Пример #1
0
    def polish_notation(self):
        r"""
        Convert the calling boolean formula into polish notation

        INPUT:

        - ``self`` -- calling object

        OUTPUT:

        A string representation of the formula in polish notation.

        EXAMPLES:

        This example illustrates converting a formula to polish notation.

        ::

            sage: import sage.logic.propcalc as propcalc
            sage: f = propcalc.formula("~~a|(c->b)")
            sage: f.polish_notation()
            '|~~a->cb'

        ::

            sage: g = propcalc.formula("(a|~b)->c")
            sage: g.polish_notation()
            '->|a~bc'

        AUTHORS:

        - Paul Scurek (2013-08-03)
        """
        return ''.join(flatten(logicparser.polish_parse(repr(self))))
Пример #2
0
    def full_tree(self):
        r"""
        This function returns a full syntax parse tree of the
        calling boolean formula.

        INPUT:
            self -- the calling object, which is a boolean formula

        OUTPUT:
            Returns a list containing the full syntax parse tree of self, with
            the symbols arranged from left to right as in polish notation.

        EXAMPLES:
            sage: import sage.logic.propcalc as propcalc
            sage: s = propcalc.formula("a->(b&c)")
            sage: s.full_tree()
            ['->', 'a', ['&', 'b', 'c']]
            sage: t = propcalc.formula("a & ((~b | c) ^ a -> c) <-> ~b")
            sage: t.full_tree()
            ['<->', ['&', 'a', ['->', ['^', ['|', ['~', 'b'], 'c'], 'a'], 'c']], ['~', 'b']]
            sage: f = propcalc.formula("~~(a&~b)")
            sage: f.full_tree()
            ['~', ['~', ['&', 'a', ['~', 'b']]]]
        """
        return logicparser.polish_parse(repr(self))
Пример #3
0
    def polish_notation(self):
        r"""
        Convert the calling boolean formula into polish notation

        INPUT:

        - ``self`` -- calling object

        OUTPUT:

        A string representation of the formula in polish notation.

        EXAMPLES:

        This example illustrates converting a formula to polish notation.

        ::

            sage: import sage.logic.propcalc as propcalc
            sage: f = propcalc.formula("~~a|(c->b)")
            sage: f.polish_notation()
            '|~~a->cb'

        ::

            sage: g = propcalc.formula("(a|~b)->c")
            sage: g.polish_notation()
            '->|a~bc'

        AUTHORS:

        - Paul Scurek (2013-08-03)
        """
        return ''.join(flatten(logicparser.polish_parse(repr(self))))
Пример #4
0
    def full_tree(self):
        r"""
        Return a full syntax parse tree of the calling formula.

        INPUT:

        - ``self`` -- calling object.  This is a boolean formula.

        OUTPUT:

        The full syntax parse tree as a nested list

        EXAMPLES:

        This example shows how to find the full syntax parse tree of a formula.

        ::

            sage: import sage.logic.propcalc as propcalc
            sage: s = propcalc.formula("a->(b&c)")
            sage: s.full_tree()
            ['->', 'a', ['&', 'b', 'c']]

        ::

            sage: t = propcalc.formula("a & ((~b | c) ^ a -> c) <-> ~b")
            sage: t.full_tree()
            ['<->', ['&', 'a', ['->', ['^', ['|', ['~', 'b'], 'c'], 'a'], 'c']], ['~', 'b']]

        ::

            sage: f = propcalc.formula("~~(a&~b)")
            sage: f.full_tree()
            ['~', ['~', ['&', 'a', ['~', 'b']]]]

        .. NOTE::

            This function is used by other functions in the logic module
            that perform syntactic operations on a boolean formula.

        AUTHORS:

        - Paul Scurek (2013-08-03)
        """
        return logicparser.polish_parse(repr(self))
Пример #5
0
    def full_tree(self):
        r"""
        Return a full syntax parse tree of the calling formula.

        INPUT:

        - ``self`` -- calling object.  This is a boolean formula.

        OUTPUT:

        The full syntax parse tree as a nested list

        EXAMPLES:

        This example shows how to find the full syntax parse tree of a formula.

        ::

            sage: import sage.logic.propcalc as propcalc
            sage: s = propcalc.formula("a->(b&c)")
            sage: s.full_tree()
            ['->', 'a', ['&', 'b', 'c']]

        ::

            sage: t = propcalc.formula("a & ((~b | c) ^ a -> c) <-> ~b")
            sage: t.full_tree()
            ['<->', ['&', 'a', ['->', ['^', ['|', ['~', 'b'], 'c'], 'a'], 'c']], ['~', 'b']]

        ::

            sage: f = propcalc.formula("~~(a&~b)")
            sage: f.full_tree()
            ['~', ['~', ['&', 'a', ['~', 'b']]]]

        .. NOTE::

            This function is used by other functions in the logic module
            that perform syntactic operations on a boolean formula.

        AUTHORS:

        - Paul Scurek (2013-08-03)
        """
        return logicparser.polish_parse(repr(self))
Пример #6
0
    def polish_notation(self):
        r"""
        This function returns the calling formula in polish notation in
        the form of a string.

        INPUT:
            self -- the calling object, which is a boolean formula

        OUTPUT:
            Returns the caling formula in polish notation as a string

        EXAMPLES:
            sage: import sage.logic.propcalc as propcalc
            sage: f = propcalc.formula("~~a|(c->b)")
            sage: f.polish_notation()
            '|~~a->cb'
            sage: g = propcalc.formula("(a|~b)->c")
            sage: g.polish_notation()
            '->|a~bc'
        """
        return ''.join(flatten(logicparser.polish_parse(repr(self))))