Пример #1
0
    def get_common_episode_title(self, num_episodes=100):

        if self.common_episode_title:
            return self.common_episode_title

        episodes = self.episode_set.all()[:num_episodes]

        # We take all non-empty titles
        titles = [_f for _f in (e.title for e in episodes) if _f]

        # there can not be a "common" title of a single title
        if len(titles) < 2:
            return None

        # get the longest common substring
        common_title = utils.longest_substr(titles)

        # but consider only the part up to the first number. Otherwise we risk
        # removing part of the number (eg if a feed contains episodes 100-199)
        common_title = re.search(r"^\D*", common_title).group(0)

        if len(common_title.strip()) < 2:
            return None

        return common_title
Пример #2
0
    def get_common_episode_title(self, num_episodes=100):

        if self.common_episode_title:
            return self.common_episode_title

        episodes = self.episode_set.all()[:num_episodes]

        # We take all non-empty titles
        titles = [_f for _f in (e.title for e in episodes) if _f]

        # there can not be a "common" title of a single title
        if len(titles) < 2:
            return None

        # get the longest common substring
        common_title = utils.longest_substr(titles)

        # but consider only the part up to the first number. Otherwise we risk
        # removing part of the number (eg if a feed contains episodes 100-199)
        common_title = re.search(r'^\D*', common_title).group(0)

        if len(common_title.strip()) < 2:
            return None

        return common_title
Пример #3
0
    def get_common_episode_title(self, num_episodes=100):

        if self.common_episode_title:
            return self.common_episode_title

        from mygpo.db.couchdb.episode import episodes_for_podcast
        episodes = episodes_for_podcast(self, descending=True, limit=num_episodes)

        # We take all non-empty titles
        titles = filter(None, (e.title for e in episodes))

        # there can not be a "common" title of a single title
        if len(titles) < 2:
            return None

        # get the longest common substring
        common_title = utils.longest_substr(titles)

        # but consider only the part up to the first number. Otherwise we risk
        # removing part of the number (eg if a feed contains episodes 100-199)
        common_title = re.search(r'^\D*', common_title).group(0)

        if len(common_title.strip()) < 2:
            return None

        return common_title
Пример #4
0
    def get_common_episode_title(self, num_episodes=100):

        if self.common_episode_title:
            return self.common_episode_title

        episodes = self.get_episodes(descending=True, limit=num_episodes)

        # We take all non-empty titles
        titles = filter(None, (e.title for e in episodes))
        # get the longest common substring
        common_title = utils.longest_substr(titles)

        # but consider only the part up to the first number. Otherwise we risk
        # removing part of the number (eg if a feed contains episodes 100-199)
        common_title = re.search(r'^\D*', common_title).group(0)

        if len(common_title.strip()) < 2:
            return None

        return common_title