def solveCircuit(componentList, GND):
# flatten_list is necessary for lists that contain two-ports,
# which will be introduced in exercises over the nex few weeks.
# It has no effect on lists that contain just one-ports.
# Do not remove the following line.
componentList = flatten_list(componentList)
equations = []
for oneport_instance in componentList:
equations.append(oneport_instance.equation)
nodes = []
for oneport_instance in componentList:
nodes.append(oneport_instance.e1)
nodes.append(oneport_instance.e2)
nodes = list(set(nodes))
nodes.remove(GND)
parts = []
for node in nodes:
for oneport_instance in componentList:
if node == oneport_instance.e1:
parts.append((1,oneport_instance.i))
elif node == oneport_instance.e2:
parts.append((-1,oneport_instance.i))
equations.append(parts)
parts = []
ground = [(1,GND)]
equations.append(ground)
return solveEquations(equations,verbose=False)
def solveCircuit(componentList, GND):
# flatten_list is necessary for lists that contain two-ports.
# It has no effect on lists that contain just one-ports.
# Do not remove the following line.
componentList = flatten_list(componentList)
componentList = [comp for comp in componentList if comp != None]
equations = []
# one equation for each component
for component in componentList:
equations.append(component.equation)
# one KCL equation for each node except ground
equations.extend(create_kcls(componentList, GND))
# one equation for ground
equations.append([(1, GND)])
return solveEquations(equations)
