def test_simplify_path(self):
p = "/my/name/is/..//keon"
self.assertEqual("/my/name/keon", simplify_path(p))
def test_simplify_path(self):
p = '/my/name/is/..//keon'
self.assertEqual('/my/name/keon', simplify_path(p))
def test_simplify_path(self):
p = '/my/name/is/..//keon'
self.assertEqual('/my/name/keon', simplify_path(p))
"""
Given an absolute path for a file (Unix-style), simplify it.
For example,
path = "/home/", => "/home"
path = "/a/./b/../../c/", => "/c"
* Did you consider the case where path = "/../"?
In this case, you should return "/".
* Another corner case is the path might contain multiple slashes '/' together, such as "/home//foo/".
In this case, you should ignore redundant slashes and return "/home/foo".
"""
from algorithms.stack import simplify_path
path = "/home/"
path2 = "/a/./b/../../c/"
print(simplify_path(path))
print(simplify_path(path2))