Пример #1
0
def solve():
    """
    >>> solve()
    428570
    """

    best = 2 / 5, 2, 5
    primer = CachedPrimer()

    for denominator in range(2, 1000001):
        if denominator % 1000 == 0:
            print(denominator)

        denominator_prime_factors = primer.prime_factors(denominator).keys()

        numerator = best_numerator_using_binary(denominator)

        assert numerator / denominator < TARGET

        def hcf_is_1(numerator):
            common_factors = (primer.prime_factors(numerator).keys()
                              & denominator_prime_factors)
            return not common_factors

        while numerator / denominator > best[0] and not hcf_is_1(numerator):
            numerator -= 1

        current = numerator / denominator
        assert current < TARGET

        if current > best[0]:
            best = current, numerator, denominator

    # Ended up using the code from both wrong solutions. Cool!
    return best[1]  # (0.42857128571385716, 428570, 999997)
Пример #2
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def solve():
    """
    >>> solve()
    142913828922
    """

    primer = CachedPrimer()
    known_primes = primer.primes_up_to(2000000)
    return sum(known_primes)
Пример #3
0
def solve():
    """
    >>> solve()
    104743
    """

    primer = CachedPrimer()

    primes = primer.primes_up_to(stop_at_n_primes=10001)

    return primes[-1]
Пример #4
0
def solve():
    """
    >>> solve()
    232792560
    """
    PRIMER = CachedPrimer()
    factors = collections.Counter()
    for i in range(1, 21):
        for factor, power in PRIMER.prime_factors(i).items():
            factors[factor] = max(power, factors[factor])

    return math.prod(factor**power for factor, power in factors.items())
Пример #5
0
def solve():
    """
    >>> solve()
    76576500
    """

    primer = CachedPrimer()
    number = 1
    print(
        candidates,
        smallest_possible_500_factors,
        primer.factors_count(smallest_possible_500_factors),
    )
    index = 1
    best_count = 0
    while (count := primer.factors_count(number)) <= 500:
        index += 1
        number += index
        if count >= best_count:
            best_count = count
            print(number, best_count)
Пример #6
0
import collections
import itertools
import math

import wrapt_timeout_decorator

from common.primer import CachedPrimer

PRIMER = CachedPrimer()

# def smallest_possible_500_factors():  # INCORRECT
#     first_500_primes = PRIMER.primes_up_to(stop_at_n_primes=500)
#     best = math.inf
#     prime_count = 500
#     while prime_count > 1:
#         factors = itertools.chain(*zip(*(first_500_primes for _ in range(prime_count))))
#         candidate = 1
#         used_factors = collections.Counter()

#         while math.prod(used_factors.values()) < 500:
#             factor = next(factors)
#             used_factors[factor] += 1
#             candidate *= factor

#             if prime_count == 4:
#                 print(factor)

#         prime_count -= 1

#         best = min(candidate, best)
#     return best
Пример #7
0
from common.primer import CachedPrimer


def sum_digits(n):
    return sum(int(char) for char in str(n))


PRIMER = CachedPrimer()
generators = []
for n in range(1, 100000001):
    last_digit = n % 10
    # if n > 6 and not last_digit in {2, 8, 0}:
    #     continue

    if all(
            PRIMER.is_prime(factor + n // factor)
            for factor in PRIMER.factors(n)):
        generators.append(n)
        print(n, last_digit in {2, 8, 0}, PRIMER.prime_factors(n))