Пример #1
0
    def relabel(self, mapping):
        try:
            old_labels = set(mapping)
            new_labels = set(mapping.values())
        except TypeError:
            raise ValueError("mapping targets must be hashable objects")

        for v in new_labels:
            if v in self and v not in old_labels:
                raise ValueError((
                    'A variable cannot be relabeled "{}" without also relabeling '
                    "the existing variable of the same name").format(v))

        if any(v in new_labels for v in old_labels):
            old_to_intermediate, intermediate_to_new = resolve_label_conflict(
                mapping, old_labels, new_labels)

            self.relabel(old_to_intermediate)
            self.relabel(intermediate_to_new)

            return

        label = self._label
        index = self.index

        for old, new in mapping.items():
            label[index[old]] = new

            index[new] = index[old]
            del index[old]
Пример #2
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    def relabel_variables(self, mapping, inplace=True):
        """Relabel a response's variables as per a given mapping.

        Args:
            mapping (dict):
                Dict mapping current variable labels to new. If an incomplete mapping is
                provided, unmapped variables keep their original labels

            inplace (bool, optional, default=True):
                If True, the original response is updated; otherwise a new response is returned.

        Returns:
            :class:`.Response`: Response with relabeled variables. If inplace=True, returns
            itself.

        Examples:
            Create a relabeled copy of a response

            >>> import dimod
            ...
            >>> response = dimod.ExactSolver().sample_ising({'a': -0.5, 'b': 1.0}, {('a', 'b'): -1})
            >>> new_response = response.relabel_variables({'a': 0, 'b': 1}, inplace=False)
            >>> response.variable_labels    # doctest: +SKIP
            [0, 1]

        """
        if not inplace:
            return self.copy().relabel_variables(mapping, inplace=True)

        try:
            old_labels = set(mapping.keys())
            new_labels = set(mapping.values())
        except TypeError:
            raise ValueError("mapping targets must be hashable objects")

        for v in self.variable_labels:
            if v in new_labels and v not in old_labels:
                raise ValueError((
                    'A variable cannot be relabeled "{}" without also relabeling '
                    "the existing variable of the same name").format(v))

        shared = old_labels & new_labels
        if shared:
            old_to_intermediate, intermediate_to_new = resolve_label_conflict(
                mapping, old_labels, new_labels)

            self.relabel_variables(old_to_intermediate, inplace=True)
            self.relabel_variables(intermediate_to_new, inplace=True)
            return self

        self._variable_labels = labels = [
            mapping.get(v, v) for v in self.variable_labels
        ]
        self._label_to_idx = {v: idx for idx, v in enumerate(labels)}
        return self
Пример #3
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    def relabel_variables(self, mapping, inplace=True):
        """Relabel the variables of a :class:`SampleSet` according to the specified mapping.

        Args:
            mapping (dict):
                Mapping from current variable labels to new, as a dict. If incomplete mapping is
                specified, unmapped variables keep their current labels.

            inplace (bool, optional, default=True):
                If True, the current :class:`SampleSet` is updated; otherwise, a new
                :class:`SampleSet` is returned.

        Returns:
            :class:`.SampleSet`: SampleSet with relabeled variables. If `inplace` is True, returns
            itself.

        Examples:
            This example creates a relabeled copy of a :class:`SampleSet`.

            >>> import dimod
            ...
            >>> sampleset = dimod.ExactSolver().sample_ising({'a': -0.5, 'b': 1.0}, {('a', 'b'): -1})
            >>> new_sampleset = sampleset.relabel_variables({'a': 0, 'b': 1}, inplace=False)
            >>> sampleset.variable_labels    # doctest: +SKIP
            [0, 1]

        """
        if not inplace:
            return self.copy().relabel_variables(mapping, inplace=True)

        try:
            old_labels = set(mapping.keys())
            new_labels = set(mapping.values())
        except TypeError:
            raise ValueError("mapping targets must be hashable objects")

        for v in self.variables:
            if v in new_labels and v not in old_labels:
                raise ValueError((
                    'A variable cannot be relabeled "{}" without also relabeling '
                    "the existing variable of the same name").format(v))

        shared = old_labels & new_labels
        if shared:
            old_to_intermediate, intermediate_to_new = resolve_label_conflict(
                mapping, old_labels, new_labels)

            self.relabel_variables(old_to_intermediate, inplace=True)
            self.relabel_variables(intermediate_to_new, inplace=True)
            return self

        self._variables = VariableIndexView(
            mapping.get(v, v) for v in self.variables)
        return self
Пример #4
0
    def relabel_variables(self, mapping, inplace=True):
        """Relabel variables of a binary polynomial as specified by mapping.

        Args:
            mapping (dict):
                Dict mapping current variable labels to new ones. If an
                incomplete mapping is provided, unmapped variables retain their
                current labels.

            inplace (bool, optional, default=True):
                If True, the binary polynomial is updated in-place; otherwise, a
                new binary polynomial is returned.

        Returns:
            :class:`.BinaryPolynomial`: A binary polynomial with the variables
            relabeled. If `inplace` is set to True, returns itself.

        """
        if not inplace:
            return self.copy().relabel_variables(mapping, inplace=True)

        try:
            old_labels = set(mapping)
            new_labels = set(mapping.values())
        except TypeError:
            raise ValueError("mapping targets must be hashable objects")

        variables = self.variables
        for v in new_labels:
            if v in variables and v not in old_labels:
                raise ValueError((
                    'A variable cannot be relabeled "{}" without also relabeling '
                    "the existing variable of the same name").format(v))

        shared = old_labels & new_labels
        if shared:
            old_to_intermediate, intermediate_to_new = resolve_label_conflict(
                mapping, old_labels, new_labels)

            self.relabel_variables(old_to_intermediate, inplace=True)
            self.relabel_variables(intermediate_to_new, inplace=True)
            return self

        for oldterm, bias in list(self.items()):
            newterm = frozenset((mapping.get(v, v) for v in oldterm))

            if newterm != oldterm:
                self[newterm] = bias
                del self[oldterm]

        return self
Пример #5
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    def relabel(self, mapping):

        # put the new labels into a set for fast lookup
        try:
            new_labels = set(mapping.values())
        except TypeError:
            # when new labels are not hashable
            raise ValueError("mapping targets must be hashable objects")

        if PY3:
            old_labels = mapping.keys()
        else:
            # we actually want old_labels to be a keysview like in python3
            # but since we don't get that in python2 we just use the mapping
            # itself and treat it as a set rather than a dict.
            old_labels = mapping

        for v in new_labels:
            if v in self and v not in old_labels:
                msg = ("A variable cannot be relabeled {!r} without also "
                       "relabeling the existing variable of the same name")
                raise ValueError(msg.format(v))

        if any(v in new_labels for v in old_labels):
            old_to_intermediate, intermediate_to_new = resolve_label_conflict(
                mapping, old_labels, new_labels)

            self.relabel(old_to_intermediate)
            self.relabel(intermediate_to_new)

            return

        label = self._label
        index = self.index

        for old, new in mapping.items():
            if old not in self:
                continue

            label[index[old]] = new
            index[new] = index[old]
            del index[old]
Пример #6
0
    def relabel_variables(self, mapping, inplace=True):
        """Relabel a response's variables as per a given mapping.

        Args:
            mapping (dict):
                Dict mapping current variable labels to new. If an incomplete mapping is
                provided, unmapped variables keep their original labels

            inplace (bool, optional, default=True):
                If True, the original response is updated; otherwise a new response is returned.

        Returns:
            :class:`.Response`: Response with relabeled variables. If inplace=True, returns
            itself.

        Examples:
            This example relabels variables in a response.

            .. code-block:: python

                response = dimod.Response.from_dicts([{'a': -1}, {'a': +1}], {'energy': [-1, 1]})
                response.relabel_variables({'a': 0})

            This example creates a new response with relabeled variables.

            .. code-block:: python

                response = dimod.Response.from_dicts([{'a': -1}, {'a': +1}], {'energy': [-1, 1]})
                new_response = response.relabel_variables({'a': 0}, inplace=False)

        """
        if not inplace:
            return self.copy().relabel_variables(mapping, inplace=True)

        # we need labels
        if self.variable_labels is None:
            __, num_variables = self.samples_matrix.shape
            self.variable_labels = list(range(num_variables))

        try:
            old_labels = set(mapping)
            new_labels = set(itervalues(mapping))
        except TypeError:
            raise ValueError("mapping targets must be hashable objects")

        for v in new_labels:
            if v in self.variable_labels and v not in old_labels:
                raise ValueError((
                    'A variable cannot be relabeled "{}" without also relabeling '
                    "the existing variable of the same name").format(v))

        shared = old_labels & new_labels
        if shared:
            old_to_intermediate, intermediate_to_new = resolve_label_conflict(
                mapping, old_labels, new_labels)

            self.relabel_variables(old_to_intermediate, inplace=True)
            self.relabel_variables(intermediate_to_new, inplace=True)
            return self

        self.variable_labels = variable_labels = [
            mapping.get(v, v) for v in self.variable_labels
        ]
        self.label_to_idx = {v: idx for idx, v in enumerate(variable_labels)}
        return self