def test_hash_equal_tuple_with_nans():
a = (float("nan"), (float("nan"), float("nan")))
b = (float("nan"), (float("nan"), float("nan")))
assert ht.object_hash(a) == ht.object_hash(b)
assert ht.objects_are_equal(a, b)
def __hash__(self) -> int:
# for python>=3.10, different nan objects have different hashes
# we need to avoid that und thus use hash function with old behavior
return object_hash(
tuple(getattr(self, attr) for attr in self._metadata))
