def hot_potato(name_lst, num):
    q = Queue()
    for n in name_lst:
        q.enqueue(n)

    while q.size() > 1:
        for i in range(num):
            q.enqueue(q.dequeue())
        q.dequeue()

    return q.dequeue()
Пример #2
0
class Stack:

    def __init__(self):
        self.__stack = Queue()

    # Adds value to the end of the Stack.
    # Complexity: O(1)
    # push(value)
    def push(self, value):
        self.__stack.push(value)

    # Returns value from the end of the Stack and removes it.
    # Complexity: O(1)
    # pop()
    def pop(self, pop_type=None):
        new_stack = Queue()
        while self.__stack.size() > 0:
            current_value = self.__stack.pop()
            if self.__stack.size() == 0:
                if pop_type is not None:
                    new_stack.push(current_value)
                self.__stack = new_stack
                return current_value
            new_stack.push(current_value)

    # Returns value from the end of the Stack without removing it.
    # Complexity: O(1)
    def peek(self):
        return self.pop(1)

    # Returns the number of elements in the Queue.
    # Complexity: O(1)
    def size(self):
        return self.__stack.size()

    def getStack(self):
        return self.__stack.getQueue()
Пример #3
0
    def find_nearest_shop(self):
        visited = []
        queue = Queue()
        queue.push(self.__start_index)

        while queue.size() != 0:
            current = queue.pop()
            if current is not None:
                if self.__shop_lists[current] != 0:
                    return current
                for e in range(len(self.__map[current])):
                    if self.__map[current][e] != 0 and e not in visited:
                        queue.push(e)
            visited.append(current)
        return None
def simulate(num_seconds, pages_per_minute):
    printer = Printer(pages_per_minute)
    print_queue = Queue()
    waiting_times = []

    for curr_sec in range(num_seconds):
        if is_create_new_print_task():
            task = RandomTask(curr_sec)
            print_queue.put(task)

        if (not printer.is_busy()) and (not print_queue.empty()):
            next_task = print_queue.get()
            waiting_times.append(next_task.get_wait_time(curr_sec))
            printer.start_next(next_task)
        printer.tick()
    avg_wait_time = sum(waiting_times) / len(waiting_times)
    return avg_wait_time, print_queue.size()
def simulation(numSeconds, pagesPerMinute):
    labprinter = Printer(pagesPerMinute)
    printQueue = Queue()
    waitingtimes = []

    for currentSecond in range(numSeconds):

        if newPrintTask():
            task = Task(currentSecond)
            printQueue.enqueue(task)

        if (not labprinter.busy()) and (not printQueue.empty()):
            nexttask = printQueue.dequeue()
            waitingtimes.append(nexttask.waitTime(currentSecond))
            labprinter.startNext(nexttask)

        labprinter.tick()

    averageWait = sum(waitingtimes) / len(waitingtimes)
    print("Average Wait %6.2f secs %3d tasks remaining." %
          (averageWait, printQueue.size()))
Пример #6
0
 def print_animation(self, names: list, num: int):
     circle_q = Queue()
     for name in names:
         circle_q.put(name)
     while True:
         # Stop the process when only one name remains
         if circle_q.size() == 1:
             break
         # When passing a potato, the simulation will simply dequeue and then immediately
         # enqueue the child, putting her at the end of the line
         for i in range(num):
             front_child = circle_q.get()
             circle_q.put(front_child)
             print("Time:", i)
             print(self.circle_q_to_str(names, front_child))
             time.sleep(1)
         # After passing potatoes `num` times, the child at the front will be removed permanently
         name = circle_q.get()
         names.remove(name)
         print('\n')
     print("The last man:", circle_q.get())
Пример #7
0
def get_last(names: list, num: int) -> str:
    """
    :param names: a list of names
    :param num: the time of each time's passing
    :return: the name of the last person remaining after repetitive counting by `num`
    """
    # Use a queue to simulate the circle
    # Child holding the potato will be at the front of the queue
    circle_q = Queue()
    for name in names:
        circle_q.put(name)
    while True:
        # Stop the process when only one name remains
        if circle_q.size() == 1:
            break
        # When passing a potato, the simulation will simply dequeue and then immediately
        # enqueue the child, putting her at the end of the line
        for _ in range(num):
            front_child = circle_q.get()
            circle_q.put(front_child)
        # After passing potatoes `num` times, the child at the front will be removed permanently
        circle_q.get()
    return circle_q.get()
Пример #8
0
 def test_size(self):
     q = Queue()
     self.assertEqual(0, q.size())
     q.put(1)
     self.assertEqual(1, q.size())