def test(arr):
solutions = [
NotSolution(),
Solution(),
Solution1b(),
Solution2(),
Solution2b(),
]
root = array_to_bt(arr)[0]
is_bst = [s.isValidBST(root) for s in solutions]
print("#"*80)
print(arr)
print()
print_tree(root)
print(f"\nis BST? {is_bst}\n")
n3b = num_path_sum3b(root, target_sum)
n3c = num_path_sum3c(root, target_sum)
n4 = num_path_sum4(root, target_sum)
n5, cache = num_path_sum5(root, target_sum)
print(f"\nnumber of paths with sum {target_sum} (sol #1) is {n}")
print(f"number of paths with sum {target_sum} (sol #2) is {n2}")
print(f"number of paths with sum {target_sum} (sol #3) is {n3}")
print(f"number of paths with sum {target_sum} (sol #3b) is {n3b}")
print(f"number of paths with sum {target_sum} (sol #3c) is {n3c}")
print(f"number of paths with sum {target_sum} (sol #4) is {n4}")
print(f"number of paths with sum {target_sum} (sol #5) is {n5}")
# LC example
arr = [10, 5, -3, 3, 2, None, 11, 3, -2, None, 1]
root = array_to_bt(arr)[0]
target_sum = 8
test(root, target_sum)
# LC test; answer = 1
arr = [1, 2, None]
root = array_to_bt(arr)[0]
target_sum = 2
test(root, target_sum)
### LC test; answer = 3
arr = [5, 4, 8, 11, None, 13, 4, 7, 2, None, None, 5, 1]
root = array_to_bt(arr)[0]
target_sum = 22
test(root, target_sum)
diam2 = diameter_bt2(root)
print(f"\ndiameter of BT (sol #1) = {diam}")
print(f"diameter of BT (sol #2) = {diam2}")
root = None
test(root)
root = TreeNode(1)
test(root)
root = TreeNode(1, TreeNode(2, TreeNode(3, TreeNode(4, TreeNode(5, )))))
test(root)
arr = [5, 4,5, 1,1,None,5]
nodes = array_to_bt(arr)
root = nodes[0]
test(root)
arr = [1, 4,5, 4,4,None,5]
nodes = array_to_bt(arr)
root = nodes[0]
test(root)
arr = [5,4,5,4,4,5,3,4,4,None,None,None,4,None,None,4,None,None,4,None,4,4,None,None,4,4]
root = array_to_bt_lc(arr)
test(root)
arr = [1, 2,3, 4,5] # LC example; answer = 3
root = array_to_bt_lc(arr)
test(root)
