Пример #1
0
foo, subfoo, subfoo2, n = Foo(), SubFoo(), SubFoo2(), N()

for _v, _id in zip([foo, subfoo, subfoo2, n],
                   ['foo', 'subfoo', 'subfoo2', 'n']):
    d[_v] = _id

from java.lang import Long, Integer, Short, Character, Byte, Boolean, Double, Float, String
from java.math import BigInteger

values = [
    0, 0L, 0.0, 'c', "string", (), o, c, foo, subfoo, subfoo2, n, Object,
    Class, Foo, SubFoo, C, SubFoo2, N, Integer,
    Long(0),
    Integer(0),
    Short(0),
    Character('c'),
    Byte(0),
    Boolean(0),
    Double(0),
    Float(0),
    String("js"),
    BigInteger("0")
]


def pp(v):
    inst = d.get(v, None)
    if inst is not None:
        return inst
    if hasattr(v, '__name__'):
        return v.__name__