >>> stack = Stack()
    >>> stack.push(1)
    >>> stack.push(2)
    >>> reverse_top_two(stack)
    >>> stack.pop()
    1
    >>> stack.pop()
    2
    >>> stack.is_empty()
    True
    """

    if stack.is_empty():
        pass
    else:
        firstvar = stack.pop()
        secondvar = stack.pop()
        stack.push(firstvar)
        stack.push(secondvar)
Пример #15
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    False
    >>> queue.dequeue()
    3
    >>> queue.is_empty()
    True
    """
    temp = Stack()
    while not queue.is_empty():
        temp.push(queue.dequeue())
    queue.enqueue(temp.pop())


if __name__ == '__main__':
    # import doctest
    # doctest.testmod()

    # Remember, to get this to work you need to Run this file, not just the
    # doctests in this file!
    # import python_ta
    # python_ta.check_all(config={
    #     'extra-imports': ['adts']
    # })
    stack = Stack()
    stack.push(1)
    stack.push(2)
    stack.push(3)
    stack.push(4)
    reverse_top_two(stack)
    print(stack.fuscat1)