def test_union(self):
elements = ['A', 'C', 'D', 'F']
elements2 = ['A', 'B', 'D', 'F', 'G', 'H']
elements3 = ['C', 'Y', 'T', 'A']
set = HashSet(elements)
set2 = HashSet(elements2)
set3 = HashSet(elements3)
self.assertCountEqual(
set.union(set2).hash.values(),
['A', 'B', 'C', 'D', 'F', 'G', 'H']) # Ignore item order
self.assertCountEqual(
set.union(set3).hash.values(),
['A', 'C', 'D', 'F', 'T', 'Y']) # Ignore item order
def test_union(self):
elements = ['W', 'X', 'Y', 'Z']
elements2 = ['A', 'B', 'D', 'E', 'G', 'I']
elements3 = ['C', 'V', 'M', 'N']
set1 = HashSet(elements)
set2 = HashSet(elements2)
set3 = HashSet(elements3)
self.assertCountEqual(
set1.union(set2).hash.values(),
['A', 'B', 'D', 'E', 'G', 'I', 'W', 'X', 'Y', 'Z'
]) # Item order does not matter
self.assertCountEqual(
set1.union(set3).hash.values(),
['C', 'M', 'N', 'V', 'W', 'X', 'Y', 'Z'
]) # Item order does not matter
def test_union(self): set_one = HashSet(["A", "B", "C"]) set_two = HashSet(["C", "D", "E"]) set_three = set_one.union(set_two) assert set_three.size == 5
def test_union(self):
# two sets with one common element
set = HashSet(
['Talent code', 'Outliers', 'Talking to strangers', 'Idea man'])
other_set = HashSet(
['Beloved', 'Nightingale', 'Mistress of the game', 'Idea man'])
assert set.union(other_set).size == 7
# two sets with no common ele
set = HashSet(
['Talent code', 'Outliers', 'Talking to strangers', 'Capital'])
other_set = HashSet(
['Beloved', 'Nightingale', 'Mistress of the game', 'Idea man'])
assert set.union(other_set).size == 8
# two sets with the same element
set = HashSet(
['Talent code', 'Outliers', 'Talking to strangers', 'Capital'])
other_set = HashSet(
['Talent code', 'Outliers', 'Talking to strangers', 'Capital'])
assert set.union(other_set).size == 4
