Пример #1
0
def _validate_move_ban_clear_analyzer(resource_element):
    resource_is_bundle = False
    resource_is_clone = False
    resource_is_in_clone = False
    resource_is_promotable_clone = False
    resource_is_in_promotable_clone = False
    promotable_clone_element = None

    if is_bundle(resource_element):
        resource_is_bundle = True
    elif is_any_clone(resource_element):
        resource_is_clone = True
        if is_master(resource_element) or is_promotable_clone(resource_element):
            resource_is_promotable_clone = True
            promotable_clone_element = resource_element
    elif get_parent_any_clone(resource_element) is not None:
        parent_clone = get_parent_any_clone(resource_element)
        resource_is_in_clone = True
        if is_master(parent_clone) or is_promotable_clone(parent_clone):
            resource_is_in_promotable_clone = True
            promotable_clone_element = parent_clone
    return _MoveBanClearAnalysis(
        resource_is_bundle,
        resource_is_clone,
        resource_is_in_clone,
        resource_is_promotable_clone,
        resource_is_in_promotable_clone,
        (
            promotable_clone_element.get("id")
            if promotable_clone_element is not None
            else None
        )
    )
Пример #2
0
def find_resources_to_delete(resource_el: _Element) -> List[_Element]:
    """
    Get resources to delete, children and parents of the given resource if
    necessary.

    If element is a primitive which is in a clone and you specify one of them,
    you will get elements for both of them. If you specify group element which
    is in a clone then will you get clone, group, and all primitive elements in
    a group and etc.

    resource_el - resource element (bundle, clone, group, primitive)
    """
    result = [resource_el]
    # childrens of bundle, clone, group, clone-with-group
    inner_resource_list = get_inner_resources(resource_el)
    if inner_resource_list:
        result.extend(inner_resource_list)
        inner_resource = inner_resource_list[0]
        if is_group(inner_resource):
            result.extend(get_inner_resources(inner_resource))
    # parents of primitive if needed (group, clone)
    parent_el = get_parent_resource(resource_el)
    if parent_el is None or is_bundle(parent_el):
        return result
    if is_any_clone(parent_el):
        result.insert(0, parent_el)
    if is_group(parent_el):
        group_inner_resources = get_group_inner_resources(parent_el)
        if len(group_inner_resources) <= 1:
            result = [parent_el] + group_inner_resources
            clone_el = get_parent_resource(parent_el)
            if clone_el is not None:
                result.insert(0, clone_el)
    return result
Пример #3
0
def find_resources_to_manage(resource_el):
    """
    Get resources to manage to manage the specified resource succesfully
    etree resource_el -- resource element
    """
    # If the resource_el is a primitive in a group, we set both the group and
    # the primitive to managed mode. Otherwise the resource_el, all its
    # children and parents need to be set to managed mode. We do it to make
    # sure to remove the unmanaged flag form the whole tree. The flag could be
    # put there manually. If we didn't do it, the resource may stay unmanaged,
    # as a managed primitive in an unmanaged clone / group is still unmanaged
    # and vice versa.
    # Bundle resources cannot be set as unmanaged - pcmk currently doesn't
    # support that. Resources in a bundle are supposed to be treated separately.
    if is_bundle(resource_el):
        return []
    res_id = resource_el.attrib["id"]
    return (
        [resource_el] # the resource itself
        +
        # its parents
        find_parent(resource_el, "resources").xpath(
            """
                (./master|./clone)[(group|group/primitive|primitive)[@id='{r}']]
                |
                //group[primitive[@id='{r}']]
            """
            .format(r=res_id)
        )
        +
        # its children
        resource_el.xpath("(./group|./primitive|./group/primitive)")
    )
Пример #4
0
def is_wrapper_resource(resource_el: Element) -> bool:
    """
    Return True for resource_el of types that can contain other resource(s)
    (these are: group, bundle, clone) and False otherwise.

    resource_el -- resource element to check
    """
    return (is_group(resource_el) or is_bundle(resource_el)
            or is_any_clone(resource_el))
Пример #5
0
def find_resources_to_enable(resource_el):
    """
    Get resources to enable in order to enable specified resource succesfully
    etree resource_el -- resource element
    """
    if is_bundle(resource_el):
        to_enable = [resource_el]
        in_bundle = get_bundle_inner_resource(resource_el)
        if in_bundle is not None:
            to_enable.append(in_bundle)
        return to_enable

    if is_any_clone(resource_el):
        return [resource_el, get_clone_inner_resource(resource_el)]

    to_enable = [resource_el]
    parent = resource_el.getparent()
    if is_any_clone(parent) or is_bundle(parent):
        to_enable.append(parent)
    return to_enable
Пример #6
0
def find_resources_to_unmanage(resource_el):
    """
    Get resources to unmanage to unmanage the specified resource succesfully
    etree resource_el -- resource element
    """
    # resource hierarchy - specified resource - what to return
    # a primitive - the primitive - the primitive
    #
    # a cloned primitive - the primitive - the primitive
    # a cloned primitive - the clone - the primitive
    #   The resource will run on all nodes after unclone. However that doesn't
    #   seem to be bad behavior. Moreover, if monitor operations were disabled,
    #   they wouldn't enable on unclone, but the resource would become managed,
    #   which is definitely bad.
    #
    # a primitive in a group - the primitive - the primitive
    #   Otherwise all primitives in the group would become unmanaged.
    # a primitive in a group - the group - all primitives in the group
    #   If only the group was set to unmanaged, setting any primitive in the
    #   group to managed would set all the primitives in the group to managed.
    #   If the group as well as all its primitives were set to unmanaged, any
    #   primitive added to the group would become unmanaged. This new primitive
    #   would become managed if any original group primitive becomes managed.
    #   Therefore changing one primitive influences another one, which we do
    #   not want to happen.
    #
    # a primitive in a cloned group - the primitive - the primitive
    # a primitive in a cloned group - the group - all primitives in the group
    #   See group notes above
    # a primitive in a cloned group - the clone - all primitives in the group
    #   See clone notes above
    #
    # a bundled primitive - the primitive - the primitive
    # a bundled primitive - the bundle - the bundle and the primitive
    #  We need to unmanage implicit resources create by pacemaker and there is
    #  no other way to do it than unmanage the bundle itself.
    #  Since it is not possible to unbundle a resource, the concers described
    #  at unclone don't apply here. However to prevent future bugs, in case
    #  unbundling becomes possible, we unmanage the primitive as well.
    # an empty bundle - the bundle - the bundle
    #  There is nothing else to unmanage.
    if is_bundle(resource_el):
        in_bundle = get_bundle_inner_resource(resource_el)
        return (
            [resource_el, in_bundle] if in_bundle is not None else [resource_el]
        )
    if is_any_clone(resource_el):
        resource_el = get_clone_inner_resource(resource_el)
    if is_group(resource_el):
        return get_group_inner_resources(resource_el)
    if is_primitive(resource_el):
        return [resource_el]
    return []
Пример #7
0
def find_primitives(resource_el):
    """
    Get list of primitives contained in a given resource
    etree resource_el -- resource element
    """
    if is_bundle(resource_el):
        in_bundle = get_bundle_inner_resource(resource_el)
        return [in_bundle] if in_bundle is not None else []
    if is_any_clone(resource_el):
        resource_el = get_clone_inner_resource(resource_el)
    if is_group(resource_el):
        return get_group_inner_resources(resource_el)
    if is_primitive(resource_el):
        return [resource_el]
    return []
Пример #8
0
def get_inner_resources(resource_el: _Element) -> List[_Element]:
    """
    Return list of inner resources (direct descendants) of a resource
    specified as resource_el.
    Example: for clone containing a group, this function will return only
    group and not resource inside the group

    resource_el -- resource element to get its inner resources
    """
    if is_bundle(resource_el):
        in_bundle = get_bundle_inner_resource(resource_el)
        return [in_bundle] if in_bundle is not None else []
    if is_any_clone(resource_el):
        return [get_clone_inner_resource(resource_el)]
    if is_group(resource_el):
        return get_group_inner_resources(resource_el)
    return []
Пример #9
0
def find_resources_to_enable(resource_el):
    """
    Get resources to enable in order to enable specified resource succesfully
    etree resource_el -- resource element
    """
    if is_bundle(resource_el):
        # bundles currently cannot be disabled - pcmk does not support that
        # inner resources are supposed to be managed separately
        return []

    if is_any_clone(resource_el):
        return [resource_el, get_clone_inner_resource(resource_el)]

    to_enable = [resource_el]
    parent = resource_el.getparent()
    if is_any_clone(parent):
        to_enable.append(parent)
    return to_enable
Пример #10
0
 def test_is_bundle(self):
     self.assertTrue(bundle.is_bundle(etree.fromstring("<bundle/>")))
     self.assertFalse(bundle.is_bundle(etree.fromstring("<clone/>")))
     self.assertFalse(bundle.is_bundle(etree.fromstring("<group/>")))
Пример #11
0
 def test_is_bundle(self):
     self.assertTrue(bundle.is_bundle(etree.fromstring("<bundle/>")))
     self.assertFalse(bundle.is_bundle(etree.fromstring("<clone/>")))
     self.assertFalse(bundle.is_bundle(etree.fromstring("<group/>")))