Пример #1
0
 def findKthLargestByStack(self, nums: List[int], k: int) -> int:
     """
     使用最大堆
     """
     from heap import HeapMin
     h = HeapMin([-i for i in nums])
     for i in range(k):
         ret = h.pop()
     return -ret
Пример #2
0
	def queueHeap(self):
		size = len(self.__queue)+1
		first = Node('', -1)
		inf = Node('', float("inf"))

		self.__heap_queue = HeapMin(first, size, inf)

		for char in self.__queue:
			try:
				self.__heap_queue.insertNode(Node(char, self.__queue[char]))
			except CapacityError as e:
				print(e.expr.upper() + ":\n" + e.msg + "\n")
				sys.exit(0)
Пример #3
0
 def prim(self):
     """Algoritmo de Prim para hallar el árbol de expansión mínimo."""
     bosque = []
     aristas = HeapMin()
     origen = self.inicio.obtener_elemento(0)
     adyac = 0
     while (adyac < origen['aristas'].tamanio()):
         arista = origen['aristas'].obtener_elemento(adyac)
         aristas.arribo([origen['info'], arista['destino']], arista['peso'])
         adyac += 1
     # print(bosque)
     # print(aristas.elementos)
     # print()
     while (len(bosque) // 2 < self.tamanio() and not aristas.vacio()):
         dato = aristas.atencion()
         if (len(bosque) == 0) or (
             (self.busqueda_prim(bosque, dato[1][0]) is not None) ^
             (self.busqueda_prim(bosque, dato[1][1]) is not None)):
             bosque.append(dato)
             pos_vertice = self.buscar_vertice(dato[1][1])
             nuevo_vertice = self.inicio.obtener_elemento(pos_vertice)
             adyac = 0
             while (adyac < nuevo_vertice['aristas'].tamanio()):
                 arista = nuevo_vertice['aristas'].obtener_elemento(adyac)
                 # print(arista)
                 aristas.arribo([nuevo_vertice['info'], arista['destino']],
                                arista['peso'])
                 adyac += 1
         # print(bosque)
         # print(aristas.elementos)
         # a = input()
     return bosque
Пример #4
0
def schargepmtn_nlogn(jobs_list):

    R = HeapMin()
    Q = HeapMax()
    i=0
    for job in jobs_list:
        R.add(Cell(value=job.head[0], job=i))
        i += 1

    # S = np.zeros(len(jobs_list))  # momenty rozpoczęcia wykonywania zadań
    # C = np.zeros(len(jobs_list))  # momenty zakończenia wykonywania zadań

    Nn = list(range(len(jobs_list)))
    Ng = []

    # order = []

    # Algorymt
    t = 0
    l = 0
    Cmax = 0
    while len(Nn) > 0 or len(Ng) > 0:
        while len(Nn) > 0 and R.min().value <= t:
            j = R.min(True).job
            Nn.remove(j)
            Ng.append(j)
            Q.add(Cell(value=jobs_list[j].tail[0], job=j))

            if jobs_list[j].tail[0] > jobs_list[l].tail[0]:
                jobs_list[l].body[0] = t - jobs_list[j].head[0]
                t = jobs_list[j].head[0]

                if jobs_list[l].body[0] > 0:
                    Ng.append(l)
                    Q.add(Cell(value=jobs_list[l].tail[0], job=l))

        if len(Ng) == 0:
            t = R.min().value
        else:
            j = Q.max(True).job
            Ng.remove(j)
            l = j
            t = t + jobs_list[j].body[0]
            Cmax = max(Cmax, t + jobs_list[j].tail[0])

    return Cmax
Пример #5
0
 def prim(self, inicio=0):
     bosque = []
     aristas = HeapMin()
     origen = self.inicio.obtener_elemento(inicio)
     adyac = 0
     while (adyac < origen['aristas'].tamanio()):
         arista = origen['aristas'].obtener_elemento(adyac)
         aristas.arribo([origen['info'], arista['destino']], arista['peso'])
         adyac += 1
     while (len(bosque) // 2 < self.tamanio() and not aristas.vacio()):
         dato = aristas.atencion()
         if (len(bosque) == 0) or (
             (self.busqueda_prim(bosque, dato[1][0]) is not None) ^
             (self.busqueda_prim(bosque, dato[1][1]) is not None)):
             bosque.append(dato)
             pos_vertice = self.buscar_vertice(dato[1][1])
             nuevo_vertice = self.inicio.obtener_elemento(pos_vertice)
             adyac = 0
             while (adyac < nuevo_vertice['aristas'].tamanio()):
                 arista = nuevo_vertice['aristas'].obtener_elemento(adyac)
                 aristas.arribo([nuevo_vertice['info'], arista['destino']],
                                arista['peso'])
                 adyac += 1
     return bosque
Пример #6
0
 def dijkstra(self, ver_origen, ver_destino):
     """Algoritmo de Dijkstra para hallar el camino mas corto."""
     no_visitados = HeapMin()
     camino = Pila()
     aux = 0
     while (aux < self.tamanio()):
         vertice = self.inicio.obtener_elemento(ver_origen)
         vertice_aux = self.inicio.obtener_elemento(aux)
         vertice_aux['anterior'] = None
         if (vertice_aux['info'] == vertice['info']):
             no_visitados.arribo([vertice_aux['info'], None], 0)
         else:
             no_visitados.arribo([vertice_aux['info'], None], inf)
         aux += 1
     while (not no_visitados.vacio()):
         dato = no_visitados.atencion()
         camino.apilar(dato)
         pos_aux = self.buscar_vertice(dato[1][0])
         vertice_aux = self.inicio.obtener_elemento(pos_aux)
         aristas = 0
         while (aristas < vertice_aux['aristas'].tamanio()):
             arista = vertice_aux['aristas'].obtener_elemento(aristas)
             pos_heap = no_visitados.busqueda(arista['destino'])
             if (pos_heap is not None
                     and no_visitados.elementos[pos_heap][0] >
                     dato[0] + arista['peso']):
                 no_visitados.elementos[pos_heap][1][1] = dato[1][0]
                 nuevo_peso = dato[0] + arista['peso']
                 no_visitados.cambiar_prioridad(pos_heap, nuevo_peso)
             aristas += 1
     # print(no_visitados.elementos)
     return camino
Пример #7
0
class Huffman:

	__queue, __table = {}, {}
	__heap_queue = []
	__text, __bintext = '', ''


	def __init__(self, filename):
		with open(filename, 'r') as f: 
			for line in f:
				for char in line:
					if char in self.__queue:
						self.__queue[char] += 1
					else:
						self.__queue[char] = 1

				self.__text += line
           		


	def printQueue(self):
		for char in self.__queue:
			print("%c:%d" %(char, self.__queue[char]))


	def queueHeap(self):
		size = len(self.__queue)+1
		first = Node('', -1)
		inf = Node('', float("inf"))

		self.__heap_queue = HeapMin(first, size, inf)

		for char in self.__queue:
			try:
				self.__heap_queue.insertNode(Node(char, self.__queue[char]))
			except CapacityError as e:
				print(e.expr.upper() + ":\n" + e.msg + "\n")
				sys.exit(0)


	def printHeapQueue(self):
		self.__heap_queue.printHeap()


	def printAllNodes(self):
		root = self.__heap_queue.getNode(1)
		level = root.height(root)+1
		root.printNode(root, level)


	def printSequenceNodes(self):
		root = self.__heap_queue.getNode(1)
		root.printNodeLine(root)


	def joinElements(self):
		while(self.__heap_queue.getSize() > 2):			
			left = self.__heap_queue.extractMin()
			right = self.__heap_queue.extractMin()
			root = Node(left.char+right.char, left.freq+right.freq, left, right)
			self.__heap_queue.insertNode(root)


	def compress(self):
		root = self.__heap_queue.getNode(1)
		root.passTree(root)
		self.__table = root.getTable()


	def extract(self, filename=''):
		b, txt = '', ''
		inv_table = dict((value, key) for key, value in self.__table.items())
		
		text = self.__bintext
		if(filename != ''):
			f = open(filename, 'rb')
			text = self.__convertStringToBin(f.read().decode('ascii'))
			f.close()

		for char in text:
			b += char
			if b in inv_table:
				txt += inv_table[b]
				b = ''
		return txt


	def saveFile(self, filename):
		f = open(filename, 'w+')
		b = ''
		for char in self.__text:
			b += self.__table[char]
			
		f.write(b)
		f.close()
		self.__bintext = b


	def saveFileBin(self, filename):
		f = open(filename, 'wb')
		b = ''
		for char in self.__text:
			b += self.__table[char]
		
		f.write(self.__convertBinToString(b).encode('ascii'))
		f.close()
		self.__bintext = b


	def __convertBinToString(self, b):
		start, end = 0, 7
		text = ''
		while(end < len(b)+7):
			temp = b[start:end]
			text += chr(int(temp, 2))
			start, end = end, end+7

		return text


	def __convertStringToBin(self, b):
		i = 0
		text = ''
		while(i < len(b)):
			temp = b[i]
			text += str(bin(ord(temp)))[2:].zfill(7)
			i += 1

		return text


	def printTexts(self):
		print(self.__text)
		print(self.__bintext)


	def printTable(self):
		print(self.__table)


	def printSizes(self):
		sizeOriginalText = len(self.__text)*8
		sizeCompressText = len(self.__bintext)
		compressRatio = 100-float((sizeCompressText*100)/sizeOriginalText)
		print("Tamanho do texto original em bits: %d" %(sizeOriginalText))
		print("Tamanho do texto compactado em bits: %d" %(sizeCompressText))
		print("Taxa de compactacao: %.2f%%" %compressRatio)
Пример #8
0
def schrange_nlogn(jobs_list):
    '''
    Simulate RPQ problem
    :param jobs_list:
    :param order:
    :return:
    '''

    R = HeapMin()
    Q = HeapMax()
    i=0
    for job in jobs_list:
        R.add(Cell(value=job.head[0], job=i))
        i += 1

    S = np.zeros(len(jobs_list))  # momenty rozpoczęcia wykonywania zadań
    C = np.zeros(len(jobs_list))  # momenty zakończenia wykonywania zadań

    Nn = list(range(len(jobs_list)))
    Ng = []

    order = []

    # Algorymt
    t = R.min().value
    while len(Nn) > 0 or len(Ng) > 0:
        while len(Nn) > 0 and R.min().value <= t:
            j = R.min(True).job
            Nn.remove(j)
            Ng.append(j)
            Q.add(Cell(value=jobs_list[j].tail[0], job=j))
        if len(Ng) == 0:
            t = R.min().value
        else:
            j = Q.max(True).job
            Ng.remove(j)
            order.append(j)
            t += jobs_list[j].body[0]

    # S czas rozpoczecia zadania
    first = True
    for i in order:
        if first:
            S[i] = jobs_list[i].head[0]
            i_last = i
            first = False
        else:
            S[i] = max(jobs_list[i].head[0], S[i_last]+jobs_list[i_last].body[0])
            i_last = i

    # C czas zakonczenia zadania
    for i in order:
        C[i] = S[i] + jobs_list[i].body[0]

    # Obliczenie cmax
    cmax = []
    for i in order:
        cmax.append(C[i]+jobs_list[i].tail[0])
    # Najdłuższy czas jako ostatnie zakonczone zadania
    cmax = max(cmax)

    return order, cmax